Integral involving Heaviside function in the exponential
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I need to compute the following integral in the real domain that involves the Heaviside step function $Theta(x)$:
$$
int_0^{infty} e^{- alpha_0Theta(x)- alpha_1 x} dx
$$
with $alpha_0, alpha_1$ two real constants.
Is there some useful representation of the Heaviside $Theta$ function that I can exploit to calculate the integral?
Or should I compute the integral using some complex plane technique?
calculus integration
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I need to compute the following integral in the real domain that involves the Heaviside step function $Theta(x)$:
$$
int_0^{infty} e^{- alpha_0Theta(x)- alpha_1 x} dx
$$
with $alpha_0, alpha_1$ two real constants.
Is there some useful representation of the Heaviside $Theta$ function that I can exploit to calculate the integral?
Or should I compute the integral using some complex plane technique?
calculus integration
1
Well, the step function is $+1$ on your entire domain of integration, so this is just $e^{-alpha_0} int_0^{infty} e^{-alpha_1 x} , dx$....
– T. Bongers
Nov 28 at 14:55
Yes, use the definition of that function.
– Yves Daoust
Nov 28 at 14:57
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
I need to compute the following integral in the real domain that involves the Heaviside step function $Theta(x)$:
$$
int_0^{infty} e^{- alpha_0Theta(x)- alpha_1 x} dx
$$
with $alpha_0, alpha_1$ two real constants.
Is there some useful representation of the Heaviside $Theta$ function that I can exploit to calculate the integral?
Or should I compute the integral using some complex plane technique?
calculus integration
I need to compute the following integral in the real domain that involves the Heaviside step function $Theta(x)$:
$$
int_0^{infty} e^{- alpha_0Theta(x)- alpha_1 x} dx
$$
with $alpha_0, alpha_1$ two real constants.
Is there some useful representation of the Heaviside $Theta$ function that I can exploit to calculate the integral?
Or should I compute the integral using some complex plane technique?
calculus integration
calculus integration
asked Nov 28 at 14:54
linello
17011
17011
1
Well, the step function is $+1$ on your entire domain of integration, so this is just $e^{-alpha_0} int_0^{infty} e^{-alpha_1 x} , dx$....
– T. Bongers
Nov 28 at 14:55
Yes, use the definition of that function.
– Yves Daoust
Nov 28 at 14:57
add a comment |
1
Well, the step function is $+1$ on your entire domain of integration, so this is just $e^{-alpha_0} int_0^{infty} e^{-alpha_1 x} , dx$....
– T. Bongers
Nov 28 at 14:55
Yes, use the definition of that function.
– Yves Daoust
Nov 28 at 14:57
1
1
Well, the step function is $+1$ on your entire domain of integration, so this is just $e^{-alpha_0} int_0^{infty} e^{-alpha_1 x} , dx$....
– T. Bongers
Nov 28 at 14:55
Well, the step function is $+1$ on your entire domain of integration, so this is just $e^{-alpha_0} int_0^{infty} e^{-alpha_1 x} , dx$....
– T. Bongers
Nov 28 at 14:55
Yes, use the definition of that function.
– Yves Daoust
Nov 28 at 14:57
Yes, use the definition of that function.
– Yves Daoust
Nov 28 at 14:57
add a comment |
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1
Well, the step function is $+1$ on your entire domain of integration, so this is just $e^{-alpha_0} int_0^{infty} e^{-alpha_1 x} , dx$....
– T. Bongers
Nov 28 at 14:55
Yes, use the definition of that function.
– Yves Daoust
Nov 28 at 14:57