How to convert data into JSON dictionary?
So I get a response and print it. The result is bytes:
payload = request.body
print (payload)
b'a=123&b=345&c=678&d=910'
I decode it, and the result is:
dataform = payload.decode('utf-8').replace("'", '"')
print(dataform, 'dataform')
a=123&b=345&c=678&d=910
I dumps it, and the result is:
result = json.dumps(dataform, indent=4, sort_keys=True)
print(result, 'result')
"a=123&b=345&c=678&d=910"
I loads it, and the result is:
jason = json.loads(result)
print(jason, 'jason')
a=123&b=345&c=678&d=910
I just want a normal json dictionary that I can refer to like data['string']. What am I doing wrong or not doing?
python json
add a comment |
So I get a response and print it. The result is bytes:
payload = request.body
print (payload)
b'a=123&b=345&c=678&d=910'
I decode it, and the result is:
dataform = payload.decode('utf-8').replace("'", '"')
print(dataform, 'dataform')
a=123&b=345&c=678&d=910
I dumps it, and the result is:
result = json.dumps(dataform, indent=4, sort_keys=True)
print(result, 'result')
"a=123&b=345&c=678&d=910"
I loads it, and the result is:
jason = json.loads(result)
print(jason, 'jason')
a=123&b=345&c=678&d=910
I just want a normal json dictionary that I can refer to like data['string']. What am I doing wrong or not doing?
python json
1
The string doesn't contain any single quotes, so replacing them is superfluous (and if it wasn't, it'd be wrong). Other than that, are you looking ford = dict(x.split('=', 1) for x in payload.decode('utf-8').split('&'))
perhaps?
– tripleee
Nov 23 '18 at 9:18
add a comment |
So I get a response and print it. The result is bytes:
payload = request.body
print (payload)
b'a=123&b=345&c=678&d=910'
I decode it, and the result is:
dataform = payload.decode('utf-8').replace("'", '"')
print(dataform, 'dataform')
a=123&b=345&c=678&d=910
I dumps it, and the result is:
result = json.dumps(dataform, indent=4, sort_keys=True)
print(result, 'result')
"a=123&b=345&c=678&d=910"
I loads it, and the result is:
jason = json.loads(result)
print(jason, 'jason')
a=123&b=345&c=678&d=910
I just want a normal json dictionary that I can refer to like data['string']. What am I doing wrong or not doing?
python json
So I get a response and print it. The result is bytes:
payload = request.body
print (payload)
b'a=123&b=345&c=678&d=910'
I decode it, and the result is:
dataform = payload.decode('utf-8').replace("'", '"')
print(dataform, 'dataform')
a=123&b=345&c=678&d=910
I dumps it, and the result is:
result = json.dumps(dataform, indent=4, sort_keys=True)
print(result, 'result')
"a=123&b=345&c=678&d=910"
I loads it, and the result is:
jason = json.loads(result)
print(jason, 'jason')
a=123&b=345&c=678&d=910
I just want a normal json dictionary that I can refer to like data['string']. What am I doing wrong or not doing?
python json
python json
edited Nov 23 '18 at 9:10
Whodini
asked Nov 23 '18 at 9:03
WhodiniWhodini
50913
50913
1
The string doesn't contain any single quotes, so replacing them is superfluous (and if it wasn't, it'd be wrong). Other than that, are you looking ford = dict(x.split('=', 1) for x in payload.decode('utf-8').split('&'))
perhaps?
– tripleee
Nov 23 '18 at 9:18
add a comment |
1
The string doesn't contain any single quotes, so replacing them is superfluous (and if it wasn't, it'd be wrong). Other than that, are you looking ford = dict(x.split('=', 1) for x in payload.decode('utf-8').split('&'))
perhaps?
– tripleee
Nov 23 '18 at 9:18
1
1
The string doesn't contain any single quotes, so replacing them is superfluous (and if it wasn't, it'd be wrong). Other than that, are you looking for
d = dict(x.split('=', 1) for x in payload.decode('utf-8').split('&'))
perhaps?– tripleee
Nov 23 '18 at 9:18
The string doesn't contain any single quotes, so replacing them is superfluous (and if it wasn't, it'd be wrong). Other than that, are you looking for
d = dict(x.split('=', 1) for x in payload.decode('utf-8').split('&'))
perhaps?– tripleee
Nov 23 '18 at 9:18
add a comment |
3 Answers
3
active
oldest
votes
There's a few errors here.
