(Beginner question) How do I get a specific data from an OpenWeatherMap API











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I am currently working on a website for my school assignment (Final Thesis for VWO which is the last year of middle school in the Netherlands) where I have a sidebar which is supposed to give me the current temperature thanks to the API that I got from OpenWeatherMap.



But after searching for a few hours I still have no clue how I'm supposed to do it.



I have just "learned" html and css within the last few days, so my knowledge with them is still at the bare minimum, and as I've understood it correctly I need javascript for this problem which I still do not completely understand either.



I currently have this code in my .html which I want to show the current temperature taken from the OpenWeatherMap API instead of the 6 degrees:





<a href="#" style="float:right;">Outside Temp: 6&#8451</a>




(Reason it's a link with no destination is because that looked better in the "sidebar" with bootstrap)



But I have no idea how I can change the 6℃ to the 276.01 kelvin which is the number I got from my API JSON website:





{"coord":{"lon":5.39,"lat":51.5},"weather":[{"id":804,"main":"Clouds","description":"overcast clouds","icon":"04n"}],"base":"stations","main":{"temp":276.01,"pressure":1008,"humidity":69,"temp_min":275.15,"temp_max":277.15},"visibility":10000,"wind":{"speed":5.1,"deg":70},"clouds":{"all":90},"dt":1542749460,"sys":{"type":1,"id":5208,"message":0.0034,"country":"NL","sunrise":1542697565,"sunset":1542728514},"id":2759040,"name":"Best","cod":200}




So I've been browsing and searching around the web and in w3schools and tried to get the data from the API by using the following script according to w3schools:





function loadDoc() {
var openweathermapapi = new XMLHttpRequest();
openweathermapapi.onreadystatechange = function() {
if (this.readyState == 4 && this.status == 200) {
var temperature = JSON.parse(this.responseText);
document.getElementById("demo").innerHTML = this.responseText;
}
};


openweathermapapi.open("GET", "http://api.openweathermap.org/data/2.5/weather?q=Best&APPID=9c0299218db10c8423221d49842d8488", true);


openweathermapapi.send();
}




After pressing a button that runs the loadDoc script I get the complete website, but I only want the "temp" part from the "main" variable and have no idea how to get it.



Thank you



PS: I completely understand it if you don't want to answer this as I probably am doing something completely wrong or searching in the wrong things. I probably have no reason to get help as I simply haven't learned enough about programming yet, and I don't know if those kinds of questions are even allowed as I haven't found anything about it in the FAQ










share|improve this question







New contributor




Roy Zhou is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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  • Just add &units=imperial to the end of your API request URL.
    – Caleb H.
    2 days ago










  • 1) don't have your app ID visible in your question or someone will steal it, 2) to access parts of a JSON, use dot notation (w3schools.com/js/js_json_objects.asp) so it would be this.responseText.main.temp
    – ecg8
    2 days ago

















up vote
1
down vote

favorite












I am currently working on a website for my school assignment (Final Thesis for VWO which is the last year of middle school in the Netherlands) where I have a sidebar which is supposed to give me the current temperature thanks to the API that I got from OpenWeatherMap.



But after searching for a few hours I still have no clue how I'm supposed to do it.



I have just "learned" html and css within the last few days, so my knowledge with them is still at the bare minimum, and as I've understood it correctly I need javascript for this problem which I still do not completely understand either.



I currently have this code in my .html which I want to show the current temperature taken from the OpenWeatherMap API instead of the 6 degrees:





<a href="#" style="float:right;">Outside Temp: 6&#8451</a>




(Reason it's a link with no destination is because that looked better in the "sidebar" with bootstrap)



But I have no idea how I can change the 6℃ to the 276.01 kelvin which is the number I got from my API JSON website:





{"coord":{"lon":5.39,"lat":51.5},"weather":[{"id":804,"main":"Clouds","description":"overcast clouds","icon":"04n"}],"base":"stations","main":{"temp":276.01,"pressure":1008,"humidity":69,"temp_min":275.15,"temp_max":277.15},"visibility":10000,"wind":{"speed":5.1,"deg":70},"clouds":{"all":90},"dt":1542749460,"sys":{"type":1,"id":5208,"message":0.0034,"country":"NL","sunrise":1542697565,"sunset":1542728514},"id":2759040,"name":"Best","cod":200}




