How can I append an alement after another element?
up vote
-1
down vote
favorite
<div>
<label for="form_username" class="required">Username</label>
<input type="text" id="form_username" name="form[username]" required="required" class="form-control">
</div>
I try to append an element to the input field with the name "form[username]:
$( "<p>Test</p>" ).insertAfter('input[name=form[username]]');
But it is not working. Nothing happens.
I expect this result:
<div>
<label for="form_username" class="required">Username</label>
<input type="text" id="form_username" name="form[username]" required="required" class="form-control">
<p>Test</p>
</div>
jquery append insertafter
asked Nov 21 at 18:30
Jarla
2,18511638
add a comment |
up vote
-1
down vote
favorite
<div>
<label for="form_username" class="required">Username</label>
<input type="text" id="form_username" name="form[username]" required="required" class="form-control">
</div>
I try to append an element to the input field with the name "form[username]:
$( "<p>Test</p>" ).insertAfter('input[name=form[username]]');
But it is not working. Nothing happens.
I expect this result:
<div>
<label for="form_username" class="required">Username</label>
<input type="text" id="form_username" name="form[username]" required="required" class="form-control">
<p>Test</p>
</div>
jquery append insertafter
asked Nov 21 at 18:30
Jarla
2,18511638
add a comment |
up vote
-1
down vote
favorite
up vote
-1
down vote
favorite
<div>
<label for="form_username" class="required">Username</label>
<input type="text" id="form_username" name="form[username]" required="required" class="form-control">
</div>
I try to append an element to the input field with the name "form[username]:
$( "<p>Test</p>" ).insertAfter('input[name=form[username]]');
But it is not working. Nothing happens.
I expect this result:
<div>
<label for="form_username" class="required">Username</label>
<input type="text" id="form_username" name="form[username]" required="required" class="form-control">
<p>Test</p>
</div>
jquery append insertafter
asked Nov 21 at 18:30
Jarla
2,18511638
<div>
<label for="form_username" class="required">Username</label>
<input type="text" id="form_username" name="form[username]" required="required" class="form-control">
</div>
I try to append an element to the input field with the name "form[username]:
$( "<p>Test</p>" ).insertAfter('input[name=form[username]]');
But it is not working. Nothing happens.
I expect this result:
<div>
<label for="form_username" class="required">Username</label>
<input type="text" id="form_username" name="form[username]" required="required" class="form-control">
<p>Test</p>
</div>
jquery append insertafter
jquery append insertafter
asked Nov 21 at 18:30
Jarla
2,18511638
asked Nov 21 at 18:30
Jarla
2,18511638
asked Nov 21 at 18:30
Jarla
2,18511638
asked Nov 21 at 18:30
Jarla
2,18511638
asked Nov 21 at 18:30
Jarla
2,18511638
2,18511638
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
up vote
1
down vote
accepted
Since your input tag has an id form_username, you don't have to use [name] attribute as a selector anymore.
$( "<p>" ).text("Test").insertAfter('#form_username');<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div>
<label for="form_username" class="required">Username</label>
<input type="text" id="form_username" name="form[username]" required="required" class="form-control">
</div>Or if you have only 1 input tag, you could try:
$( "<p>" ).text("Test").insertAfter('input');<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div>
<label for="form_username" class="required">Username</label>
<input type="text" id="form_username" name="form[username]" required="required" class="form-control">
</div>Or if you want to use attribute name, you could rename the value form[username] to form_username, like this:
$( "<p>" ).text("Test").insertAfter('[name=form_username]');
$( "<p>" ).text("Test").insertAfter('input[name=form_username]');<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div>
<label for="form_username" class="required">Username</label>
<input type="text" id="form_username" name="form_username" required="required" class="form-control">
</div>If you don't want to rename the name attribute value, you could try:
$( "<p>" ).text("Test").insertAfter('input[name*="username"]');<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div>
<label for="form_username" class="required">Username</label>
<input type="text" id="form_username" name="form[username]" required="required" class="form-control">
</div>answered Nov 21 at 18:35
Foo
1
Thank you! What if I cannot rename it. Is it then not possible?
– Jarla
Nov 21 at 18:47
@Jarla I've updated new solution.
– Foo
Nov 21 at 18:52
1
This worked! Perfect. Thanks a lot!!
– Jarla
Nov 21 at 18:53
add a comment |
up vote
0
down vote
Alternatively, you could just use jQuery's .append() method to append your paragraph to your existing page elements.
