Htykuut

I have a BitSet, which needs to be converted to a Byte. However, by using BitSet.toByteArray(), I don't get the correct output. I have tried converting the Byte to its binary form in order to check whether the Bitset and the binary form of the Byte are similiar.

public static void generate() {



        BitSet temp1 = new BitSet(64);



        for (int i = 0; i < 64; i++) {

            if(i % 8 != 0 && i < 23) {

            temp1.set(i, true);

            }

        }



        StringBuilder s = new StringBuilder();

        for (int i = 0; i < 64; i++) {

            s.append(temp1.get(i) == true ? 1 : 0);

        }



        System.out.println(s);



        byte tempByteKey1 = temp1.toByteArray();



        for (byte b : tempByteKey1) {

            System.out.print(Integer.toBinaryString(b & 255 | 256).substring(1));

        }



    }

Output:

Bitset: 0111111101111111011111100000000000000000000000000000000000000000

Converted Byte: 1111111011111110011111100000000000000000000000000000000000000000

They are both 64 bits, but the first 0 in the BitSet is placed somewhere else after the conversion. Why is this happening, and how can I fix it?