Ternary operator function for JavaScript 'get middle letter' Code War challenge
Code challenge: write a function that gets the middle letter(s) of a string of even or odd numbered letters, as a ternary operator.
My function is working for odd numbers. But it does not work for even numbers - it seems to be skipping letters.
eg.
getMiddle("testing") // the output is "t", this is correct.
getMiddle("test") // the output is "et", it should be "es".
my code:
function getMiddle(str) {
return str.length % 2 === 0 ? str[str.length/2 - 1] + str[str.length/2 + 1] : str[Math.floor(str.length/2)];
}
javascript algorithm ternary
asked Nov 23 '18 at 14:58
Hm 13Hm 13
31
add a comment |
Code challenge: write a function that gets the middle letter(s) of a string of even or odd numbered letters, as a ternary operator.
My function is working for odd numbers. But it does not work for even numbers - it seems to be skipping letters.
eg.
getMiddle("testing") // the output is "t", this is correct.
getMiddle("test") // the output is "et", it should be "es".
my code:
function getMiddle(str) {
return str.length % 2 === 0 ? str[str.length/2 - 1] + str[str.length/2 + 1] : str[Math.floor(str.length/2)];
}
javascript algorithm ternary
asked Nov 23 '18 at 14:58
Hm 13Hm 13
31
1
When it's even, you get the letters at positions one before and one after half the length; you skip the letter at exactly half the length.
– Pointy
Nov 23 '18 at 15:00
1
The answer is very easy, I think you could see it if you try more
– Cristian Traìna
Nov 23 '18 at 15:02
add a comment |
Code challenge: write a function that gets the middle letter(s) of a string of even or odd numbered letters, as a ternary operator.
My function is working for odd numbers. But it does not work for even numbers - it seems to be skipping letters.
eg.
getMiddle("testing") // the output is "t", this is correct.
getMiddle("test") // the output is "et", it should be "es".
my code:
function getMiddle(str) {
return str.length % 2 === 0 ? str[str.length/2 - 1] + str[str.length/2 + 1] : str[Math.floor(str.length/2)];
}
javascript algorithm ternary
asked Nov 23 '18 at 14:58
Hm 13Hm 13
31
Code challenge: write a function that gets the middle letter(s) of a string of even or odd numbered letters, as a ternary operator.
My function is working for odd numbers. But it does not work for even numbers - it seems to be skipping letters.
eg.
getMiddle("testing") // the output is "t", this is correct.
getMiddle("test") // the output is "et", it should be "es".
my code:
function getMiddle(str) {
return str.length % 2 === 0 ? str[str.length/2 - 1] + str[str.length/2 + 1] : str[Math.floor(str.length/2)];
}
javascript algorithm ternary
javascript algorithm ternary
asked Nov 23 '18 at 14:58
Hm 13Hm 13
31
asked Nov 23 '18 at 14:58
Hm 13Hm 13
31
asked Nov 23 '18 at 14:58
Hm 13Hm 13
31
asked Nov 23 '18 at 14:58
Hm 13Hm 13
31
asked Nov 23 '18 at 14:58
Hm 13Hm 13
31
31
1
When it's even, you get the letters at positions one before and one after half the length; you skip the letter at exactly half the length.
– Pointy
Nov 23 '18 at 15:00
1
The answer is very easy, I think you could see it if you try more
– Cristian Traìna
Nov 23 '18 at 15:02
add a comment |
1
When it's even, you get the letters at positions one before and one after half the length; you skip the letter at exactly half the length.
– Pointy
Nov 23 '18 at 15:00
1
The answer is very easy, I think you could see it if you try more
– Cristian Traìna
Nov 23 '18 at 15:02
1
1
When it's even, you get the letters at positions one before and one after half the length; you skip the letter at exactly half the length.
– Pointy
Nov 23 '18 at 15:00
When it's even, you get the letters at positions one before and one after half the length; you skip the letter at exactly half the length.
– Pointy
Nov 23 '18 at 15:00
1
1
The answer is very easy, I think you could see it if you try more
– Cristian Traìna
Nov 23 '18 at 15:02
The answer is very easy, I think you could see it if you try more
– Cristian Traìna
Nov 23 '18 at 15:02
add a comment |
2 Answers
2
active
oldest
votes
When the length is is even, you want the 2 characters which are at the middle. You do that by taking the length of the string and divide it by 2.
