Finding $(x,y)$ closest to $N$ points












1














Given $N$ points where the coordinates of the $i$th point are $(x_i,y_i)$ find $(x,y)$ that minimizes the following sum.
$$sum_{i=1}^ Nmax(|x-x_i|,|y-y_i|)$$
I've done a similar problem minimize
$$sum_{i=1}^ N(|x-x_i|+|y-y_i|)$$
Which I found that the minimum is achieved when we take $x$ as the median of $x_1,x_2,ldots,x_N$ and $y$ as median of $y_1,y_2,ldots,y_N$.



I'm stuck on the first one because I don't know how to manipulate the $max$.



Edit 1:




After tinkering with the suggestion below I am still struggling to make progress here: The $frac{|x-x_i|+|y-y_i|}{2}$ can be minimized by taking the median but I am not sure how to minimize the other part: $frac{||x|-|x_i||-||y|-|y_i||}{2}$. I also don't know what to do if I could minimize the other part. How can I minimize the sum of these two?











share|cite|improve this question




















  • 1




    Not a complete answer which finds an expression for the $(x,y)$. However, here is an identity that I think will probably get you where you want to go. $max{{a,b}} = frac{a+b}{2} + frac{|a-b|}{2}$
    – Mason
    yesterday










  • I hope I didn't rob you of more complete answers by putting something more worthy as a comment as an answer. Anyway: I put a suggested edit and deleted my answer to get this back on the list of unanswered questions+ an edit will bump this back on to active questions.
    – Mason
    yesterday










  • @Mason Nice of you to do that, I don't think you robbed me of an answer. I feel that the question isn't interesting to people and your observation is helpful.
    – kingW3
    yesterday
















1














Given $N$ points where the coordinates of the $i$th point are $(x_i,y_i)$ find $(x,y)$ that minimizes the following sum.
$$sum_{i=1}^ Nmax(|x-x_i|,|y-y_i|)$$
I've done a similar problem minimize
$$sum_{i=1}^ N(|x-x_i|+|y-y_i|)$$
Which I found that the minimum is achieved when we take $x$ as the median of $x_1,x_2,ldots,x_N$ and $y$ as median of $y_1,y_2,ldots,y_N$.



I'm stuck on the first one because I don't know how to manipulate the $max$.



Edit 1:




After tinkering with the suggestion below I am still struggling to make progress here: The $frac{|x-x_i|+|y-y_i|}{2}$ can be minimized by taking the median but I am not sure how to minimize the other part: $frac{||x|-|x_i||-||y|-|y_i||}{2}$. I also don't know what to do if I could minimize the other part. How can I minimize the sum of these two?











share|cite|improve this question




















  • 1




    Not a complete answer which finds an expression for the $(x,y)$. However, here is an identity that I think will probably get you where you want to go. $max{{a,b}} = frac{a+b}{2} + frac{|a-b|}{2}$
    – Mason
    yesterday










  • I hope I didn't rob you of more complete answers by putting something more worthy as a comment as an answer. Anyway: I put a suggested edit and deleted my answer to get this back on the list of unanswered questions+ an edit will bump this back on to active questions.
    – Mason
    yesterday










  • @Mason Nice of you to do that, I don't think you robbed me of an answer. I feel that the question isn't interesting to people and your observation is helpful.
    – kingW3
    yesterday














1












1








1


1





Given $N$ points where the coordinates of the $i$th point are $(x_i,y_i)$ find $(x,y)$ that minimizes the following sum.
$$sum_{i=1}^ Nmax(|x-x_i|,|y-y_i|)$$
I've done a similar problem minimize
$$sum_{i=1}^ N(|x-x_i|+|y-y_i|)$$
Which I found that the minimum is achieved when we take $x$ as the median of $x_1,x_2,ldots,x_N$ and $y$ as median of $y_1,y_2,ldots,y_N$.



I'm stuck on the first one because I don't know how to manipulate the $max$.



