Qt Serialization no match for operator << operand types are 'QDataStream'












0















I have a problem during serialization with a simple Managed Structure.



My Class Header



class MappySaver
{

public:
MappySaver();

//structure
struct Tile
{
public:
int ID;
int x,y,w,h;
QRect rect;
};

QList<Tile> Tiles;
QObject t;
Tile tile;

};

QDataStream& operator << (QDataStream& s, const MappySaver::Tile& tile);
QDataStream& operator >> (QDataStream& s, MappySaver::Tile& tile);


#endif // MAPPYSAVER_H


and source cpp



   QDataStream &operator<<(QDataStream &s, const MappySaver::Tile& tile)
{
s << tile;
return s;
}


When I try to compile this, I get this error:




error: no match for 'operator<<' (operand types are 'QDataStream' and 'const MappySaver::Tile')




template <typename T> //QDataStream.h
QDataStream& operator<<(QDataStream& s, const QList<T>& l)
{
s << quint32(l.size());
for (int i = 0; i < l.size(); ++i)
s << l.at(i);
return s;
}


I use this class to serialize a list.
On the main form, I have a widget with the same data.



And I use this method for try to serialize.



QString filename = QFileDialog::getSaveFileName(this,
tr("Seleziona il file da salvare"),"",
tr("File Mappa (*.mp2d)"));

MappySaver::Tile t;
MappySaver m;


for(int i = 0; i < ui->maps->Tiles.count(); i++)
{
t.ID = ui->maps->Tiles[i].ID;
t.h = ui->maps->Tiles[i].h;
t.rect = ui->maps->Tiles[i].rect;
t.w = ui->maps->Tiles[i].w;
t.x = ui->maps->Tiles[i].x;
t.y = ui->maps->Tiles[i].y;

m.Tiles.append(t);
}



QFile f(filename);

if(!f.open(QIODevice::WriteOnly))
{

}else
{
QDataStream out(&f);
out.setVersion(QDataStream::Qt_4_8);

out << m.Tiles;

}

f.flush();
f.close();


How can I fix this problem and serialize?










share|improve this question

























  • At first glance the compiler tells you what's wrong. You wrote functions for MappySaver but pass MappySaver::Tile as argument.

    – vahancho
    Nov 23 '18 at 10:59











  • just create the function QDataStream& operator << (QDataStream& s, const MappySever::Tile& tile);

    – Alexander Chernin
    Nov 23 '18 at 11:48













  • @AlexanderChernin i have an error Segmentation Fault.

    – giovanni mannuoio
    Nov 23 '18 at 14:09








  • 1





    Yep, you're getting recursion there. The function is calling itself. More appropriately, you might be wanting to output individual << tile.ID, tile.x, etc?

    – TrebuchetMS
    Nov 23 '18 at 14:43








  • 1





    @TrebuchetMS Yea! Work! Tanks a lot Trebuchet. i have changend whit your example and work! image.ibb.co/f0FB5V/Immagine.png

    – giovanni mannuoio
    Nov 23 '18 at 15:09


















0















I have a problem during serialization with a simple Managed Structure.



My Class Header



class MappySaver
{

public:
MappySaver();

//structure
struct Tile
{
public:
int ID;
int x,y,w,h;
QRect rect;
};

QList<Tile> Tiles;
QObject t;
Tile tile;

};

QDataStream& operator << (QDataStream& s, const MappySaver::Tile& tile);
QDataStream& operator >> (QDataStream& s, MappySaver::Tile& tile);


#endif // MAPPYSAVER_H


and source cpp



   QDataStream &operator<<(QDataStream &s, const MappySaver::Tile& tile)
{
s << tile;
return s;
}


When I try to compile this, I get this error:




error: no match for 'operator<<' (operand types are 'QDataStream' and 'const MappySaver::Tile')




template <typename T> //QDataStream.h
QDataStream& operator<<(QDataStream& s, const QList<T>& l)
{
s << quint32(l.size());
for (int i = 0; i < l.size(); ++i)
s << l.at(i);
return s;
}


I use this class to serialize a list.
On the main form, I have a widget with the same data.



And I use this method for try to serialize.



