What is the best formula for calculating average based on count?
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I would like to calculate an average of the series based on the count.
Say, for example,
Series 1 (10 values): 5, 1, 2, 3, 4, 5, 4, 1, 2, 3
Average: 30 / 10 = 3
Series 2 (2 values): 3, 4
Average: 7 / 2 = 3.5
Series 2 has the higher average than series 1 but series attempted 10 times which is more than series 2 (2 times).
I need to find a formula to calculate the average based on the counts to make sure the values are perfectly averaged. Can anyone help me achieve this?
sequences-and-series average
asked Nov 25 at 13:24
good-to-know
1011
add a comment |
up vote
0
down vote
favorite
I would like to calculate an average of the series based on the count.
Say, for example,
Series 1 (10 values): 5, 1, 2, 3, 4, 5, 4, 1, 2, 3
Average: 30 / 10 = 3
Series 2 (2 values): 3, 4
Average: 7 / 2 = 3.5
Series 2 has the higher average than series 1 but series attempted 10 times which is more than series 2 (2 times).
I need to find a formula to calculate the average based on the counts to make sure the values are perfectly averaged. Can anyone help me achieve this?
sequences-and-series average
asked Nov 25 at 13:24
good-to-know
1011
Welcome to MSE. It will be more likely that you will get an answer if you show us that you made an effort. This should be added to the question rather than in the comments.
– José Carlos Santos
Nov 25 at 13:25
I agree. I quoted what I actually tried in the question itself.
– good-to-know
Nov 25 at 13:26
The problem is that you want an answer for a question that you have not given. What do you mean with "perfectly averaged"? What I guess is that your series' come from some kind of measurement (like school grades) and maybe you want to take into account that having an average score of 3.4 over 10 grades is more reliable than one of 3.5 over just 2 grades. But all of this information needs to come from you, there is no magical formula that will take that into account that is generally applicable.
– Ingix
Nov 25 at 16:15
@Ingix What I need to do, then?
– good-to-know
Nov 27 at 13:11
Describe what you want in your terms, and try not to use phrases like "perfectly averaged", which are not well defined. Include the background of the question (as I guessed at). Make a new question for this.
– Ingix
Nov 27 at 13:16
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
I would like to calculate an average of the series based on the count.
Say, for example,
Series 1 (10 values): 5, 1, 2, 3, 4, 5, 4, 1, 2, 3
Average: 30 / 10 = 3
Series 2 (2 values): 3, 4
Average: 7 / 2 = 3.5
Series 2 has the higher average than series 1 but series attempted 10 times which is more than series 2 (2 times).
I need to find a formula to calculate the average based on the counts to make sure the values are perfectly averaged. Can anyone help me achieve this?
sequences-and-series average
asked Nov 25 at 13:24
good-to-know
1011
I would like to calculate an average of the series based on the count.
Say, for example,
Series 1 (10 values): 5, 1, 2, 3, 4, 5, 4, 1, 2, 3
Average: 30 / 10 = 3
Series 2 (2 values): 3, 4
Average: 7 / 2 = 3.5
Series 2 has the higher average than series 1 but series attempted 10 times which is more than series 2 (2 times).
I need to find a formula to calculate the average based on the counts to make sure the values are perfectly averaged. Can anyone help me achieve this?
sequences-and-series average
sequences-and-series average
asked Nov 25 at 13:24
good-to-know
1011
asked Nov 25 at 13:24
good-to-know
1011
asked Nov 25 at 13:24
good-to-know
1011
asked Nov 25 at 13:24
good-to-know
1011
asked Nov 25 at 13:24
good-to-know
1011
1011
Welcome to MSE. It will be more likely that you will get an answer if you show us that you made an effort. This should be added to the question rather than in the comments.
– José Carlos Santos
Nov 25 at 13:25
I agree. I quoted what I actually tried in the question itself.
– good-to-know
Nov 25 at 13:26
The problem is that you want an answer for a question that you have not given. What do you mean with "perfectly averaged"? What I guess is that your series' come from some kind of measurement (like school grades) and maybe you want to take into account that having an average score of 3.4 over 10 grades is more reliable than one of 3.5 over just 2 grades. But all of this information needs to come from you, there is no magical formula that will take that into account that is generally applicable.