First off, dumping to JSON and then loading it again does absolutely nothing (it does have a few side-effects, but that's not important here).
Secondly, and mainly, your input data isn't JSON - it's either a query string or, more likely, form-data.
You can try to parse it using the standard parse_qs
in urllib.parse
, but if that fails you'll have to look around for a library that can handle proper form data.
In [1]: from urllib.parse import parse_qs
In [2]: payload = b'a=123&b=345&c=678&d=910'
In [3]: dataform = payload.decode('utf-8').replace("'", '"')
In [4]: result = parse_qs(dataform)
In [5]: print(result)
{'a': ['123'], 'b': ['345'], 'c': ['678'], 'd': ['910']}
1
The.replace()
part is superfluous. Also in python2, you should dofrom urlparse import parse_qs
.
– SMir
Nov 23 '18 at 9:23
the parse_qs is what I needed. Thanks. I did not know of that.
– Whodini
Nov 23 '18 at 9:32
add a comment |
At first, you need to convert the string (here, as the example, to the array, but you can use that you want)
data = [x.split('=') for x in data.split('&')]
>>> data
[['a', '123'], ['b', '345'], ['c', '678'], ['d', '910']]
And after this, you can easily create the dictionary.
dict = {key: value for (key,value) in data}
>>> dict
{'a': '123', 'c': '678', 'b': '345', 'd': '910'}
Or if you want to store numbers as int:
dict = {key: int(value) for (key,value) in data}
>>> dict
{'a': 123, 'c': 678, 'b': 345, 'd': 910}
add a comment |
import json
from urllib.parse import parse_qs
payload = request.body
# b'a=123&b=345&c=678&d=910'
qs = parse_qs(payload.decode())
# {'a': ['123'], 'b': ['345'], 'c': ['678'], 'd': ['910']}
Convert list values and convert data into JSON
json.dumps({k: v[0] for k, v in qs.items()})
# '{"a": "123", "b": "345", "c": "678", "d": "910"}'
2
An explanation, what the posted code does and how this addresses the problem in the question, rarely fails to improve an answer.
– blue-phoenox
Nov 23 '18 at 9:35
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53443490%2fhow-to-convert-data-into-json-dictionary%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
There's a few errors here.
First off, dumping to JSON and then loading it again does absolutely nothing (it does have a few side-effects, but that's not important here).
Secondly, and mainly, your input data isn't JSON - it's either a query string or, more likely, form-data.
You can try to parse it using the standard parse_qs
in urllib.parse
, but if that fails you'll have to look around for a library that can handle proper form data.
In [1]: from urllib.parse import parse_qs
In [2]: payload = b'a=123&b=345&c=678&d=910'
In [3]: dataform = payload.decode('utf-8').replace("'", '"')
In [4]: result = parse_qs(dataform)
In [5]: print(result)
{'a': ['123'], 'b': ['345'], 'c': ['678'], 'd': ['910']}
1
The.replace()
part is superfluous. Also in python2, you should dofrom urlparse import parse_qs
.
– SMir
Nov 23 '18 at 9:23
the parse_qs is what I needed. Thanks. I did not know of that.
– Whodini
Nov 23 '18 at 9:32
add a comment |
There's a few errors here.
First off, dumping to JSON and then loading it again does absolutely nothing (it does have a few side-effects, but that's not important here).
Secondly, and mainly, your input data isn't JSON - it's either a query string or, more likely, form-data.
You can try to parse it using the standard parse_qs
in urllib.parse
, but if that fails you'll have to look around for a library that can handle proper form data.
In [1]: from urllib.parse import parse_qs
In [2]: payload = b'a=123&b=345&c=678&d=910'
In [3]: dataform = payload.decode('utf-8').replace("'", '"')
In [4]: result = parse_qs(dataform)
In [5]: print(result)
{'a': ['123'], 'b': ['345'], 'c': ['678'], 'd': ['910']}
1
The.replace()
part is superfluous. Also in python2, you should dofrom urlparse import parse_qs
.
– SMir
Nov 23 '18 at 9:23
the parse_qs is what I needed. Thanks. I did not know of that.
