Htykuut

The question asks: Rewrite the character value example from the previous Try this to use a for-statement.

With that being said, what I wrote for the previous question was the following which runs fine as well:

#include "pch.h"

#include <iostream>

#include <string>

#include <vector>

#include <algorithm>

#include "cmath"



using namespace std;



int main()

{

    char letter = 'a';

    int i = 97;



    while (i < 123) {

        cout << letter << 't' << i << 'n';

        i = i + 1;

        letter = letter + 1;



      }

}

EDIT: After thinking about it overnight I made some changes:

int main()

{

    char letter = 'a';



    for (int i = 97; i < 123; i = i + 1)

        cout << letter << 't' << i << 'n';

        letter = letter + 1;

}

So this is still wrong, but I have gotten closer. I am having difficulty having the control variable on my char type count and line up with the int variable counter. What is it that I am doing wrong?

So what you are missing now is only the braces:

int main()

{

    char letter = 'a';



    for (int i = 97; i < 123; i = i + 1)

    {

        cout << letter << 't' << i << 'n';

        letter = letter + 1;

    }

}

All of these control structures expect a block of statements after it (e.g. if, else, for, while). A block of statements is enclosed in braces. However all of these controls also accept a single statement instead of a block of statements. So if there is no opening brace following the for(...) then only the next statement will be considered part of the loop iteration. But in your case you want both following statements to be executed in each loop iteration, so the braces are needed. It is good practice to always use the braces, even if only one statement is part of the loop body.

From your earlier version it seemed that you want to include both the i, as well as the letter as loop variables in your for loop. This is partially possible, but the individual statements must be in the matching section between the ;, e.g.:

int main()

{

    char letter = 'a';



    for (int i = 97; i < 123; i = i + 1, letter = letter + 1)

    {

        cout << letter << 't' << i << 'n';

    }

}

or

int main()

{

    char letter;

    int i;



    for (i = 97, letter='a'; i < 123; i = i + 1, letter = letter + 1)

    {

        cout << letter << 't' << i << 'n';

    }

}

However you cannot declare two variables of different type in one for statement.

Also besides the problem of the for loop: I don't have a reference for the exercise at hand, but is it really required to iterate both i and letter? It seems that you hold the ASCII integer representation of letter in i, so you can just iterate either i or letter, remove the other one, and cast appropriately in your output:

int main()

{

    for (int i = 97; i < 123; i = i + 1)

    {

        cout << static_cast<char>(i) << 't' << i << 'n';

    }

}

(Although it should be noted that this makes the assumption that the character set encoding is (a super-set of) ASCII, but I think in practice this is almost always true)