Xpath from next page to scrapy in Stack Overflow
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1
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I'm trying to crawl Stack Overflow with scrapy, but I'm not clear enough to make the rule to get next page. I don't know if the XPath I choose is right also.
He follows the code:
class StackCrawlerSpider(CrawlSpider):
name = 'stack_crawler'
allowed_domains = ['stackoverflow.com']
start_urls = [
'http://stackoverflow.com/questions?pagesize=50&sort=newest'
]
rules = [
Rule(LinkExtractor(allow=(), restrict_xpaths=('div[@class="pager fl"]/a[@class="page-numbers next"]/@href',)),
callback='parse_item', follow=True)
]
Could someone who understand scrapy an XPath help me to get next page from the following page (http://stackoverflow.com/questions?pagesize=50&sort=newest) and add it to the rule?
xpath web-scraping scrapy
add a comment |
up vote
1
down vote
favorite
I'm trying to crawl Stack Overflow with scrapy, but I'm not clear enough to make the rule to get next page. I don't know if the XPath I choose is right also.
He follows the code:
class StackCrawlerSpider(CrawlSpider):
name = 'stack_crawler'
allowed_domains = ['stackoverflow.com']
start_urls = [
'http://stackoverflow.com/questions?pagesize=50&sort=newest'
]
rules = [
Rule(LinkExtractor(allow=(), restrict_xpaths=('div[@class="pager fl"]/a[@class="page-numbers next"]/@href',)),
callback='parse_item', follow=True)
]
Could someone who understand scrapy an XPath help me to get next page from the following page (http://stackoverflow.com/questions?pagesize=50&sort=newest) and add it to the rule?
xpath web-scraping scrapy
add a comment |
up vote
1
down vote
favorite
up vote
1
down vote
favorite
I'm trying to crawl Stack Overflow with scrapy, but I'm not clear enough to make the rule to get next page. I don't know if the XPath I choose is right also.
He follows the code:
class StackCrawlerSpider(CrawlSpider):
name = 'stack_crawler'
allowed_domains = ['stackoverflow.com']
start_urls = [
'http://stackoverflow.com/questions?pagesize=50&sort=newest'
]
rules = [
Rule(LinkExtractor(allow=(), restrict_xpaths=('div[@class="pager fl"]/a[@class="page-numbers next"]/@href',)),
callback='parse_item', follow=True)
]
Could someone who understand scrapy an XPath help me to get next page from the following page (http://stackoverflow.com/questions?pagesize=50&sort=newest) and add it to the rule?
xpath web-scraping scrapy
I'm trying to crawl Stack Overflow with scrapy, but I'm not clear enough to make the rule to get next page. I don't know if the XPath I choose is right also.
He follows the code:
class StackCrawlerSpider(CrawlSpider):
name = 'stack_crawler'
allowed_domains = ['stackoverflow.com']
start_urls = [
'http://stackoverflow.com/questions?pagesize=50&sort=newest'
]
rules = [
Rule(LinkExtractor(allow=(), restrict_xpaths=('div[@class="pager fl"]/a[@class="page-numbers next"]/@href',)),
callback='parse_item', follow=True)
]
Could someone who understand scrapy an XPath help me to get next page from the following page (http://stackoverflow.com/questions?pagesize=50&sort=newest) and add it to the rule?
xpath web-scraping scrapy
xpath web-scraping scrapy
edited Nov 26 at 1:42
Pang
6,8301563101
6,8301563101
asked Nov 21 at 23:34
Lucas Oliveira Costa
154
154
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1 Answer
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oldest
votes
up vote
1
down vote
accepted
you need to select root element //
then go to span
containing class page-numbers next
and text next
then go to it parent ..
which is a
tag.
//span[@class="page-numbers next"]/../@href
Wouldn't it be simpler to use//a[@rel="next"]/@href
?
– Casper
Nov 22 at 13:52
yes you're right, above is first way in my mind
– ewwink
Nov 22 at 20:16
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
1
down vote
accepted
you need to select root element //
then go to span
containing class page-numbers next
and text next
then go to it parent ..
which is a
tag.
//span[@class="page-numbers next"]/../@href
Wouldn't it be simpler to use//a[@rel="next"]/@href
?
– Casper
Nov 22 at 13:52
yes you're right, above is first way in my mind
– ewwink
Nov 22 at 20:16
add a comment |
up vote
1
down vote
accepted
you need to select root element //
then go to span
containing class page-numbers next
and text next
then go to it parent ..
which is a
tag.
//span[@class="page-numbers next"]/../@href
Wouldn't it be simpler to use//a[@rel="next"]/@href
?
– Casper
Nov 22 at 13:52
yes you're right, above is first way in my mind
– ewwink
Nov 22 at 20:16
add a comment |
up vote
1
down vote
accepted
up vote
1
down vote
accepted
you need to select root element //
then go to span
containing class page-numbers next
and text next
then go to it parent ..
which is a
tag.
//span[@class="page-numbers next"]/../@href
you need to select root element //
then go to span
containing class page-numbers next
and text next
then go to it parent ..
which is a
tag.
//span[@class="page-numbers next"]/../@href
answered Nov 22 at 2:09
ewwink
8,68122235
8,68122235
Wouldn't it be simpler to use//a[@rel="next"]/@href
?
– Casper
Nov 22 at 13:52
yes you're right, above is first way in my mind
– ewwink
Nov 22 at 20:16
add a comment |
Wouldn't it be simpler to use//a[@rel="next"]/@href
?
– Casper
Nov 22 at 13:52
yes you're right, above is first way in my mind
– ewwink
Nov 22 at 20:16
Wouldn't it be simpler to use
//a[@rel="next"]/@href
?– Casper
Nov 22 at 13:52
Wouldn't it be simpler to use
//a[@rel="next"]/@href
?– Casper
Nov 22 at 13:52
yes you're right, above is first way in my mind
– ewwink
Nov 22 at 20:16
yes you're right, above is first way in my mind
– ewwink
Nov 22 at 20:16
add a comment |
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