So I've been browsing and searching around the web and in w3schools and tried to get the data from the API by using the following script according to w3schools:





function loadDoc() {
var openweathermapapi = new XMLHttpRequest();
openweathermapapi.onreadystatechange = function() {
if (this.readyState == 4 && this.status == 200) {
var temperature = JSON.parse(this.responseText);
document.getElementById("demo").innerHTML = this.responseText;
}
};


openweathermapapi.open("GET", "http://api.openweathermap.org/data/2.5/weather?q=Best&APPID=9c0299218db10c8423221d49842d8488", true);


openweathermapapi.send();
}




After pressing a button that runs the loadDoc script I get the complete website, but I only want the "temp" part from the "main" variable and have no idea how to get it.



Thank you



PS: I completely understand it if you don't want to answer this as I probably am doing something completely wrong or searching in the wrong things. I probably have no reason to get help as I simply haven't learned enough about programming yet, and I don't know if those kinds of questions are even allowed as I haven't found anything about it in the FAQ










share|improve this question







New contributor




Roy Zhou is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.




















  • Just add &units=imperial to the end of your API request URL.
    – Caleb H.
    2 days ago










  • 1) don't have your app ID visible in your question or someone will steal it, 2) to access parts of a JSON, use dot notation (w3schools.com/js/js_json_objects.asp) so it would be this.responseText.main.temp
    – ecg8
    2 days ago















up vote
1
down vote

favorite









up vote
1
down vote

favorite











I am currently working on a website for my school assignment (Final Thesis for VWO which is the last year of middle school in the Netherlands) where I have a sidebar which is supposed to give me the current temperature thanks to the API that I got from OpenWeatherMap.



But after searching for a few hours I still have no clue how I'm supposed to do it.



I have just "learned" html and css within the last few days, so my knowledge with them is still at the bare minimum, and as I've understood it correctly I need javascript for this problem which I still do not completely understand either.



I currently have this code in my .html which I want to show the current temperature taken from the OpenWeatherMap API instead of the 6 degrees:





<a href="#" style="float:right;">Outside Temp: 6&#8451</a>




(Reason it's a link with no destination is because that looked better in the "sidebar" with bootstrap)



But I have no idea how I can change the 6℃ to the 276.01 kelvin which is the number I got from my API JSON website:





{"coord":{"lon":5.39,"lat":51.5},"weather":[{"id":804,"main":"Clouds","description":"overcast clouds","icon":"04n"}],"base":"stations","main":{"temp":276.01,"pressure":1008,"humidity":69,"temp_min":275.15,"temp_max":277.15},"visibility":10000,"wind":{"speed":5.1,"deg":70},"clouds":{"all":90},"dt":1542749460,"sys":{"type":1,"id":5208,"message":0.0034,"country":"NL","sunrise":1542697565,"sunset":1542728514},"id":2759040,"name":"Best","cod":200}




So I've been browsing and searching around the web and in w3schools and tried to get the data from the API by using the following script according to w3schools:





function loadDoc() {
var openweathermapapi = new XMLHttpRequest();
openweathermapapi.onreadystatechange = function() {
if (this.readyState == 4 && this.status == 200) {
var temperature = JSON.parse(this.responseText);
document.getElementById("demo").innerHTML = this.responseText;
}
};


openweathermapapi.open("GET", "http://api.openweathermap.org/data/2.5/weather?q=Best&APPID=9c0299218db10c8423221d49842d8488", true);


openweathermapapi.send();
}




After pressing a button that runs the loadDoc script I get the complete website, but I only want the "temp" part from the "main" variable and have no idea how to get it.



