Definition of sample mean











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I've seen two definitions of sample mean on the internet.

One definition defines it as the average of Random variable other defines it as the average of sample values of a sample.

I'm confused which one is correct.

Also if it is defined as the average of random variables why don't we just define it as the average of sample values?










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  • For a sample $X_1,X_2,ldots,X_n$ ($X_i$'s being random variables) of size $n$, the sample mean is the statistic $overline X=frac{1}{n}sum_{i=1}^n X_i$. If we denote the observed values of the sample by $x_1,ldots,x_n$, then the observed value of the sample mean is $bar x=frac{1}{n}sum_{i=1}^n x_i$. I think you are asking the same question as here.
    – StubbornAtom
    Nov 11 at 13:51















up vote
0
down vote

favorite












I've seen two definitions of sample mean on the internet.

One definition defines it as the average of Random variable other defines it as the average of sample values of a sample.

I'm confused which one is correct.

Also if it is defined as the average of random variables why don't we just define it as the average of sample values?










share|cite|improve this question






















  • For a sample $X_1,X_2,ldots,X_n$ ($X_i$'s being random variables) of size $n$, the sample mean is the statistic $overline X=frac{1}{n}sum_{i=1}^n X_i$. If we denote the observed values of the sample by $x_1,ldots,x_n$, then the observed value of the sample mean is $bar x=frac{1}{n}sum_{i=1}^n x_i$. I think you are asking the same question as here.
    – StubbornAtom
    Nov 11 at 13:51













up vote
0
down vote

favorite









up vote
0
down vote

favorite











I've seen two definitions of sample mean on the internet.

One definition defines it as the average of Random variable other defines it as the average of sample values of a sample.

I'm confused which one is correct.

Also if it is defined as the average of random variables why don't we just define it as the average of sample values?










share|cite|improve this question













I've seen two definitions of sample mean on the internet.

One definition defines it as the average of Random variable other defines it as the average of sample values of a sample.

I'm confused which one is correct.

Also if it is defined as the average of random variables why don't we just define it as the average of sample values?







statistics means sampling






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asked Nov 11 at 13:27









falcon lover

11




11












  • For a sample $X_1,X_2,ldots,X_n$ ($X_i$'s being random variables) of size $n$, the sample mean is the statistic $overline X=frac{1}{n}sum_{i=1}^n X_i$. If we denote the observed values of the sample by $x_1,ldots,x_n$, then the observed value of the sample mean is $bar x=frac{1}{n}sum_{i=1}^n x_i$. I think you are asking the same question as here.
    – StubbornAtom
    Nov 11 at 13:51


















  • For a sample $X_1,X_2,ldots,X_n$ ($X_i$'s being random variables) of size $n$, the sample mean is the statistic $overline X=frac{1}{n}sum_{i=1}^n X_i$. If we denote the observed values of the sample by $x_1,ldots,x_n$, then the observed value of the sample mean is $bar x=frac{1}{n}sum_{i=1}^n x_i$. I think you are asking the same question as here.
    – StubbornAtom
    Nov 11 at 13:51
















For a sample $X_1,X_2,ldots,X_n$ ($X_i$'s being random variables) of size $n$, the sample mean is the statistic $overline X=frac{1}{n}sum_{i=1}^n X_i$. If we denote the observed values of the sample by $x_1,ldots,x_n$, then the observed value of the sample mean is $bar x=frac{1}{n}sum_{i=1}^n x_i$. I think you are asking the same question as here.
– StubbornAtom
Nov 11 at 13:51




For a sample $X_1,X_2,ldots,X_n$ ($X_i$'s being random variables) of size $n$, the sample mean is the statistic $overline X=frac{1}{n}sum_{i=1}^n X_i$. If we denote the observed values of the sample by $x_1,ldots,x_n$, then the observed value of the sample mean is $bar x=frac{1}{n}sum_{i=1}^n x_i$. I think you are asking the same question as here.
– StubbornAtom
Nov 11 at 13:51










2 Answers
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Given samples ${x_i}_{i=1}^n$ (presumed to be drawn from an underlying distribution $F$, density $f$), the sample mean $bar{x}$ defined as:



$bar{x} = frac{1}{n} sum_{i=1}^n x_i$



is an estimate of the expected value $mathbb{E}[X]$ of that distribution.



On the other hand, given RVs ${X_i}_{i=1}^n$ (drawn independently from distribution $F$), their average $bar{X}$ defined as:



$bar{X} = frac{1}{n} sum_{i=1}^n X_i$



is also a random variable with mean $mathbb{E}[bar{X}] = mathbb{E}[X]$ and distribution given by an n-fold convolution of $f$.



It is not meaningful to compare $bar{x}$ and $bar{X}$ directly.






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    In statistical probability, a single sampled value is a random variable.
    If you have a sample consisting of $N$ values, then you have $N$ random variables.
    The words "sample value" are just another name for one of these random variables.



    So both methods of obtaining a "sample mean" do exactly the same thing.



    The mean value of a random variable is a completely different thing.
    Be careful not to write "variable" (singular) when the text you are getting your definitions from said "variables" (plural).
    It changes the possible interpretation of what you write quite dramatically.






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      2 Answers
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      2 Answers
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      up vote
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      down vote













      Given samples ${x_i}_{i=1}^n$ (presumed to be drawn from an underlying distribution $F$, density $f$), the sample mean $bar{x}$ defined as:



      $bar{x} = frac{1}{n} sum_{i=1}^n x_i$



      is an estimate of the expected value $mathbb{E}[X]$ of that distribution.