QString filename = QFileDialog::getSaveFileName(this,
tr("Seleziona il file da salvare"),"",
tr("File Mappa (*.mp2d)"));

MappySaver::Tile t;
MappySaver m;


for(int i = 0; i < ui->maps->Tiles.count(); i++)
{
t.ID = ui->maps->Tiles[i].ID;
t.h = ui->maps->Tiles[i].h;
t.rect = ui->maps->Tiles[i].rect;
t.w = ui->maps->Tiles[i].w;
t.x = ui->maps->Tiles[i].x;
t.y = ui->maps->Tiles[i].y;

m.Tiles.append(t);
}



QFile f(filename);

if(!f.open(QIODevice::WriteOnly))
{

}else
{
QDataStream out(&f);
out.setVersion(QDataStream::Qt_4_8);

out << m.Tiles;

}

f.flush();
f.close();


How can I fix this problem and serialize?










share|improve this question

























  • At first glance the compiler tells you what's wrong. You wrote functions for MappySaver but pass MappySaver::Tile as argument.

    – vahancho
    Nov 23 '18 at 10:59











  • just create the function QDataStream& operator << (QDataStream& s, const MappySever::Tile& tile);

    – Alexander Chernin
    Nov 23 '18 at 11:48













  • @AlexanderChernin i have an error Segmentation Fault.

    – giovanni mannuoio
    Nov 23 '18 at 14:09








  • 1





    Yep, you're getting recursion there. The function is calling itself. More appropriately, you might be wanting to output individual << tile.ID, tile.x, etc?

    – TrebuchetMS
    Nov 23 '18 at 14:43








  • 1





    @TrebuchetMS Yea! Work! Tanks a lot Trebuchet. i have changend whit your example and work! image.ibb.co/f0FB5V/Immagine.png

    – giovanni mannuoio
    Nov 23 '18 at 15:09
















0












0








0








I have a problem during serialization with a simple Managed Structure.



My Class Header



class MappySaver
{

public:
MappySaver();

//structure
struct Tile
{
public:
int ID;
int x,y,w,h;
QRect rect;
};

QList<Tile> Tiles;
QObject t;
Tile tile;

};

QDataStream& operator << (QDataStream& s, const MappySaver::Tile& tile);
QDataStream& operator >> (QDataStream& s, MappySaver::Tile& tile);


#endif // MAPPYSAVER_H


and source cpp



   QDataStream &operator<<(QDataStream &s, const MappySaver::Tile& tile)
{
s << tile;
return s;
}


When I try to compile this, I get this error:




error: no match for 'operator<<' (operand types are 'QDataStream' and 'const MappySaver::Tile')




template <typename T> //QDataStream.h
QDataStream& operator<<(QDataStream& s, const QList<T>& l)
{
s << quint32(l.size());
for (int i = 0; i < l.size(); ++i)
s << l.at(i);
return s;
}


I use this class to serialize a list.
On the main form, I have a widget with the same data.



And I use this method for try to serialize.



QString filename = QFileDialog::getSaveFileName(this,
tr("Seleziona il file da salvare"),"",
tr("File Mappa (*.mp2d)"));

MappySaver::Tile t;
MappySaver m;


for(int i = 0; i < ui->maps->Tiles.count(); i++)
{
t.ID = ui->maps->Tiles[i].ID;
t.h = ui->maps->Tiles[i].h;
t.rect = ui->maps->Tiles[i].rect;
t.w = ui->maps->Tiles[i].w;
t.x = ui->maps->Tiles[i].x;
t.y = ui->maps->Tiles[i].y;

m.Tiles.append(t);
}



QFile f(filename);

if(!f.open(QIODevice::WriteOnly))
{

}else
{
QDataStream out(&f);
out.setVersion(QDataStream::Qt_4_8);

out << m.Tiles;

}

f.flush();
f.close();


How can I fix this problem and serialize?










share|improve this question
















I have a problem during serialization with a simple Managed Structure.



My Class Header



class MappySaver
{

public:
MappySaver();

//structure
struct Tile
{
public:
int ID;
int x,y,w,h;
QRect rect;
};

QList<Tile> Tiles;
QObject t;
Tile tile;

};

QDataStream& operator << (QDataStream& s, const MappySaver::Tile& tile);
QDataStream& operator >> (QDataStream& s, MappySaver::Tile& tile);


#endif // MAPPYSAVER_H


and source cpp



   QDataStream &operator<<(QDataStream &s, const MappySaver::Tile& tile)
{
s << tile;
return s;
}


When I try to compile this, I get this error:




error: no match for 'operator<<' (operand types are 'QDataStream' and 'const MappySaver::Tile')




template <typename T> //QDataStream.h
QDataStream& operator<<(QDataStream& s, const QList<T>& l)
{
s << quint32(l.size());
for (int i = 0; i < l.size(); ++i)
s << l.at(i);
return s;
}


I use this class to serialize a list.
On the main form, I have a widget with the same data.



And I use this method for try to serialize.