Thank you



PS: I completely understand it if you don't want to answer this as I probably am doing something completely wrong or searching in the wrong things. I probably have no reason to get help as I simply haven't learned enough about programming yet, and I don't know if those kinds of questions are even allowed as I haven't found anything about it in the FAQ










share|improve this question







New contributor




Roy Zhou is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











I am currently working on a website for my school assignment (Final Thesis for VWO which is the last year of middle school in the Netherlands) where I have a sidebar which is supposed to give me the current temperature thanks to the API that I got from OpenWeatherMap.



But after searching for a few hours I still have no clue how I'm supposed to do it.



I have just "learned" html and css within the last few days, so my knowledge with them is still at the bare minimum, and as I've understood it correctly I need javascript for this problem which I still do not completely understand either.



I currently have this code in my .html which I want to show the current temperature taken from the OpenWeatherMap API instead of the 6 degrees:





<a href="#" style="float:right;">Outside Temp: 6&#8451</a>




(Reason it's a link with no destination is because that looked better in the "sidebar" with bootstrap)



But I have no idea how I can change the 6℃ to the 276.01 kelvin which is the number I got from my API JSON website:





{"coord":{"lon":5.39,"lat":51.5},"weather":[{"id":804,"main":"Clouds","description":"overcast clouds","icon":"04n"}],"base":"stations","main":{"temp":276.01,"pressure":1008,"humidity":69,"temp_min":275.15,"temp_max":277.15},"visibility":10000,"wind":{"speed":5.1,"deg":70},"clouds":{"all":90},"dt":1542749460,"sys":{"type":1,"id":5208,"message":0.0034,"country":"NL","sunrise":1542697565,"sunset":1542728514},"id":2759040,"name":"Best","cod":200}




So I've been browsing and searching around the web and in w3schools and tried to get the data from the API by using the following script according to w3schools:





function loadDoc() {
var openweathermapapi = new XMLHttpRequest();
openweathermapapi.onreadystatechange = function() {
if (this.readyState == 4 && this.status == 200) {
var temperature = JSON.parse(this.responseText);
document.getElementById("demo").innerHTML = this.responseText;
}
};


openweathermapapi.open("GET", "http://api.openweathermap.org/data/2.5/weather?q=Best&APPID=9c0299218db10c8423221d49842d8488", true);


openweathermapapi.send();
}




After pressing a button that runs the loadDoc script I get the complete website, but I only want the "temp" part from the "main" variable and have no idea how to get it.



Thank you



PS: I completely understand it if you don't want to answer this as I probably am doing something completely wrong or searching in the wrong things. I probably have no reason to get help as I simply haven't learned enough about programming yet, and I don't know if those kinds of questions are even allowed as I haven't found anything about it in the FAQ







javascript html openweathermap






share|improve this question







New contributor




Roy Zhou is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











share|improve this question







New contributor




Roy Zhou is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









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Roy Zhou is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









asked 2 days ago









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New contributor




Roy Zhou is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.





New contributor





Roy Zhou is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






Roy Zhou is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.












  • Just add &units=imperial to the end of your API request URL.
    – Caleb H.
    2 days ago










  • 1) don't have your app ID visible in your question or someone will steal it, 2) to access parts of a JSON, use dot notation (w3schools.com/js/js_json_objects.asp) so it would be this.responseText.main.temp
    – ecg8
    2 days ago




















  • Just add &units=imperial to the end of your API request URL.
    – Caleb H.
    2 days ago










  • 1) don't have your app ID visible in your question or someone will steal it, 2) to access parts of a JSON, use dot notation (w3schools.com/js/js_json_objects.asp) so it would be this.responseText.main.temp
    – ecg8
    2 days ago


















Just add &units=imperial to the end of your API request URL.
– Caleb H.
2 days ago




Just add &units=imperial to the end of your API request URL.
– Caleb H.
2 days ago












1) don't have your app ID visible in your question or someone will steal it, 2) to access parts of a JSON, use dot notation (w3schools.com/js/js_json_objects.asp) so it would be this.responseText.main.temp
– ecg8
2 days ago






1) don't have your app ID visible in your question or someone will steal it, 2) to access parts of a JSON, use dot notation (w3schools.com/js/js_json_objects.asp) so it would be this.responseText.main.temp
– ecg8
2 days ago














