Developing a cross product of tensors within integrals











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I read in a book the following unproven statement:



$int_{s} utimes A n , ds = int_v ( utimes nablacdot A + mathcal{E}: A^T ) , dv$



with a: 1st order tensor, n: normal vector of s, A: 2nd order tensor, and $mathcal{E}$ the permutation 3rd order tensor.



I don't know much about properties to modify the left hand side cross product so I am trying to develop both sides using Einstein notation but I can't obtain the equality..



Any hint ?



EDIT: I am able to demonstrate the equation if I assume $frac{partial u_j}{partial x_j}$ is one, which makes sense if u is the position vector. Since this assumption is not mentioned in my book, I would like to know if there is another way ..



$ int_{partial v} left( utimes A n right)_i , ds = ... = int_{v} mathcal{E}_{ijk} left[ frac{partial u_j}{partial x_j }A_{kj} + u_jfrac{partial A_{kK}}{partial x_K} right] , dv $



and



$int_v left( utimes nablacdot A + mathcal{E}: A^T right)_i , dv = int_v mathcal{E}_{ijk} left[ u_jfrac{partial A_{kK}}{partial x_K} + A_{jk}^T right] , dv = int_v mathcal{E}_{ijk} left[ A_{kj} + u_j frac{partial A_{kK}}{partial x_K} right] , dv $










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    up vote
    0
    down vote

    favorite












    I read in a book the following unproven statement:



    $int_{s} utimes A n , ds = int_v ( utimes nablacdot A + mathcal{E}: A^T ) , dv$



    with a: 1st order tensor, n: normal vector of s, A: 2nd order tensor, and $mathcal{E}$ the permutation 3rd order tensor.



    I don't know much about properties to modify the left hand side cross product so I am trying to develop both sides using Einstein notation but I can't obtain the equality..



    Any hint ?



    EDIT: I am able to demonstrate the equation if I assume $frac{partial u_j}{partial x_j}$ is one, which makes sense if u is the position vector. Since this assumption is not mentioned in my book, I would like to know if there is another way ..



    $ int_{partial v} left( utimes A n right)_i , ds = ... = int_{v} mathcal{E}_{ijk} left[ frac{partial u_j}{partial x_j }A_{kj} + u_jfrac{partial A_{kK}}{partial x_K} right] , dv $



    and



    $int_v left( utimes nablacdot A + mathcal{E}: A^T right)_i , dv = int_v mathcal{E}_{ijk} left[ u_jfrac{partial A_{kK}}{partial x_K} + A_{jk}^T right] , dv = int_v mathcal{E}_{ijk} left[ A_{kj} + u_j frac{partial A_{kK}}{partial x_K} right] , dv $










    share|cite|improve this question


























      up vote
      0
      down vote

      favorite









      up vote
      0
      down vote

      favorite











      I read in a book the following unproven statement:



      $int_{s} utimes A n , ds = int_v ( utimes nablacdot A + mathcal{E}: A^T ) , dv$



      with a: 1st order tensor, n: normal vector of s, A: 2nd order tensor, and $mathcal{E}$ the permutation 3rd order tensor.



      I don't know much about properties to modify the left hand side cross product so I am trying to develop both sides using Einstein notation but I can't obtain the equality..



      Any hint ?



      EDIT: I am able to demonstrate the equation if I assume $frac{partial u_j}{partial x_j}$ is one, which makes sense if u is the position vector. Since this assumption is not mentioned in my book, I would like to know if there is another way ..



      $ int_{partial v} left( utimes A n right)_i , ds = ... = int_{v} mathcal{E}_{ijk} left[ frac{partial u_j}{partial x_j }A_{kj} + u_jfrac{partial A_{kK}}{partial x_K} right] , dv $



      and



      $int_v left( utimes nablacdot A + mathcal{E}: A^T right)_i , dv = int_v mathcal{E}_{ijk} left[ u_jfrac{partial A_{kK}}{partial x_K} + A_{jk}^T right] , dv = int_v mathcal{E}_{ijk} left[ A_{kj} + u_j frac{partial A_{kK}}{partial x_K} right] , dv $










      share|cite|improve this question















      I read in a book the following unproven statement:



      $int_{s} utimes A n , ds = int_v ( utimes nablacdot A + mathcal{E}: A^T ) , dv$



      with a: 1st order tensor, n: normal vector of s, A: 2nd order tensor, and $mathcal{E}$ the permutation 3rd order tensor.



      I don't know much about properties to modify the left hand side cross product so I am trying to develop both sides using Einstein notation but I can't obtain the equality..



      Any hint ?



      EDIT: I am able to demonstrate the equation if I assume $frac{partial u_j}{partial x_j}$ is one, which makes sense if u is the position vector. Since this assumption is not mentioned in my book, I would like to know if there is another way ..



      $ int_{partial v} left( utimes A n right)_i , ds = ... = int_{v} mathcal{E}_{ijk} left[ frac{partial u_j}{partial x_j }A_{kj} + u_jfrac{partial A_{kK}}{partial x_K} right] , dv $



      and



      $int_v left( utimes nablacdot A + mathcal{E}: A^T right)_i , dv = int_v mathcal{E}_{ijk} left[ u_jfrac{partial A_{kK}}{partial x_K} + A_{jk}^T right] , dv = int_v mathcal{E}_{ijk} left[ A_{kj} + u_j frac{partial A_{kK}}{partial x_K} right] , dv $







      integration tensor-products cross-product divergence gaussian-integral






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      edited Nov 23 at 16:44

























      asked Nov 23 at 15:52









      Thomas Di Giusto

      12




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