$('#content_one').append('<p>Test 1</p>');
$('#content_two').append('<p>Test 2</p>');<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="content_one">
<label for="form_username" class="required">Username</label>
<input type="text" id="form_username" name="form[username]" required="required" class="form-control">
</div>
<div id="content_two">
<label for="form_password" class="required">Password</label>
<input type="text" id="form_password" name="form[password]" required="required" class="form-control">
</div>answered Nov 21 at 18:45
Peter
38513
I have more than one div so I need to append it to the specific with the name form[username]
– Jarla
Nov 21 at 18:52
That's not a problem. I will update my snippet.
– Peter
Nov 21 at 18:53
add a comment |
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
1
down vote
accepted
Since your input tag has an id form_username, you don't have to use [name] attribute as a selector anymore.
$( "<p>" ).text("Test").insertAfter('#form_username');<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div>
<label for="form_username" class="required">Username</label>
<input type="text" id="form_username" name="form[username]" required="required" class="form-control">
</div>Or if you have only 1 input tag, you could try:
$( "<p>" ).text("Test").insertAfter('input');<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div>
<label for="form_username" class="required">Username</label>
<input type="text" id="form_username" name="form[username]" required="required" class="form-control">
</div>Or if you want to use attribute name, you could rename the value form[username] to form_username, like this:
$( "<p>" ).text("Test").insertAfter('[name=form_username]');
$( "<p>" ).text("Test").insertAfter('input[name=form_username]');<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div>
<label for="form_username" class="required">Username</label>
<input type="text" id="form_username" name="form_username" required="required" class="form-control">
</div>If you don't want to rename the name attribute value, you could try:
$( "<p>" ).text("Test").insertAfter('input[name*="username"]');<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div>
<label for="form_username" class="required">Username</label>
<input type="text" id="form_username" name="form[username]" required="required" class="form-control">
</div>answered Nov 21 at 18:35
Foo
1
Thank you! What if I cannot rename it. Is it then not possible?
– Jarla
Nov 21 at 18:47
@Jarla I've updated new solution.
– Foo
Nov 21 at 18:52
1
This worked! Perfect. Thanks a lot!!
– Jarla
Nov 21 at 18:53
add a comment |
up vote
1
down vote
accepted
Since your input tag has an id form_username, you don't have to use [name] attribute as a selector anymore.
$( "<p>" ).text("Test").insertAfter('#form_username');<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div>
<label for="form_username" class="required">Username</label>
<input type="text" id="form_username" name="form[username]" required="required" class="form-control">
</div>Or if you have only 1 input tag, you could try:
$( "<p>" ).text("Test").insertAfter('input');<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div>
<label for="form_username" class="required">Username</label>
<input type="text" id="form_username" name="form[username]" required="required" class="form-control">
</div>Or if you want to use attribute name, you could rename the value form[username] to form_username, like this:
$( "<p>" ).text("Test").insertAfter('[name=form_username]');
$( "<p>" ).text("Test").insertAfter('input[name=form_username]');<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div>
<label for="form_username" class="required">Username</label>
<input type="text" id="form_username" name="form_username" required="required" class="form-control">
</div>If you don't want to rename the name attribute value, you could try:
$( "<p>" ).text("Test").insertAfter('input[name*="username"]');<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div>
<label for="form_username" class="required">Username</label>
<input type="text" id="form_username" name="form[username]" required="required" class="form-control">
</div>answered Nov 21 at 18:35
Foo
1
Thank you! What if I cannot rename it. Is it then not possible?
– Jarla
Nov 21 at 18:47
@Jarla I've updated new solution.
– Foo
Nov 21 at 18:52
1
This worked! Perfect. Thanks a lot!!
– Jarla
Nov 21 at 18:53
add a comment |
up vote
1
down vote
accepted
up vote
1
down vote
accepted
Since your input tag has an id form_username, you don't have to use [name] attribute as a selector anymore.
$( "<p>" ).text("Test").insertAfter('#form_username');<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div>
<label for="form_username" class="required">Username</label>
<input type="text" id="form_username" name="form[username]" required="required" class="form-control">
</div>Or if you have only 1 input tag, you could try:
$( "<p>" ).text("Test").insertAfter('input');<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div>
<label for="form_username" class="required">Username</label>
<input type="text" id="form_username" name="form[username]" required="required" class="form-control">
</div>Or if you want to use attribute name, you could rename the value form[username] to form_username, like this:
$( "<p>" ).text("Test").insertAfter('[name=form_username]');
$( "<p>" ).text("Test").insertAfter('input[name=form_username]');<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div>
<label for="form_username" class="required">Username</label>
<input type="text" id="form_username" name="form_username" required="required" class="form-control">
</div>If you don't want to rename the name attribute value, you could try:
$( "<p>" ).text("Test").insertAfter('input[name*="username"]');<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div>
<label for="form_username" class="required">Username</label>
<input type="text" id="form_username" name="form[username]" required="required" class="form-control">
</div>answered Nov 21 at 18:35
Foo
1
Since your input tag has an id form_username, you don't have to use [name] attribute as a selector anymore.