1 Answer
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up vote
0
down vote













here's an example of getting current location's weather details



first get your current system's location using this



var getIP = 'http://ip-api.com/json/';


then, it returns you your location's details in json



THIS CODE GETS ENTIRE DATA ON LOCATION and sets it to your tag



var weatherjson = "";
var getIP = 'http://ip-api.com/json/';
var openWeatherMap = 'http://api.openweathermap.org/data/2.5/weather'
$.getJSON(getIP).done(function(location) {
$.getJSON(openWeatherMap, {
lat: location.lat,
lon: location.lon,
units: 'metric',
APPID: 'APIKEY'
}).done(function(weather) {

//set temperature from json to your <a> tag
$('#mytemp').text(weather.main.temp);
})
})


Explanation of above code:-



the sample json returned



{
"coord": {
"lon": -122.08,
"lat": 37.39
},
"weather": [
{
"id": 721,
"main": "Haze",
"description": "haze",
"icon": "50n"
},
{
"id": 711,
"main": "Smoke",
"description": "smoke",
"icon": "50n"
}
],
"base": "stations",
"main": {
"temp": 11.84,
"pressure": 1016,
"humidity": 81,
"temp_min": 10,
"temp_max": 13.3
},
"visibility": 11265,
"wind": {
"speed": 1.13,
"deg": 128.002
},
"clouds": {
"all": 90
},
"dt": 1542782400,
"sys": {
"type": 1,
"id": 471,
"message": 0.003,
"country": "US",
"sunrise": 1542812064,
"sunset": 1542848035
},
"id": 420006353,
"name": "Mountain View",
"cod": 200
}


The main column contains the degree of your own location named (TEMP)



"main": {
"temp": 11.84,
"pressure": 1016,
"humidity": 81,
"temp_min": 10,
"temp_max": 13.3
},


Now we need to show the TEMPERATURE on display level



<a href="#" id="mytemp" style="float:right;">Outside Temp: 6&#8451</a>


given an identity to your temperature containing anchor tag named ID which is "mytemp"



now find the ID and update the temperature



//set temperature from json to your <a> tag
$('#mytemp').text(weather.main.temp);





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    up vote
    0
    down vote













    here's an example of getting current location's weather details



    first get your current system's location using this



    var getIP = 'http://ip-api.com/json/';


    then, it returns you your location's details in json



    THIS CODE GETS ENTIRE DATA ON LOCATION and sets it to your tag



    var weatherjson = "";
    var getIP = 'http://ip-api.com/json/';
    var openWeatherMap = 'http://api.openweathermap.org/data/2.5/weather'
    $.getJSON(getIP).done(function(location) {
    $.getJSON(openWeatherMap, {
    lat: location.lat,
    lon: location.lon,
    units: 'metric',
    APPID: 'APIKEY'
    }).done(function(weather) {

    //set temperature from json to your <a> tag
    $('#mytemp').text(weather.main.temp);
    })
    })


    Explanation of above code:-



    the sample json returned



    {
    "coord": {
    "lon": -122.08,
    "lat": 37.39
    },
    "weather": [
    {
    "id": 721,
    "main": "Haze",
    "description": "haze",
    "icon": "50n"
    },
    {
    "id": 711,
    "main": "Smoke",
    "description": "smoke",
    "icon": "50n"
    }
    ],
    "base": "stations",
    "main": {
    "temp": 11.84,
    "pressure": 1016,
    "humidity": 81,
    "temp_min": 10,
    "temp_max": 13.3
    },
    "visibility": 11265,
    "wind": {
    "speed": 1.13,
    "deg": 128.002
    },
    "clouds": {
    "all": 90
    },
    "dt": 1542782400,
    "sys": {
    "type": 1,
    "id": 471,
    "message": 0.003,
    "country": "US",
    "sunrise": 1542812064,
    "sunset": 1542848035
    },
    "id": 420006353,
    "name": "Mountain View",
    "cod": 200
    }


