Rearrangement of lists of strings

up vote
5
down vote

favorite

I have a list:

lis = {{"abc","def","ghi"},{"jkl","mno"}}

and wish to get:

res = {"abc def ghi","jkl mno"}

This:

Table[StringJoin[lis[[i]]], {i, Length[lis]}]

doesn't produce the desired " " between the original elements in lis. As always, thanks for suggestions!

edited Nov 25 at 9:27

kglr

174k9197402

asked Nov 25 at 2:43

Suite401

959312

add a comment |

up vote
5
down vote

favorite

I have a list:

lis = {{"abc","def","ghi"},{"jkl","mno"}}

and wish to get:

res = {"abc def ghi","jkl mno"}

This:

Table[StringJoin[lis[[i]]], {i, Length[lis]}]

doesn't produce the desired " " between the original elements in lis. As always, thanks for suggestions!

edited Nov 25 at 9:27

kglr

174k9197402

asked Nov 25 at 2:43

Suite401

959312

add a comment |

up vote
5
down vote

favorite

I have a list:

lis = {{"abc","def","ghi"},{"jkl","mno"}}

and wish to get:

res = {"abc def ghi","jkl mno"}

This:

Table[StringJoin[lis[[i]]], {i, Length[lis]}]

doesn't produce the desired " " between the original elements in lis. As always, thanks for suggestions!

edited Nov 25 at 9:27

kglr

174k9197402

asked Nov 25 at 2:43

Suite401

959312

I have a list:

lis = {{"abc","def","ghi"},{"jkl","mno"}}

and wish to get:

res = {"abc def ghi","jkl mno"}

This:

Table[StringJoin[lis[[i]]], {i, Length[lis]}]

doesn't produce the desired " " between the original elements in lis. As always, thanks for suggestions!

string-manipulation

edited Nov 25 at 9:27

kglr

174k9197402

asked Nov 25 at 2:43

Suite401

959312

edited Nov 25 at 9:27

kglr

174k9197402

asked Nov 25 at 2:43

Suite401

959312

edited Nov 25 at 9:27

kglr

174k9197402

edited Nov 25 at 9:27

kglr

174k9197402

edited Nov 25 at 9:27

kglr

174k9197402

asked Nov 25 at 2:43

Suite401

959312

asked Nov 25 at 2:43

Suite401

959312

asked Nov 25 at 2:43

Suite401

959312

add a comment |

2 Answers
2

active

oldest

votes

up vote
14
down vote

accepted

You can use StringRiffle:

StringRiffle /@ lis

{"abc def ghi", "jkl mno"}

answered Nov 25 at 2:56

kglr

174k9197402

add a comment |

up vote
6
down vote

Use Riffle

lis = {{"abc", "def", "ghi"}, {"jkl", "mno"}};



StringJoin[Riffle[#, " "]] & /@ lis



(* {"abc def ghi", "jkl mno"} *)

answered Nov 25 at 2:52

Bob Hanlon

58k23593

add a comment |

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2 Answers
2

active

oldest

votes

2 Answers
2

active

oldest

votes

up vote
14
down vote

accepted

You can use StringRiffle:

StringRiffle /@ lis

{"abc def ghi", "jkl mno"}

answered Nov 25 at 2:56

kglr

174k9197402

add a comment |

up vote
14
down vote

accepted

You can use StringRiffle:

StringRiffle /@ lis

{"abc def ghi", "jkl mno"}

answered Nov 25 at 2:56

kglr

174k9197402

add a comment |

up vote
14
down vote

accepted

You can use StringRiffle:

StringRiffle /@ lis

{"abc def ghi", "jkl mno"}

answered Nov 25 at 2:56

kglr

174k9197402

You can use StringRiffle:

StringRiffle /@ lis

{"abc def ghi", "jkl mno"}

answered Nov 25 at 2:56

kglr

174k9197402

answered Nov 25 at 2:56

kglr

174k9197402

answered Nov 25 at 2:56

kglr

174k9197402

answered Nov 25 at 2:56

kglr

174k9197402

add a comment |

up vote
6
down vote

Use Riffle

lis = {{"abc", "def", "ghi"}, {"jkl", "mno"}};



StringJoin[Riffle[#, " "]] & /@ lis



(* {"abc def ghi", "jkl mno"} *)

answered Nov 25 at 2:52

Bob Hanlon

58k23593

add a comment |

up vote
6
down vote

Use Riffle

lis = {{"abc", "def", "ghi"}, {"jkl", "mno"}};



StringJoin[Riffle[#, " "]] & /@ lis



(* {"abc def ghi", "jkl mno"} *)

answered Nov 25 at 2:52

Bob Hanlon

58k23593

add a comment |

up vote
6
down vote

Use Riffle

lis = {{"abc", "def", "ghi"}, {"jkl", "mno"}};



StringJoin[Riffle[#, " "]] & /@ lis



(* {"abc def ghi", "jkl mno"} *)

answered Nov 25 at 2:52

Bob Hanlon

58k23593

Use Riffle

lis = {{"abc", "def", "ghi"}, {"jkl", "mno"}};



StringJoin[Riffle[#, " "]] & /@ lis



(* {"abc def ghi", "jkl mno"} *)

answered Nov 25 at 2:52

Bob Hanlon

58k23593

answered Nov 25 at 2:52

Bob Hanlon

58k23593

answered Nov 25 at 2:52

Bob Hanlon

58k23593

answered Nov 25 at 2:52

Bob Hanlon

58k23593

add a comment |

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