That index in a zero based array will be the s.If you subtract 1 from the index, it will be the e. When you add +1, you get the t
In your code, you concatenate the index -1 and the index +1 leading to et
You should omit the + 1 in str[str.length/2 + 1] like:
function getMiddle(str) {
return str.length % 2 === 0 ? str[str.length / 2 - 1] + str[str.length / 2] : str[Math.floor(str.length / 2)];
}
function getMiddle(str) {
return str.length % 2 === 0 ? str[str.length / 2 - 1] + str[str.length / 2] : str[Math.floor(str.length / 2)];
}
console.log(getMiddle("testing"));
console.log(getMiddle("test"));
console.log(getMiddle("testtest"))answered Nov 23 '18 at 15:02
The fourth birdThe fourth bird
21.3k81326
add a comment |
I understand a use of ternary is required but you may simply do this without any such conditionals as well.
var getmid = (s, i=s.length/2) => s.slice(Math.ceil(i-1), Math.ceil(i+1)-(s.length & 1));
console.log(getmid("test")); // <- "es"
console.log(getmid("testo")); // <- "s"answered Nov 24 '18 at 16:01
ReduRedu
12.7k22435
add a comment |
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2 Answers
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active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
When the length is is even, you want the 2 characters which are at the middle. You do that by taking the length of the string and divide it by 2.
That index in a zero based array will be the s.If you subtract 1 from the index, it will be the e. When you add +1, you get the t
In your code, you concatenate the index -1 and the index +1 leading to et
You should omit the + 1 in str[str.length/2 + 1] like:
function getMiddle(str) {
return str.length % 2 === 0 ? str[str.length / 2 - 1] + str[str.length / 2] : str[Math.floor(str.length / 2)];
}
function getMiddle(str) {
return str.length % 2 === 0 ? str[str.length / 2 - 1] + str[str.length / 2] : str[Math.floor(str.length / 2)];
}
console.log(getMiddle("testing"));
console.log(getMiddle("test"));
console.log(getMiddle("testtest"))answered Nov 23 '18 at 15:02
The fourth birdThe fourth bird
21.3k81326
add a comment |
When the length is is even, you want the 2 characters which are at the middle. You do that by taking the length of the string and divide it by 2.
That index in a zero based array will be the s.If you subtract 1 from the index, it will be the e. When you add +1, you get the t
In your code, you concatenate the index -1 and the index +1 leading to et
You should omit the + 1 in str[str.length/2 + 1] like:
function getMiddle(str) {
return str.length % 2 === 0 ? str[str.length / 2 - 1] + str[str.length / 2] : str[Math.floor(str.length / 2)];
}
function getMiddle(str) {
return str.length % 2 === 0 ? str[str.length / 2 - 1] + str[str.length / 2] : str[Math.floor(str.length / 2)];
}
console.log(getMiddle("testing"));
console.log(getMiddle("test"));
console.log(getMiddle("testtest"))answered Nov 23 '18 at 15:02
The fourth birdThe fourth bird
21.3k81326
add a comment |
When the length is is even, you want the 2 characters which are at the middle. You do that by taking the length of the string and divide it by 2.
That index in a zero based array will be the s.If you subtract 1 from the index, it will be the e. When you add +1, you get the t
In your code, you concatenate the index -1 and the index +1 leading to et
You should omit the + 1 in str[str.length/2 + 1] like:
function getMiddle(str) {
return str.length % 2 === 0 ? str[str.length / 2 - 1] + str[str.length / 2] : str[Math.floor(str.length / 2)];
}
function getMiddle(str) {
return str.length % 2 === 0 ? str[str.length / 2 - 1] + str[str.length / 2] : str[Math.floor(str.length / 2)];
}
console.log(getMiddle("testing"));
console.log(getMiddle("test"));
console.log(getMiddle("testtest"))answered Nov 23 '18 at 15:02
The fourth birdThe fourth bird
21.3k81326
When the length is is even, you want the 2 characters which are at the middle. You do that by taking the length of the string and divide it by 2.
