Probability. Distribution function
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Distribution function is $$D(x)=sum_{k=1, kgeq x}^{infty} 2^{-k}$$.
We need to find $mathbb{P}_D({14}cup{15})$ and $mathbb{P}_D([0,5])$.
1) So I think $mathbb{P}_D({14}cup{15})= mathbb{P}_D({14})+ mathbb{P}_D({15})=D(14)+D(15)$ Is it right?
2) What about $mathbb{P}_D([0,5])$?
$mathbb{P}_D([0,5])=D(5)-D(0)$?
is $D(0) = 0$?
probability probability-theory probability-distributions
asked yesterday
Atstovas
334
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up vote
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Distribution function is $$D(x)=sum_{k=1, kgeq x}^{infty} 2^{-k}$$.
We need to find $mathbb{P}_D({14}cup{15})$ and $mathbb{P}_D([0,5])$.
1) So I think $mathbb{P}_D({14}cup{15})= mathbb{P}_D({14})+ mathbb{P}_D({15})=D(14)+D(15)$ Is it right?
2) What about $mathbb{P}_D([0,5])$?
$mathbb{P}_D([0,5])=D(5)-D(0)$?
is $D(0) = 0$?
probability probability-theory probability-distributions
asked yesterday
Atstovas
334
It is similar to 1, you need to add the probabilities of the values that the random variable can take on (the values that are in its range) that are also in [0,5]. Though the range isn't clear to me and neither is your subscript in the summation with this information.
– Steven Wagter
yesterday
Is that an increasing function of $x$?
– Henry
yesterday
From the sum it is not look like increasing function. This information is everything I have
– Atstovas
yesterday
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
Distribution function is $$D(x)=sum_{k=1, kgeq x}^{infty} 2^{-k}$$.
We need to find $mathbb{P}_D({14}cup{15})$ and $mathbb{P}_D([0,5])$.
1) So I think $mathbb{P}_D({14}cup{15})= mathbb{P}_D({14})+ mathbb{P}_D({15})=D(14)+D(15)$ Is it right?
2) What about $mathbb{P}_D([0,5])$?
$mathbb{P}_D([0,5])=D(5)-D(0)$?
is $D(0) = 0$?
probability probability-theory probability-distributions
asked yesterday
Atstovas
334
Distribution function is $$D(x)=sum_{k=1, kgeq x}^{infty} 2^{-k}$$.
We need to find $mathbb{P}_D({14}cup{15})$ and $mathbb{P}_D([0,5])$.
1) So I think $mathbb{P}_D({14}cup{15})= mathbb{P}_D({14})+ mathbb{P}_D({15})=D(14)+D(15)$ Is it right?
2) What about $mathbb{P}_D([0,5])$?
$mathbb{P}_D([0,5])=D(5)-D(0)$?
is $D(0) = 0$?
probability probability-theory probability-distributions
probability probability-theory probability-distributions
asked yesterday
Atstovas
334
asked yesterday
Atstovas
334
asked yesterday
Atstovas
334
asked yesterday
Atstovas
334
asked yesterday
Atstovas
334
334
It is similar to 1, you need to add the probabilities of the values that the random variable can take on (the values that are in its range) that are also in [0,5]. Though the range isn't clear to me and neither is your subscript in the summation with this information.
– Steven Wagter
yesterday
Is that an increasing function of $x$?
– Henry
yesterday
From the sum it is not look like increasing function. This information is everything I have
– Atstovas
yesterday
add a comment |
It is similar to 1, you need to add the probabilities of the values that the random variable can take on (the values that are in its range) that are also in [0,5]. Though the range isn't clear to me and neither is your subscript in the summation with this information.
– Steven Wagter
yesterday
Is that an increasing function of $x$?
– Henry
yesterday
From the sum it is not look like increasing function. This information is everything I have
– Atstovas
yesterday
It is similar to 1, you need to add the probabilities of the values that the random variable can take on (the values that are in its range) that are also in [0,5]. Though the range isn't clear to me and neither is your subscript in the summation with this information.
– Steven Wagter
yesterday
It is similar to 1, you need to add the probabilities of the values that the random variable can take on (the values that are in its range) that are also in [0,5]. Though the range isn't clear to me and neither is your subscript in the summation with this information.
– Steven Wagter
yesterday
Is that an increasing function of $x$?
– Henry
yesterday
Is that an increasing function of $x$?
– Henry
yesterday
From the sum it is not look like increasing function. This information is everything I have
– Atstovas
yesterday
From the sum it is not look like increasing function. This information is everything I have
– Atstovas
yesterday
add a comment |
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It is similar to 1, you need to add the probabilities of the values that the random variable can take on (the values that are in its range) that are also in [0,5]. Though the range isn't clear to me and neither is your subscript in the summation with this information.
– Steven Wagter
yesterday
Is that an increasing function of $x$?
– Henry
yesterday
From the sum it is not look like increasing function. This information is everything I have
– Atstovas
yesterday