$( "<p>" ).text("Test").insertAfter('#form_username');<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div>
<label for="form_username" class="required">Username</label>
<input type="text" id="form_username" name="form[username]" required="required" class="form-control">
</div>Or if you have only 1 input tag, you could try:
$( "<p>" ).text("Test").insertAfter('input');<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div>
<label for="form_username" class="required">Username</label>
<input type="text" id="form_username" name="form[username]" required="required" class="form-control">
</div>Or if you want to use attribute name, you could rename the value form[username] to form_username, like this:
$( "<p>" ).text("Test").insertAfter('[name=form_username]');
$( "<p>" ).text("Test").insertAfter('input[name=form_username]');<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div>
<label for="form_username" class="required">Username</label>
<input type="text" id="form_username" name="form_username" required="required" class="form-control">
</div>If you don't want to rename the name attribute value, you could try:
$( "<p>" ).text("Test").insertAfter('input[name*="username"]');<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div>
<label for="form_username" class="required">Username</label>
<input type="text" id="form_username" name="form[username]" required="required" class="form-control">
</div>$( "<p>" ).text("Test").insertAfter('#form_username');<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div>
<label for="form_username" class="required">Username</label>
<input type="text" id="form_username" name="form[username]" required="required" class="form-control">
</div>$( "<p>" ).text("Test").insertAfter('#form_username');<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div>
<label for="form_username" class="required">Username</label>
<input type="text" id="form_username" name="form[username]" required="required" class="form-control">
</div>$( "<p>" ).text("Test").insertAfter('input');<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div>
<label for="form_username" class="required">Username</label>
<input type="text" id="form_username" name="form[username]" required="required" class="form-control">
</div>$( "<p>" ).text("Test").insertAfter('input');<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div>
<label for="form_username" class="required">Username</label>
<input type="text" id="form_username" name="form[username]" required="required" class="form-control">
</div>$( "<p>" ).text("Test").insertAfter('[name=form_username]');
$( "<p>" ).text("Test").insertAfter('input[name=form_username]');<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div>
<label for="form_username" class="required">Username</label>
<input type="text" id="form_username" name="form_username" required="required" class="form-control">
</div>$( "<p>" ).text("Test").insertAfter('[name=form_username]');
$( "<p>" ).text("Test").insertAfter('input[name=form_username]');<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div>
<label for="form_username" class="required">Username</label>
<input type="text" id="form_username" name="form_username" required="required" class="form-control">
</div>$( "<p>" ).text("Test").insertAfter('input[name*="username"]');<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div>
<label for="form_username" class="required">Username</label>
<input type="text" id="form_username" name="form[username]" required="required" class="form-control">
</div>$( "<p>" ).text("Test").insertAfter('input[name*="username"]');<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div>
<label for="form_username" class="required">Username</label>
<input type="text" id="form_username" name="form[username]" required="required" class="form-control">
</div>answered Nov 21 at 18:35
Foo
1
edited Nov 21 at 18:51
answered Nov 21 at 18:35
Foo
1
answered Nov 21 at 18:35
Foo
1
answered Nov 21 at 18:35
Foo
1
1
Thank you! What if I cannot rename it. Is it then not possible?
– Jarla
Nov 21 at 18:47
@Jarla I've updated new solution.
– Foo
Nov 21 at 18:52
1
This worked! Perfect. Thanks a lot!!
– Jarla
Nov 21 at 18:53
add a comment |
Thank you! What if I cannot rename it. Is it then not possible?
– Jarla
Nov 21 at 18:47
@Jarla I've updated new solution.
– Foo
Nov 21 at 18:52
1
This worked! Perfect. Thanks a lot!!
– Jarla
Nov 21 at 18:53
Thank you! What if I cannot rename it. Is it then not possible?
– Jarla
Nov 21 at 18:47
Thank you! What if I cannot rename it. Is it then not possible?
– Jarla
Nov 21 at 18:47
@Jarla I've updated new solution.
– Foo
Nov 21 at 18:52
@Jarla I've updated new solution.
– Foo
Nov 21 at 18:52
1
1
This worked! Perfect. Thanks a lot!!
– Jarla
Nov 21 at 18:53
This worked! Perfect. Thanks a lot!!