      On the other hand, given RVs ${X_i}_{i=1}^n$ (drawn independently from distribution $F$), their average $bar{X}$ defined as:



      $bar{X} = frac{1}{n} sum_{i=1}^n X_i$



      is also a random variable with mean $mathbb{E}[bar{X}] = mathbb{E}[X]$ and distribution given by an n-fold convolution of $f$.



      It is not meaningful to compare $bar{x}$ and $bar{X}$ directly.






      share|cite|improve this answer

























        up vote
        0
        down vote













        Given samples ${x_i}_{i=1}^n$ (presumed to be drawn from an underlying distribution $F$, density $f$), the sample mean $bar{x}$ defined as:



        $bar{x} = frac{1}{n} sum_{i=1}^n x_i$



        is an estimate of the expected value $mathbb{E}[X]$ of that distribution.



        On the other hand, given RVs ${X_i}_{i=1}^n$ (drawn independently from distribution $F$), their average $bar{X}$ defined as:



        $bar{X} = frac{1}{n} sum_{i=1}^n X_i$



        is also a random variable with mean $mathbb{E}[bar{X}] = mathbb{E}[X]$ and distribution given by an n-fold convolution of $f$.



        It is not meaningful to compare $bar{x}$ and $bar{X}$ directly.






        share|cite|improve this answer























          up vote
          0
          down vote










          up vote
          0
          down vote









          Given samples ${x_i}_{i=1}^n$ (presumed to be drawn from an underlying distribution $F$, density $f$), the sample mean $bar{x}$ defined as:



          $bar{x} = frac{1}{n} sum_{i=1}^n x_i$



          is an estimate of the expected value $mathbb{E}[X]$ of that distribution.



          On the other hand, given RVs ${X_i}_{i=1}^n$ (drawn independently from distribution $F$), their average $bar{X}$ defined as:



          $bar{X} = frac{1}{n} sum_{i=1}^n X_i$



          is also a random variable with mean $mathbb{E}[bar{X}] = mathbb{E}[X]$ and distribution given by an n-fold convolution of $f$.



          It is not meaningful to compare $bar{x}$ and $bar{X}$ directly.






          share|cite|improve this answer












          Given samples ${x_i}_{i=1}^n$ (presumed to be drawn from an underlying distribution $F$, density $f$), the sample mean $bar{x}$ defined as:



          $bar{x} = frac{1}{n} sum_{i=1}^n x_i$



          is an estimate of the expected value $mathbb{E}[X]$ of that distribution.



          On the other hand, given RVs ${X_i}_{i=1}^n$ (drawn independently from distribution $F$), their average $bar{X}$ defined as:



          $bar{X} = frac{1}{n} sum_{i=1}^n X_i$



          is also a random variable with mean $mathbb{E}[bar{X}] = mathbb{E}[X]$ and distribution given by an n-fold convolution of $f$.



          It is not meaningful to compare $bar{x}$ and $bar{X}$ directly.







          share|cite|improve this answer












          share|cite|improve this answer



          share|cite|improve this answer










          answered yesterday









          Aditya Dua

          4906




          4906






















              up vote
              0
              down vote













              In statistical probability, a single sampled value is a random variable.
              If you have a sample consisting of $N$ values, then you have $N$ random variables.
              The words "sample value" are just another name for one of these random variables.



              So both methods of obtaining a "sample mean" do exactly the same thing.



              The mean value of a random variable is a completely different thing.
              Be careful not to write "variable" (singular) when the text you are getting your definitions from said "variables" (plural).
              It changes the possible interpretation of what you write quite dramatically.






              share|cite|improve this answer

























                up vote
                0
                down vote













                In statistical probability, a single sampled value is a random variable.
                If you have a sample consisting of $N$ values, then you have $N$ random variables.
                The words "sample value" are just another name for one of these random variables.



                So both methods of obtaining a "sample mean" do exactly the same thing.



                The mean value of a random variable is a completely different thing.
                Be careful not to write "variable" (singular) when the text you are getting your definitions from said "variables" (plural).
                It changes the possible interpretation of what you write quite dramatically.






                share|cite|improve this answer























                  up vote
                  0
                  down vote










                  up vote
                  0
                  down vote









                  In statistical probability, a single sampled value is a random variable.
                  If you have a sample consisting of $N$ values, then you have $N$ random variables.
                  The words "sample value" are just another name for one of these random variables.



                  So both methods of obtaining a "sample mean" do exactly the same thing.



                  The mean value of a random variable is a completely different thing.
                  Be careful not to write "variable" (singular) when the text you are getting your definitions from said "variables" (plural).
                  It changes the possible interpretation of what you write quite dramatically.






                  share|cite|improve this answer












                  In statistical probability, a single sampled value is a random variable.
                  If you have a sample consisting of $N$ values, then you have $N$ random variables.
                  The words "sample value" are just another name for one of these random variables.



                  So both methods of obtaining a "sample mean" do exactly the same thing.



                  The mean value of a random variable is a completely different thing.
                  Be careful not to write "variable" (singular) when the text you are getting your definitions from said "variables" (plural).
                  It changes the possible interpretation of what you write quite dramatically.







                  share|cite|improve this answer












                  share|cite|improve this answer



                  share|cite|improve this answer










                  answered yesterday









                  David K

                  51.2k340113




                  51.2k340113






























                       

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