    The main column contains the degree of your own location named (TEMP)



    "main": {
    "temp": 11.84,
    "pressure": 1016,
    "humidity": 81,
    "temp_min": 10,
    "temp_max": 13.3
    },


    Now we need to show the TEMPERATURE on display level



    <a href="#" id="mytemp" style="float:right;">Outside Temp: 6&#8451</a>


    given an identity to your temperature containing anchor tag named ID which is "mytemp"



    now find the ID and update the temperature



    //set temperature from json to your <a> tag
    $('#mytemp').text(weather.main.temp);





    share|improve this answer

























      up vote
      0
      down vote













      here's an example of getting current location's weather details



      first get your current system's location using this



      var getIP = 'http://ip-api.com/json/';


      then, it returns you your location's details in json



      THIS CODE GETS ENTIRE DATA ON LOCATION and sets it to your tag



      var weatherjson = "";
      var getIP = 'http://ip-api.com/json/';
      var openWeatherMap = 'http://api.openweathermap.org/data/2.5/weather'
      $.getJSON(getIP).done(function(location) {
      $.getJSON(openWeatherMap, {
      lat: location.lat,
      lon: location.lon,
      units: 'metric',
      APPID: 'APIKEY'
      }).done(function(weather) {

      //set temperature from json to your <a> tag
      $('#mytemp').text(weather.main.temp);
      })
      })


      Explanation of above code:-



      the sample json returned



      {
      "coord": {
      "lon": -122.08,
      "lat": 37.39
      },
      "weather": [
      {
      "id": 721,
      "main": "Haze",
      "description": "haze",
      "icon": "50n"
      },
      {
      "id": 711,
      "main": "Smoke",
      "description": "smoke",
      "icon": "50n"
      }
      ],
      "base": "stations",
      "main": {
      "temp": 11.84,
      "pressure": 1016,
      "humidity": 81,
      "temp_min": 10,
      "temp_max": 13.3
      },
      "visibility": 11265,
      "wind": {
      "speed": 1.13,
      "deg": 128.002
      },
      "clouds": {
      "all": 90
      },
      "dt": 1542782400,
      "sys": {
      "type": 1,
      "id": 471,
      "message": 0.003,
      "country": "US",
      "sunrise": 1542812064,
      "sunset": 1542848035
      },
      "id": 420006353,
      "name": "Mountain View",
      "cod": 200
      }


      The main column contains the degree of your own location named (TEMP)



      "main": {
      "temp": 11.84,
      "pressure": 1016,
      "humidity": 81,
      "temp_min": 10,
      "temp_max": 13.3
      },


      Now we need to show the TEMPERATURE on display level



      <a href="#" id="mytemp" style="float:right;">Outside Temp: 6&#8451</a>


      given an identity to your temperature containing anchor tag named ID which is "mytemp"



      now find the ID and update the temperature



      //set temperature from json to your <a> tag
      $('#mytemp').text(weather.main.temp);





      share|improve this answer























        up vote
        0
        down vote










        up vote
        0
        down vote









        here's an example of getting current location's weather details



        first get your current system's location using this



        var getIP = 'http://ip-api.com/json/';


        then, it returns you your location's details in json



        THIS CODE GETS ENTIRE DATA ON LOCATION and sets it to your tag



        var weatherjson = "";
        var getIP = 'http://ip-api.com/json/';
        var openWeatherMap = 'http://api.openweathermap.org/data/2.5/weather'
        $.getJSON(getIP).done(function(location) {
        $.getJSON(openWeatherMap, {
        lat: location.lat,
        lon: location.lon,
        units: 'metric',
        APPID: 'APIKEY'
        }).done(function(weather) {

        //set temperature from json to your <a> tag
        $('#mytemp').text(weather.main.temp);
        })
        })