– Whodini
Nov 23 '18 at 9:32
add a comment |
There's a few errors here.
First off, dumping to JSON and then loading it again does absolutely nothing (it does have a few side-effects, but that's not important here).
Secondly, and mainly, your input data isn't JSON - it's either a query string or, more likely, form-data.
You can try to parse it using the standard parse_qs
in urllib.parse
, but if that fails you'll have to look around for a library that can handle proper form data.
In [1]: from urllib.parse import parse_qs
In [2]: payload = b'a=123&b=345&c=678&d=910'
In [3]: dataform = payload.decode('utf-8').replace("'", '"')
In [4]: result = parse_qs(dataform)
In [5]: print(result)
{'a': ['123'], 'b': ['345'], 'c': ['678'], 'd': ['910']}
There's a few errors here.
First off, dumping to JSON and then loading it again does absolutely nothing (it does have a few side-effects, but that's not important here).
Secondly, and mainly, your input data isn't JSON - it's either a query string or, more likely, form-data.
You can try to parse it using the standard parse_qs
in urllib.parse
, but if that fails you'll have to look around for a library that can handle proper form data.
In [1]: from urllib.parse import parse_qs
In [2]: payload = b'a=123&b=345&c=678&d=910'
In [3]: dataform = payload.decode('utf-8').replace("'", '"')
In [4]: result = parse_qs(dataform)
In [5]: print(result)
{'a': ['123'], 'b': ['345'], 'c': ['678'], 'd': ['910']}
answered Nov 23 '18 at 9:19
RanizRaniz
8,27312155
8,27312155
1
The.replace()
part is superfluous. Also in python2, you should dofrom urlparse import parse_qs
.
– SMir
Nov 23 '18 at 9:23
the parse_qs is what I needed. Thanks. I did not know of that.
– Whodini
Nov 23 '18 at 9:32
add a comment |
1
The.replace()
part is superfluous. Also in python2, you should dofrom urlparse import parse_qs
.
– SMir
Nov 23 '18 at 9:23
the parse_qs is what I needed. Thanks. I did not know of that.
– Whodini
Nov 23 '18 at 9:32
1
1
The
.replace()
part is superfluous. Also in python2, you should do from urlparse import parse_qs
.– SMir
Nov 23 '18 at 9:23
The
.replace()
part is superfluous. Also in python2, you should do from urlparse import parse_qs
.– SMir
Nov 23 '18 at 9:23
the parse_qs is what I needed. Thanks. I did not know of that.
– Whodini
Nov 23 '18 at 9:32
the parse_qs is what I needed. Thanks. I did not know of that.
– Whodini
Nov 23 '18 at 9:32
add a comment |
At first, you need to convert the string (here, as the example, to the array, but you can use that you want)
data = [x.split('=') for x in data.split('&')]
>>> data
[['a', '123'], ['b', '345'], ['c', '678'], ['d', '910']]
And after this, you can easily create the dictionary.
dict = {key: value for (key,value) in data}
>>> dict
{'a': '123', 'c': '678', 'b': '345', 'd': '910'}
Or if you want to store numbers as int:
dict = {key: int(value) for (key,value) in data}
>>> dict
{'a': 123, 'c': 678, 'b': 345, 'd': 910}
add a comment |
At first, you need to convert the string (here, as the example, to the array, but you can use that you want)
data = [x.split('=') for x in data.split('&')]
>>> data
[['a', '123'], ['b', '345'], ['c', '678'], ['d', '910']]
And after this, you can easily create the dictionary.
dict = {key: value for (key,value) in data}
>>> dict
{'a': '123', 'c': '678', 'b': '345', 'd': '910'}
Or if you want to store numbers as int:
dict = {key: int(value) for (key,value) in data}
>>> dict
{'a': 123, 'c': 678, 'b': 345, 'd': 910}
add a comment |
At first, you need to convert the string (here, as the example, to the array, but you can use that you want)
data = [x.split('=') for x in data.split('&')]
>>> data
[['a', '123'], ['b', '345'], ['c', '678'], ['d', '910']]
And after this, you can easily create the dictionary.