Edit 1:




After tinkering with the suggestion below I am still struggling to make progress here: The $frac{|x-x_i|+|y-y_i|}{2}$ can be minimized by taking the median but I am not sure how to minimize the other part: $frac{||x|-|x_i||-||y|-|y_i||}{2}$. I also don't know what to do if I could minimize the other part. How can I minimize the sum of these two?











share|cite|improve this question















Given $N$ points where the coordinates of the $i$th point are $(x_i,y_i)$ find $(x,y)$ that minimizes the following sum.
$$sum_{i=1}^ Nmax(|x-x_i|,|y-y_i|)$$
I've done a similar problem minimize
$$sum_{i=1}^ N(|x-x_i|+|y-y_i|)$$
Which I found that the minimum is achieved when we take $x$ as the median of $x_1,x_2,ldots,x_N$ and $y$ as median of $y_1,y_2,ldots,y_N$.



I'm stuck on the first one because I don't know how to manipulate the $max$.



Edit 1:




After tinkering with the suggestion below I am still struggling to make progress here: The $frac{|x-x_i|+|y-y_i|}{2}$ can be minimized by taking the median but I am not sure how to minimize the other part: $frac{||x|-|x_i||-||y|-|y_i||}{2}$. I also don't know what to do if I could minimize the other part. How can I minimize the sum of these two?








optimization algorithms






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share|cite|improve this question













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edited yesterday









Mason

1,8581529




1,8581529










asked Nov 30 at 17:36









kingW3

11k72554




11k72554








  • 1




    Not a complete answer which finds an expression for the $(x,y)$. However, here is an identity that I think will probably get you where you want to go. $max{{a,b}} = frac{a+b}{2} + frac{|a-b|}{2}$
    – Mason
    yesterday










  • I hope I didn't rob you of more complete answers by putting something more worthy as a comment as an answer. Anyway: I put a suggested edit and deleted my answer to get this back on the list of unanswered questions+ an edit will bump this back on to active questions.
    – Mason
    yesterday










  • @Mason Nice of you to do that, I don't think you robbed me of an answer. I feel that the question isn't interesting to people and your observation is helpful.
    – kingW3
    yesterday














  • 1




    Not a complete answer which finds an expression for the $(x,y)$. However, here is an identity that I think will probably get you where you want to go. $max{{a,b}} = frac{a+b}{2} + frac{|a-b|}{2}$
    – Mason
    yesterday










  • I hope I didn't rob you of more complete answers by putting something more worthy as a comment as an answer. Anyway: I put a suggested edit and deleted my answer to get this back on the list of unanswered questions+ an edit will bump this back on to active questions.
    – Mason
    yesterday










  • @Mason Nice of you to do that, I don't think you robbed me of an answer. I feel that the question isn't interesting to people and your observation is helpful.
    – kingW3
    yesterday








1




1




Not a complete answer which finds an expression for the $(x,y)$. However, here is an identity that I think will probably get you where you want to go. $max{{a,b}} = frac{a+b}{2} + frac{|a-b|}{2}$
– Mason
yesterday




Not a complete answer which finds an expression for the $(x,y)$. However, here is an identity that I think will probably get you where you want to go. $max{{a,b}} = frac{a+b}{2} + frac{|a-b|}{2}$
– Mason
yesterday












I hope I didn't rob you of more complete answers by putting something more worthy as a comment as an answer. Anyway: I put a suggested edit and deleted my answer to get this back on the list of unanswered questions+ an edit will bump this back on to active questions.
– Mason
yesterday




I hope I didn't rob you of more complete answers by putting something more worthy as a comment as an answer. Anyway: I put a suggested edit and deleted my answer to get this back on the list of unanswered questions+ an edit will bump this back on to active questions.
– Mason
yesterday












@Mason Nice of you to do that, I don't think you robbed me of an answer. I feel that the question isn't interesting to people and your observation is helpful.
– kingW3
yesterday




@Mason Nice of you to do that, I don't think you robbed me of an answer. I feel that the question isn't interesting to people and your observation is helpful.
– kingW3
yesterday















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