        Explanation of above code:-



        the sample json returned



        {
        "coord": {
        "lon": -122.08,
        "lat": 37.39
        },
        "weather": [
        {
        "id": 721,
        "main": "Haze",
        "description": "haze",
        "icon": "50n"
        },
        {
        "id": 711,
        "main": "Smoke",
        "description": "smoke",
        "icon": "50n"
        }
        ],
        "base": "stations",
        "main": {
        "temp": 11.84,
        "pressure": 1016,
        "humidity": 81,
        "temp_min": 10,
        "temp_max": 13.3
        },
        "visibility": 11265,
        "wind": {
        "speed": 1.13,
        "deg": 128.002
        },
        "clouds": {
        "all": 90
        },
        "dt": 1542782400,
        "sys": {
        "type": 1,
        "id": 471,
        "message": 0.003,
        "country": "US",
        "sunrise": 1542812064,
        "sunset": 1542848035
        },
        "id": 420006353,
        "name": "Mountain View",
        "cod": 200
        }


        The main column contains the degree of your own location named (TEMP)



        "main": {
        "temp": 11.84,
        "pressure": 1016,
        "humidity": 81,
        "temp_min": 10,
        "temp_max": 13.3
        },


        Now we need to show the TEMPERATURE on display level



        <a href="#" id="mytemp" style="float:right;">Outside Temp: 6&#8451</a>


        given an identity to your temperature containing anchor tag named ID which is "mytemp"



        now find the ID and update the temperature



        //set temperature from json to your <a> tag
        $('#mytemp').text(weather.main.temp);





        share|improve this answer












        here's an example of getting current location's weather details



        first get your current system's location using this



        var getIP = 'http://ip-api.com/json/';


        then, it returns you your location's details in json



        THIS CODE GETS ENTIRE DATA ON LOCATION and sets it to your tag



        var weatherjson = "";
        var getIP = 'http://ip-api.com/json/';
        var openWeatherMap = 'http://api.openweathermap.org/data/2.5/weather'
        $.getJSON(getIP).done(function(location) {
        $.getJSON(openWeatherMap, {
        lat: location.lat,
        lon: location.lon,
        units: 'metric',
        APPID: 'APIKEY'
        }).done(function(weather) {

        //set temperature from json to your <a> tag
        $('#mytemp').text(weather.main.temp);
        })
        })


        Explanation of above code:-



        the sample json returned



        {
        "coord": {
        "lon": -122.08,
        "lat": 37.39
        },
        "weather": [
        {
        "id": 721,
        "main": "Haze",
        "description": "haze",
        "icon": "50n"
        },
        {
        "id": 711,
        "main": "Smoke",
        "description": "smoke",
        "icon": "50n"
        }
        ],
        "base": "stations",
        "main": {
        "temp": 11.84,
        "pressure": 1016,
        "humidity": 81,
        "temp_min": 10,
        "temp_max": 13.3
        },
        "visibility": 11265,
        "wind": {
        "speed": 1.13,
        "deg": 128.002
        },
        "clouds": {
        "all": 90
        },
        "dt": 1542782400,
        "sys": {
        "type": 1,
        "id": 471,
        "message": 0.003,
        "country": "US",
        "sunrise": 1542812064,
        "sunset": 1542848035
        },
        "id": 420006353,
        "name": "Mountain View",
        "cod": 200
        }


        The main column contains the degree of your own location named (TEMP)



        "main": {
        "temp": 11.84,
        "pressure": 1016,
        "humidity": 81,
        "temp_min": 10,
        "temp_max": 13.3
        },


        Now we need to show the TEMPERATURE on display level



        <a href="#" id="mytemp" style="float:right;">Outside Temp: 6&#8451</a>


        given an identity to your temperature containing anchor tag named ID which is "mytemp"



        now find the ID and update the temperature



        //set temperature from json to your <a> tag
        $('#mytemp').text(weather.main.temp);






        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered yesterday









        Yash Soni

        1167




        1167






















            Roy Zhou is a new contributor. Be nice, and check out our Code of Conduct.










             

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            Roy Zhou is a new contributor. Be nice, and check out our Code of Conduct.













            Roy Zhou is a new contributor. Be nice, and check out our Code of Conduct.












            Roy Zhou is a new contributor. Be nice, and check out our Code of Conduct.















             


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