QString filename = QFileDialog::getSaveFileName(this,
tr("Seleziona il file da salvare"),"",
tr("File Mappa (*.mp2d)"));

MappySaver::Tile t;
MappySaver m;


for(int i = 0; i < ui->maps->Tiles.count(); i++)
{
t.ID = ui->maps->Tiles[i].ID;
t.h = ui->maps->Tiles[i].h;
t.rect = ui->maps->Tiles[i].rect;
t.w = ui->maps->Tiles[i].w;
t.x = ui->maps->Tiles[i].x;
t.y = ui->maps->Tiles[i].y;

m.Tiles.append(t);
}



QFile f(filename);

if(!f.open(QIODevice::WriteOnly))
{

}else
{
QDataStream out(&f);
out.setVersion(QDataStream::Qt_4_8);

out << m.Tiles;

}

f.flush();
f.close();


How can I fix this problem and serialize?







c++ qt serialization qdatastream






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 23 '18 at 14:29







giovanni mannuoio

















asked Nov 23 '18 at 10:49









giovanni mannuoiogiovanni mannuoio

97




97













  • At first glance the compiler tells you what's wrong. You wrote functions for MappySaver but pass MappySaver::Tile as argument.

    – vahancho
    Nov 23 '18 at 10:59











  • just create the function QDataStream& operator << (QDataStream& s, const MappySever::Tile& tile);

    – Alexander Chernin
    Nov 23 '18 at 11:48













  • @AlexanderChernin i have an error Segmentation Fault.

    – giovanni mannuoio
    Nov 23 '18 at 14:09








  • 1





    Yep, you're getting recursion there. The function is calling itself. More appropriately, you might be wanting to output individual << tile.ID, tile.x, etc?

    – TrebuchetMS
    Nov 23 '18 at 14:43








  • 1





    @TrebuchetMS Yea! Work! Tanks a lot Trebuchet. i have changend whit your example and work! image.ibb.co/f0FB5V/Immagine.png

    – giovanni mannuoio
    Nov 23 '18 at 15:09





















  • At first glance the compiler tells you what's wrong. You wrote functions for MappySaver but pass MappySaver::Tile as argument.

    – vahancho
    Nov 23 '18 at 10:59











  • just create the function QDataStream& operator << (QDataStream& s, const MappySever::Tile& tile);

    – Alexander Chernin
    Nov 23 '18 at 11:48













  • @AlexanderChernin i have an error Segmentation Fault.

    – giovanni mannuoio
    Nov 23 '18 at 14:09








  • 1





    Yep, you're getting recursion there. The function is calling itself. More appropriately, you might be wanting to output individual << tile.ID, tile.x, etc?

    – TrebuchetMS
    Nov 23 '18 at 14:43








  • 1





    @TrebuchetMS Yea! Work! Tanks a lot Trebuchet. i have changend whit your example and work! image.ibb.co/f0FB5V/Immagine.png

    – giovanni mannuoio
    Nov 23 '18 at 15:09



















At first glance the compiler tells you what's wrong. You wrote functions for MappySaver but pass MappySaver::Tile as argument.

– vahancho
Nov 23 '18 at 10:59





At first glance the compiler tells you what's wrong. You wrote functions for MappySaver but pass MappySaver::Tile as argument.

– vahancho
Nov 23 '18 at 10:59













just create the function QDataStream& operator << (QDataStream& s, const MappySever::Tile& tile);

– Alexander Chernin
Nov 23 '18 at 11:48







just create the function QDataStream& operator << (QDataStream& s, const MappySever::Tile& tile);

– Alexander Chernin
Nov 23 '18 at 11:48















@AlexanderChernin i have an error Segmentation Fault.

– giovanni mannuoio
Nov 23 '18 at 14:09







@AlexanderChernin i have an error Segmentation Fault.

– giovanni mannuoio
Nov 23 '18 at 14:09






1




1





Yep, you're getting recursion there. The function is calling itself. More appropriately, you might be wanting to output individual << tile.ID, tile.x, etc?

– TrebuchetMS
Nov 23 '18 at 14:43







Yep, you're getting recursion there. The function is calling itself. More appropriately, you might be wanting to output individual << tile.ID, tile.x, etc?

– TrebuchetMS
Nov 23 '18 at 14:43






1




1





@TrebuchetMS Yea! Work! Tanks a lot Trebuchet. i have changend whit your example and work! image.ibb.co/f0FB5V/Immagine.png

– giovanni mannuoio
Nov 23 '18 at 15:09







@TrebuchetMS Yea! Work! Tanks a lot Trebuchet. i have changend whit your example and work! image.ibb.co/f0FB5V/Immagine.png

– giovanni mannuoio
Nov 23 '18 at 15:09














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