– Ingix
Nov 25 at 16:15
@Ingix What I need to do, then?
– good-to-know
Nov 27 at 13:11
Describe what you want in your terms, and try not to use phrases like "perfectly averaged", which are not well defined. Include the background of the question (as I guessed at). Make a new question for this.
– Ingix
Nov 27 at 13:16
add a comment |
Welcome to MSE. It will be more likely that you will get an answer if you show us that you made an effort. This should be added to the question rather than in the comments.
– José Carlos Santos
Nov 25 at 13:25
I agree. I quoted what I actually tried in the question itself.
– good-to-know
Nov 25 at 13:26
The problem is that you want an answer for a question that you have not given. What do you mean with "perfectly averaged"? What I guess is that your series' come from some kind of measurement (like school grades) and maybe you want to take into account that having an average score of 3.4 over 10 grades is more reliable than one of 3.5 over just 2 grades. But all of this information needs to come from you, there is no magical formula that will take that into account that is generally applicable.
– Ingix
Nov 25 at 16:15
@Ingix What I need to do, then?
– good-to-know
Nov 27 at 13:11
Describe what you want in your terms, and try not to use phrases like "perfectly averaged", which are not well defined. Include the background of the question (as I guessed at). Make a new question for this.
– Ingix
Nov 27 at 13:16
Welcome to MSE. It will be more likely that you will get an answer if you show us that you made an effort. This should be added to the question rather than in the comments.
– José Carlos Santos
Nov 25 at 13:25
Welcome to MSE. It will be more likely that you will get an answer if you show us that you made an effort. This should be added to the question rather than in the comments.
– José Carlos Santos
Nov 25 at 13:25
I agree. I quoted what I actually tried in the question itself.
– good-to-know
Nov 25 at 13:26
I agree. I quoted what I actually tried in the question itself.
– good-to-know
Nov 25 at 13:26
The problem is that you want an answer for a question that you have not given. What do you mean with "perfectly averaged"? What I guess is that your series' come from some kind of measurement (like school grades) and maybe you want to take into account that having an average score of 3.4 over 10 grades is more reliable than one of 3.5 over just 2 grades. But all of this information needs to come from you, there is no magical formula that will take that into account that is generally applicable.
– Ingix
Nov 25 at 16:15
The problem is that you want an answer for a question that you have not given. What do you mean with "perfectly averaged"? What I guess is that your series' come from some kind of measurement (like school grades) and maybe you want to take into account that having an average score of 3.4 over 10 grades is more reliable than one of 3.5 over just 2 grades. But all of this information needs to come from you, there is no magical formula that will take that into account that is generally applicable.
– Ingix
Nov 25 at 16:15
@Ingix What I need to do, then?
– good-to-know
Nov 27 at 13:11
@Ingix What I need to do, then?
– good-to-know
Nov 27 at 13:11
Describe what you want in your terms, and try not to use phrases like "perfectly averaged", which are not well defined. Include the background of the question (as I guessed at). Make a new question for this.
– Ingix
Nov 27 at 13:16
Describe what you want in your terms, and try not to use phrases like "perfectly averaged", which are not well defined. Include the background of the question (as I guessed at). Make a new question for this.
– Ingix
Nov 27 at 13:16
add a comment |
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Welcome to MSE. It will be more likely that you will get an answer if you show us that you made an effort. This should be added to the question rather than in the comments.
– José Carlos Santos
Nov 25 at 13:25
I agree. I quoted what I actually tried in the question itself.
– good-to-know
Nov 25 at 13:26
The problem is that you want an answer for a question that you have not given. What do you mean with "perfectly averaged"? What I guess is that your series' come from some kind of measurement (like school grades) and maybe you want to take into account that having an average score of 3.4 over 10 grades is more reliable than one of 3.5 over just 2 grades. But all of this information needs to come from you, there is no magical formula that will take that into account that is generally applicable.
– Ingix
Nov 25 at 16:15
@Ingix What I need to do, then?
– good-to-know
Nov 27 at 13:11
Describe what you want in your terms, and try not to use phrases like "perfectly averaged", which are not well defined. Include the background of the question (as I guessed at). Make a new question for this.
– Ingix
Nov 27 at 13:16