That index in a zero based array will be the s.If you subtract 1 from the index, it will be the e. When you add +1, you get the t
In your code, you concatenate the index -1 and the index +1 leading to et
You should omit the + 1 in str[str.length/2 + 1] like:
function getMiddle(str) {
return str.length % 2 === 0 ? str[str.length / 2 - 1] + str[str.length / 2] : str[Math.floor(str.length / 2)];
}
function getMiddle(str) {
return str.length % 2 === 0 ? str[str.length / 2 - 1] + str[str.length / 2] : str[Math.floor(str.length / 2)];
}
console.log(getMiddle("testing"));
console.log(getMiddle("test"));
console.log(getMiddle("testtest"))function getMiddle(str) {
return str.length % 2 === 0 ? str[str.length / 2 - 1] + str[str.length / 2] : str[Math.floor(str.length / 2)];
}
console.log(getMiddle("testing"));
console.log(getMiddle("test"));
console.log(getMiddle("testtest"))function getMiddle(str) {
return str.length % 2 === 0 ? str[str.length / 2 - 1] + str[str.length / 2] : str[Math.floor(str.length / 2)];
}
console.log(getMiddle("testing"));
console.log(getMiddle("test"));
console.log(getMiddle("testtest"))answered Nov 23 '18 at 15:02
The fourth birdThe fourth bird
21.3k81326
edited Nov 23 '18 at 15:19
answered Nov 23 '18 at 15:02
The fourth birdThe fourth bird
21.3k81326
answered Nov 23 '18 at 15:02
The fourth birdThe fourth bird
21.3k81326
answered Nov 23 '18 at 15:02
The fourth birdThe fourth bird
21.3k81326
21.3k81326
add a comment |
add a comment |
I understand a use of ternary is required but you may simply do this without any such conditionals as well.
var getmid = (s, i=s.length/2) => s.slice(Math.ceil(i-1), Math.ceil(i+1)-(s.length & 1));
console.log(getmid("test")); // <- "es"
console.log(getmid("testo")); // <- "s"answered Nov 24 '18 at 16:01
ReduRedu
12.7k22435
add a comment |
I understand a use of ternary is required but you may simply do this without any such conditionals as well.
var getmid = (s, i=s.length/2) => s.slice(Math.ceil(i-1), Math.ceil(i+1)-(s.length & 1));
console.log(getmid("test")); // <- "es"
console.log(getmid("testo")); // <- "s"answered Nov 24 '18 at 16:01
ReduRedu
12.7k22435
add a comment |
I understand a use of ternary is required but you may simply do this without any such conditionals as well.
var getmid = (s, i=s.length/2) => s.slice(Math.ceil(i-1), Math.ceil(i+1)-(s.length & 1));
console.log(getmid("test")); // <- "es"
console.log(getmid("testo")); // <- "s"answered Nov 24 '18 at 16:01
ReduRedu
12.7k22435
I understand a use of ternary is required but you may simply do this without any such conditionals as well.
var getmid = (s, i=s.length/2) => s.slice(Math.ceil(i-1), Math.ceil(i+1)-(s.length & 1));
console.log(getmid("test")); // <- "es"
console.log(getmid("testo")); // <- "s"var getmid = (s, i=s.length/2) => s.slice(Math.ceil(i-1), Math.ceil(i+1)-(s.length & 1));
console.log(getmid("test")); // <- "es"
console.log(getmid("testo")); // <- "s"var getmid = (s, i=s.length/2) => s.slice(Math.ceil(i-1), Math.ceil(i+1)-(s.length & 1));
console.log(getmid("test")); // <- "es"
console.log(getmid("testo")); // <- "s"answered Nov 24 '18 at 16:01
ReduRedu
12.7k22435
answered Nov 24 '18 at 16:01
ReduRedu
12.7k22435
answered Nov 24 '18 at 16:01
ReduRedu
12.7k22435
answered Nov 24 '18 at 16:01
ReduRedu
12.7k22435
12.7k22435
add a comment |
add a comment |
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1
When it's even, you get the letters at positions one before and one after half the length; you skip the letter at exactly half the length.
– Pointy
Nov 23 '18 at 15:00
1
The answer is very easy, I think you could see it if you try more
– Cristian Traìna
Nov 23 '18 at 15:02