A problem about notation of expectation value











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When I looking expectation value in wikipedia



I find that it has several expression for expectation value



(1).$E[X]=int_Omega X(omega)dP(omega)$



(2).$E[X]=int_Bbb R xf(x)dx$



and a random variable is a function that transform a probability space to another space is built up on real number



i.e ($Omega,mathcal F,P)to(Bbb R,mathcal B,P_X$)



so,it seems (1) is a expression based on the probability space $(Omega,mathcal F,P)$



(2) is for probability space $ (Bbb R,mathcal B,P_X$)



and I know $f=frac{dP_X}{du} $ is a Radon–Nikodym derivative where $u$ is Lebesgue measure



Now I am trying to rewrite the expression from (2) to (1)



(3) $E[X]=int_Bbb R xf(x)dx=int_Bbb R xf(x)u(dx)=int_Bbb R xfdu=int_Bbb R xfrac{dP_X}{du}du=int_Bbb RxdP_x$



Is that (3) correct?



and how do I rewrite the right hand side of (3) to (1)?










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    up vote
    2
    down vote

    favorite
    2












    When I looking expectation value in wikipedia



    I find that it has several expression for expectation value



    (1).$E[X]=int_Omega X(omega)dP(omega)$



    (2).$E[X]=int_Bbb R xf(x)dx$



    and a random variable is a function that transform a probability space to another space is built up on real number



    i.e ($Omega,mathcal F,P)to(Bbb R,mathcal B,P_X$)



    so,it seems (1) is a expression based on the probability space $(Omega,mathcal F,P)$



    (2) is for probability space $ (Bbb R,mathcal B,P_X$)



    and I know $f=frac{dP_X}{du} $ is a Radon–Nikodym derivative where $u$ is Lebesgue measure



    Now I am trying to rewrite the expression from (2) to (1)



    (3) $E[X]=int_Bbb R xf(x)dx=int_Bbb R xf(x)u(dx)=int_Bbb R xfdu=int_Bbb R xfrac{dP_X}{du}du=int_Bbb RxdP_x$



    Is that (3) correct?



    and how do I rewrite the right hand side of (3) to (1)?










    share|cite|improve this question
























      up vote
      2
      down vote

      favorite
      2









      up vote
      2
      down vote

      favorite
      2






      2





      When I looking expectation value in wikipedia



      I find that it has several expression for expectation value



      (1).$E[X]=int_Omega X(omega)dP(omega)$



      (2).$E[X]=int_Bbb R xf(x)dx$



      and a random variable is a function that transform a probability space to another space is built up on real number



      i.e ($Omega,mathcal F,P)to(Bbb R,mathcal B,P_X$)



      so,it seems (1) is a expression based on the probability space $(Omega,mathcal F,P)$



      (2) is for probability space $ (Bbb R,mathcal B,P_X$)



      and I know $f=frac{dP_X}{du} $ is a Radon–Nikodym derivative where $u$ is Lebesgue measure



      Now I am trying to rewrite the expression from (2) to (1)



      (3) $E[X]=int_Bbb R xf(x)dx=int_Bbb R xf(x)u(dx)=int_Bbb R xfdu=int_Bbb R xfrac{dP_X}{du}du=int_Bbb RxdP_x$



      Is that (3) correct?



      and how do I rewrite the right hand side of (3) to (1)?










      share|cite|improve this question













      When I looking expectation value in wikipedia



      I find that it has several expression for expectation value



      (1).$E[X]=int_Omega X(omega)dP(omega)$



      (2).$E[X]=int_Bbb R xf(x)dx$



      and a random variable is a function that transform a probability space to another space is built up on real number



      i.e ($Omega,mathcal F,P)to(Bbb R,mathcal B,P_X$)



      so,it seems (1) is a expression based on the probability space $(Omega,mathcal F,P)$



      (2) is for probability space $ (Bbb R,mathcal B,P_X$)



      and I know $f=frac{dP_X}{du} $ is a Radon–Nikodym derivative where $u$ is Lebesgue measure



      Now I am trying to rewrite the expression from (2) to (1)



      (3) $E[X]=int_Bbb R xf(x)dx=int_Bbb R xf(x)u(dx)=int_Bbb R xfdu=int_Bbb R xfrac{dP_X}{du}du=int_Bbb RxdP_x$



      Is that (3) correct?



      and how do I rewrite the right hand side of (3) to (1)?







      probability-theory measure-theory






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      asked yesterday









      Vergil Chan

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          $P_X$ is defined by $P_X(B)=P(X^{-1}(B))$.Ffrom this we can show that $int xdP_X=int XdP$ (by simple function approximation). It should be noted that 1) is more general than 2) in the sense it does not require existence of $f$.






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            1 Answer
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            up vote
            2
            down vote













            $P_X$ is defined by $P_X(B)=P(X^{-1}(B))$.Ffrom this we can show that $int xdP_X=int XdP$ (by simple function approximation). It should be noted that 1) is more general than 2) in the sense it does not require existence of $f$.






            share|cite|improve this answer

























              up vote
              2
              down vote













              $P_X$ is defined by $P_X(B)=P(X^{-1}(B))$.Ffrom this we can show that $int xdP_X=int XdP$ (by simple function approximation). It should be noted that 1) is more general than 2) in the sense it does not require existence of $f$.






              share|cite|improve this answer























                up vote
                2
                down vote










                up vote
                2
                down vote









                $P_X$ is defined by $P_X(B)=P(X^{-1}(B))$.Ffrom this we can show that $int xdP_X=int XdP$ (by simple function approximation). It should be noted that 1) is more general than 2) in the sense it does not require existence of $f$.






                share|cite|improve this answer












                $P_X$ is defined by $P_X(B)=P(X^{-1}(B))$.Ffrom this we can show that $int xdP_X=int XdP$ (by simple function approximation). It should be noted that 1) is more general than 2) in the sense it does not require existence of $f$.







                share|cite|improve this answer












                share|cite|improve this answer



                share|cite|improve this answer










                answered yesterday









                Kavi Rama Murthy

                41.1k31751




                41.1k31751






























                     

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