– Jarla
Nov 21 at 18:53
add a comment |
up vote
0
down vote
Alternatively, you could just use jQuery's .append() method to append your paragraph to your existing page elements.
$('#content_one').append('<p>Test 1</p>');
$('#content_two').append('<p>Test 2</p>');<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="content_one">
<label for="form_username" class="required">Username</label>
<input type="text" id="form_username" name="form[username]" required="required" class="form-control">
</div>
<div id="content_two">
<label for="form_password" class="required">Password</label>
<input type="text" id="form_password" name="form[password]" required="required" class="form-control">
</div>answered Nov 21 at 18:45
Peter
38513
I have more than one div so I need to append it to the specific with the name form[username]
– Jarla
Nov 21 at 18:52
That's not a problem. I will update my snippet.
– Peter
Nov 21 at 18:53
add a comment |
up vote
0
down vote
Alternatively, you could just use jQuery's .append() method to append your paragraph to your existing page elements.
$('#content_one').append('<p>Test 1</p>');
$('#content_two').append('<p>Test 2</p>');<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="content_one">
<label for="form_username" class="required">Username</label>
<input type="text" id="form_username" name="form[username]" required="required" class="form-control">
</div>
<div id="content_two">
<label for="form_password" class="required">Password</label>
<input type="text" id="form_password" name="form[password]" required="required" class="form-control">
</div>answered Nov 21 at 18:45
Peter
38513
I have more than one div so I need to append it to the specific with the name form[username]
– Jarla
Nov 21 at 18:52
That's not a problem. I will update my snippet.
– Peter
Nov 21 at 18:53
add a comment |
up vote
0
down vote
up vote
0
down vote
Alternatively, you could just use jQuery's .append() method to append your paragraph to your existing page elements.
$('#content_one').append('<p>Test 1</p>');
$('#content_two').append('<p>Test 2</p>');<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="content_one">
<label for="form_username" class="required">Username</label>
<input type="text" id="form_username" name="form[username]" required="required" class="form-control">
</div>
<div id="content_two">
<label for="form_password" class="required">Password</label>
<input type="text" id="form_password" name="form[password]" required="required" class="form-control">
</div>answered Nov 21 at 18:45
Peter
38513
Alternatively, you could just use jQuery's .append() method to append your paragraph to your existing page elements.
$('#content_one').append('<p>Test 1</p>');
$('#content_two').append('<p>Test 2</p>');<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="content_one">
<label for="form_username" class="required">Username</label>
<input type="text" id="form_username" name="form[username]" required="required" class="form-control">
</div>
<div id="content_two">
<label for="form_password" class="required">Password</label>
<input type="text" id="form_password" name="form[password]" required="required" class="form-control">
</div>$('#content_one').append('<p>Test 1</p>');
$('#content_two').append('<p>Test 2</p>');<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="content_one">
<label for="form_username" class="required">Username</label>
<input type="text" id="form_username" name="form[username]" required="required" class="form-control">
</div>
<div id="content_two">
<label for="form_password" class="required">Password</label>
<input type="text" id="form_password" name="form[password]" required="required" class="form-control">
</div>$('#content_one').append('<p>Test 1</p>');
$('#content_two').append('<p>Test 2</p>');<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="content_one">
<label for="form_username" class="required">Username</label>
<input type="text" id="form_username" name="form[username]" required="required" class="form-control">
</div>
<div id="content_two">
<label for="form_password" class="required">Password</label>
<input type="text" id="form_password" name="form[password]" required="required" class="form-control">
</div>answered Nov 21 at 18:45
Peter
38513
edited Nov 21 at 18:55
answered Nov 21 at 18:45
Peter
38513
answered Nov 21 at 18:45
Peter
38513
answered Nov 21 at 18:45
Peter
38513
38513
I have more than one div so I need to append it to the specific with the name form[username]
– Jarla
Nov 21 at 18:52
That's not a problem. I will update my snippet.
– Peter
Nov 21 at 18:53
add a comment |
I have more than one div so I need to append it to the specific with the name form[username]
– Jarla
Nov 21 at 18:52
That's not a problem. I will update my snippet.
– Peter
Nov 21 at 18:53
I have more than one div so I need to append it to the specific with the name form[username]
– Jarla
Nov 21 at 18:52
I have more than one div so I need to append it to the specific with the name form[username]
– Jarla
Nov 21 at 18:52
That's not a problem. I will update my snippet.
– Peter
Nov 21 at 18:53
That's not a problem. I will update my snippet.
– Peter
Nov 21 at 18:53
add a comment |
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Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
