If $Acap B subseteq bar{C}$ and $Acup C subseteq B$ then $Acap C=emptyset$
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Prove the following:
If $Acap B subseteq bar{C}$ and $Acup C subseteq B$ then $Acap C=emptyset$
discrete-mathematics elementary-set-theory
edited Nov 28 at 3:21
Andrés E. Caicedo
64.6k8158246
asked Nov 28 at 2:21
Mharfe Micaroz
11
|
show 1 more comment
up vote
-4
down vote
favorite
Prove the following:
If $Acap B subseteq bar{C}$ and $Acup C subseteq B$ then $Acap C=emptyset$
discrete-mathematics elementary-set-theory
edited Nov 28 at 3:21
Andrés E. Caicedo
64.6k8158246
asked Nov 28 at 2:21
Mharfe Micaroz
11
how do you know if it's very hard? did you try it? can you share with us what you have tried?
– Siong Thye Goh
Nov 28 at 2:23
I tried it using direct method.
– Mharfe Micaroz
Nov 28 at 2:24
I see, perhaps try by contradiction? it might give you more tools to use. Include your attempt directly in the post. Usually people are more willing to help if you include your attempt. Welcome to MSE.
– Siong Thye Goh
Nov 28 at 2:25
Work by contradiction. Suppose $xin Acap C$. Then $xin A$, so $xin Acup C$, so $xin B$, so ....
– symplectomorphic
Nov 28 at 2:25
Thanks so much.. Actually I need help in my set theory,
– Mharfe Micaroz
Nov 28 at 2:26
|
show 1 more comment
up vote
-4
down vote
favorite
up vote
-4
down vote
favorite
Prove the following:
If $Acap B subseteq bar{C}$ and $Acup C subseteq B$ then $Acap C=emptyset$
discrete-mathematics elementary-set-theory
edited Nov 28 at 3:21
Andrés E. Caicedo
64.6k8158246
asked Nov 28 at 2:21
Mharfe Micaroz
11
Prove the following:
If $Acap B subseteq bar{C}$ and $Acup C subseteq B$ then $Acap C=emptyset$
discrete-mathematics elementary-set-theory
discrete-mathematics elementary-set-theory
edited Nov 28 at 3:21
Andrés E. Caicedo
64.6k8158246
asked Nov 28 at 2:21
Mharfe Micaroz
11
edited Nov 28 at 3:21
Andrés E. Caicedo
64.6k8158246
asked Nov 28 at 2:21
Mharfe Micaroz
11
edited Nov 28 at 3:21
Andrés E. Caicedo
64.6k8158246
edited Nov 28 at 3:21
Andrés E. Caicedo
64.6k8158246
edited Nov 28 at 3:21
Andrés E. Caicedo
64.6k8158246
64.6k8158246
asked Nov 28 at 2:21
Mharfe Micaroz
11
asked Nov 28 at 2:21
Mharfe Micaroz
11
asked Nov 28 at 2:21
Mharfe Micaroz
11
11
how do you know if it's very hard? did you try it? can you share with us what you have tried?
– Siong Thye Goh
Nov 28 at 2:23
I tried it using direct method.
– Mharfe Micaroz
Nov 28 at 2:24
I see, perhaps try by contradiction? it might give you more tools to use. Include your attempt directly in the post. Usually people are more willing to help if you include your attempt. Welcome to MSE.
– Siong Thye Goh
Nov 28 at 2:25
Work by contradiction. Suppose $xin Acap C$. Then $xin A$, so $xin Acup C$, so $xin B$, so ....
– symplectomorphic
Nov 28 at 2:25
Thanks so much.. Actually I need help in my set theory,
– Mharfe Micaroz
Nov 28 at 2:26
|
show 1 more comment
how do you know if it's very hard? did you try it? can you share with us what you have tried?
– Siong Thye Goh
Nov 28 at 2:23
I tried it using direct method.
– Mharfe Micaroz
Nov 28 at 2:24
I see, perhaps try by contradiction? it might give you more tools to use. Include your attempt directly in the post. Usually people are more willing to help if you include your attempt. Welcome to MSE.
– Siong Thye Goh
Nov 28 at 2:25
Work by contradiction. Suppose $xin Acap C$. Then $xin A$, so $xin Acup C$, so $xin B$, so ....
– symplectomorphic
Nov 28 at 2:25
Thanks so much.. Actually I need help in my set theory,
– Mharfe Micaroz
Nov 28 at 2:26
how do you know if it's very hard? did you try it? can you share with us what you have tried?
– Siong Thye Goh
Nov 28 at 2:23
how do you know if it's very hard? did you try it? can you share with us what you have tried?
– Siong Thye Goh
Nov 28 at 2:23
I tried it using direct method.
– Mharfe Micaroz
Nov 28 at 2:24
I tried it using direct method.
– Mharfe Micaroz
Nov 28 at 2:24
I see, perhaps try by contradiction? it might give you more tools to use. Include your attempt directly in the post. Usually people are more willing to help if you include your attempt. Welcome to MSE.
– Siong Thye Goh
Nov 28 at 2:25
I see, perhaps try by contradiction? it might give you more tools to use. Include your attempt directly in the post. Usually people are more willing to help if you include your attempt. Welcome to MSE.
– Siong Thye Goh
Nov 28 at 2:25
Work by contradiction. Suppose $xin Acap C$. Then $xin A$, so $xin Acup C$, so $xin B$, so ....
– symplectomorphic
Nov 28 at 2:25
Work by contradiction. Suppose $xin Acap C$. Then $xin A$, so $xin Acup C$, so $xin B$, so ....
– symplectomorphic
Nov 28 at 2:25
Thanks so much.. Actually I need help in my set theory,
– Mharfe Micaroz
Nov 28 at 2:26
Thanks so much.. Actually I need help in my set theory,
– Mharfe Micaroz
Nov 28 at 2:26
|
show 1 more comment
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how do you know if it's very hard? did you try it? can you share with us what you have tried?
– Siong Thye Goh
Nov 28 at 2:23
I tried it using direct method.
– Mharfe Micaroz
Nov 28 at 2:24
I see, perhaps try by contradiction? it might give you more tools to use. Include your attempt directly in the post. Usually people are more willing to help if you include your attempt. Welcome to MSE.
– Siong Thye Goh
Nov 28 at 2:25
Work by contradiction. Suppose $xin Acap C$. Then $xin A$, so $xin Acup C$, so $xin B$, so ....
– symplectomorphic
Nov 28 at 2:25
Thanks so much.. Actually I need help in my set theory,
– Mharfe Micaroz
Nov 28 at 2:26