dict = {key: value for (key,value) in data}
>>> dict
{'a': '123', 'c': '678', 'b': '345', 'd': '910'}
Or if you want to store numbers as int:
dict = {key: int(value) for (key,value) in data}
>>> dict
{'a': 123, 'c': 678, 'b': 345, 'd': 910}
At first, you need to convert the string (here, as the example, to the array, but you can use that you want)
data = [x.split('=') for x in data.split('&')]
>>> data
[['a', '123'], ['b', '345'], ['c', '678'], ['d', '910']]
And after this, you can easily create the dictionary.
dict = {key: value for (key,value) in data}
>>> dict
{'a': '123', 'c': '678', 'b': '345', 'd': '910'}
Or if you want to store numbers as int:
dict = {key: int(value) for (key,value) in data}
>>> dict
{'a': 123, 'c': 678, 'b': 345, 'd': 910}
edited Nov 23 '18 at 9:19
tripleee
89.1k12124181
89.1k12124181
answered Nov 23 '18 at 9:18
Ihor VoroninIhor Voronin
1856
1856
add a comment |
add a comment |
import json
from urllib.parse import parse_qs
payload = request.body
# b'a=123&b=345&c=678&d=910'
qs = parse_qs(payload.decode())
# {'a': ['123'], 'b': ['345'], 'c': ['678'], 'd': ['910']}
Convert list values and convert data into JSON
json.dumps({k: v[0] for k, v in qs.items()})
# '{"a": "123", "b": "345", "c": "678", "d": "910"}'
2
An explanation, what the posted code does and how this addresses the problem in the question, rarely fails to improve an answer.
– blue-phoenox
Nov 23 '18 at 9:35
add a comment |
import json
from urllib.parse import parse_qs
payload = request.body
# b'a=123&b=345&c=678&d=910'
qs = parse_qs(payload.decode())
# {'a': ['123'], 'b': ['345'], 'c': ['678'], 'd': ['910']}
Convert list values and convert data into JSON
json.dumps({k: v[0] for k, v in qs.items()})
# '{"a": "123", "b": "345", "c": "678", "d": "910"}'
2
An explanation, what the posted code does and how this addresses the problem in the question, rarely fails to improve an answer.
– blue-phoenox
Nov 23 '18 at 9:35
add a comment |
import json
from urllib.parse import parse_qs
payload = request.body
# b'a=123&b=345&c=678&d=910'
qs = parse_qs(payload.decode())
# {'a': ['123'], 'b': ['345'], 'c': ['678'], 'd': ['910']}
Convert list values and convert data into JSON
json.dumps({k: v[0] for k, v in qs.items()})
# '{"a": "123", "b": "345", "c": "678", "d": "910"}'
import json
from urllib.parse import parse_qs
payload = request.body
# b'a=123&b=345&c=678&d=910'
qs = parse_qs(payload.decode())
# {'a': ['123'], 'b': ['345'], 'c': ['678'], 'd': ['910']}
Convert list values and convert data into JSON
json.dumps({k: v[0] for k, v in qs.items()})
# '{"a": "123", "b": "345", "c": "678", "d": "910"}'
edited Nov 23 '18 at 10:42
answered Nov 23 '18 at 9:13
vczmvczm
413
413
2
An explanation, what the posted code does and how this addresses the problem in the question, rarely fails to improve an answer.
– blue-phoenox
Nov 23 '18 at 9:35
add a comment |
2
An explanation, what the posted code does and how this addresses the problem in the question, rarely fails to improve an answer.
– blue-phoenox
Nov 23 '18 at 9:35
2
2
An explanation, what the posted code does and how this addresses the problem in the question, rarely fails to improve an answer.
– blue-phoenox
Nov 23 '18 at 9:35
An explanation, what the posted code does and how this addresses the problem in the question, rarely fails to improve an answer.
– blue-phoenox
Nov 23 '18 at 9:35
add a comment |
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Some of your past answers have not been well-received, and you're in danger of being blocked from answering.
Please pay close attention to the following guidance:
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53443490%2fhow-to-convert-data-into-json-dictionary%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
1
The string doesn't contain any single quotes, so replacing them is superfluous (and if it wasn't, it'd be wrong). Other than that, are you looking for
d = dict(x.split('=', 1) for x in payload.decode('utf-8').split('&'))
perhaps?– tripleee
Nov 23 '18 at 9:18