Let $T: Bbb R^n to Bbb R^n$ be a linear transformation which satisfies $T^2(v)=-v$ for all $vinBbb R^n$ then...











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Let $T: Bbb R^n to Bbb R^n$ be a linear transformation which satisfies $T^2(v)=-v$ for all $vinBbb R^n$ then $n$ is always even?










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    Let $T: Bbb R^n to Bbb R^n$ be a linear transformation which satisfies $T^2(v)=-v$ for all $vinBbb R^n$ then $n$ is always even?










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      Let $T: Bbb R^n to Bbb R^n$ be a linear transformation which satisfies $T^2(v)=-v$ for all $vinBbb R^n$ then $n$ is always even?










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      Let $T: Bbb R^n to Bbb R^n$ be a linear transformation which satisfies $T^2(v)=-v$ for all $vinBbb R^n$ then $n$ is always even?







      abstract-algebra






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      edited Nov 23 at 15:37









      David C. Ullrich

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      57.3k43791










      asked Nov 23 at 15:30









      Muskan khanam

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          Yes. Hint: If $p$ is a polynomial with real coefficients and $p$ has odd degree then there exists $xinBbb R$ with $p(x)=0$.






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            up vote
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            down vote













            Yes. Hint: If $p$ is a polynomial with real coefficients and $p$ has odd degree then there exists $xinBbb R$ with $p(x)=0$.






            share|cite|improve this answer

























              up vote
              -1
              down vote













              Yes. Hint: If $p$ is a polynomial with real coefficients and $p$ has odd degree then there exists $xinBbb R$ with $p(x)=0$.






              share|cite|improve this answer























                up vote
                -1
                down vote










                up vote
                -1
                down vote









                Yes. Hint: If $p$ is a polynomial with real coefficients and $p$ has odd degree then there exists $xinBbb R$ with $p(x)=0$.






                share|cite|improve this answer












                Yes. Hint: If $p$ is a polynomial with real coefficients and $p$ has odd degree then there exists $xinBbb R$ with $p(x)=0$.







                share|cite|improve this answer












                share|cite|improve this answer



                share|cite|improve this answer










                answered Nov 23 at 15:39









                David C. Ullrich

                57.3k43791




                57.3k43791






























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