I am not able to access data as per POJO class
up vote
-2
down vote
favorite
Hi I have following json response, I am not able to access data of 'edit' jsonobject, how to create pojo for that?
Example
{
"result":"",
"responseMessage":"",
"edit":{
"id":"156",
"user_id":"5466",
},
"data":[
{
"dataid":"1",
"dataname":"tt"
},
{
"dataid":"2",
"dataname":"tt"
}
]
}
How to create pojo class for this response
android getter-setter pojo
add a comment |
up vote
-2
down vote
favorite
Hi I have following json response, I am not able to access data of 'edit' jsonobject, how to create pojo for that?
Example
{
"result":"",
"responseMessage":"",
"edit":{
"id":"156",
"user_id":"5466",
},
"data":[
{
"dataid":"1",
"dataname":"tt"
},
{
"dataid":"2",
"dataname":"tt"
}
]
}
How to create pojo class for this response
android getter-setter pojo
1
Please post the code you have so far so we can best help you.
– Sub 6 Resources
Nov 22 at 5:33
2
if you are having trouble creating pojo class by your own use this website jsonschema2pojo
– Kevin Kurien
Nov 22 at 5:34
@Sub6Resources just help me with pojo class, i have created one but can you tell how to access data of edit json object.
– Nilima
Nov 22 at 5:35
Always use JsonValidator for checking that your json is valid or not.
– Piyush
Nov 22 at 5:54
1
Possible duplicate of How do I parse JSON in Android?
– Vladyslav Matviienko
Nov 22 at 6:16
add a comment |
up vote
-2
down vote
favorite
up vote
-2
down vote
favorite
Hi I have following json response, I am not able to access data of 'edit' jsonobject, how to create pojo for that?
Example
{
"result":"",
"responseMessage":"",
"edit":{
"id":"156",
"user_id":"5466",
},
"data":[
{
"dataid":"1",
"dataname":"tt"
},
{
"dataid":"2",
"dataname":"tt"
}
]
}
How to create pojo class for this response
android getter-setter pojo
Hi I have following json response, I am not able to access data of 'edit' jsonobject, how to create pojo for that?
Example
{
"result":"",
"responseMessage":"",
"edit":{
"id":"156",
"user_id":"5466",
},
"data":[
{
"dataid":"1",
"dataname":"tt"
},
{
"dataid":"2",
"dataname":"tt"
}
]
}
How to create pojo class for this response
android getter-setter pojo
android getter-setter pojo
edited Nov 22 at 10:56
AwaisMajeed
657219
657219
asked Nov 22 at 5:29
Nilima
307
307
1
Please post the code you have so far so we can best help you.
– Sub 6 Resources
Nov 22 at 5:33
2
if you are having trouble creating pojo class by your own use this website jsonschema2pojo
– Kevin Kurien
Nov 22 at 5:34
@Sub6Resources just help me with pojo class, i have created one but can you tell how to access data of edit json object.
– Nilima
Nov 22 at 5:35
Always use JsonValidator for checking that your json is valid or not.
– Piyush
Nov 22 at 5:54
1
Possible duplicate of How do I parse JSON in Android?
– Vladyslav Matviienko
Nov 22 at 6:16
add a comment |
1
Please post the code you have so far so we can best help you.
– Sub 6 Resources
Nov 22 at 5:33
2
if you are having trouble creating pojo class by your own use this website jsonschema2pojo
– Kevin Kurien
Nov 22 at 5:34
@Sub6Resources just help me with pojo class, i have created one but can you tell how to access data of edit json object.
– Nilima
Nov 22 at 5:35
Always use JsonValidator for checking that your json is valid or not.
– Piyush
Nov 22 at 5:54
1
Possible duplicate of How do I parse JSON in Android?
– Vladyslav Matviienko
Nov 22 at 6:16
1
1
Please post the code you have so far so we can best help you.
– Sub 6 Resources
Nov 22 at 5:33
Please post the code you have so far so we can best help you.
– Sub 6 Resources
Nov 22 at 5:33
2
2
if you are having trouble creating pojo class by your own use this website jsonschema2pojo
– Kevin Kurien
Nov 22 at 5:34
if you are having trouble creating pojo class by your own use this website jsonschema2pojo
– Kevin Kurien
Nov 22 at 5:34
@Sub6Resources just help me with pojo class, i have created one but can you tell how to access data of edit json object.
– Nilima
Nov 22 at 5:35
@Sub6Resources just help me with pojo class, i have created one but can you tell how to access data of edit json object.
– Nilima
Nov 22 at 5:35
Always use JsonValidator for checking that your json is valid or not.
– Piyush
Nov 22 at 5:54
Always use JsonValidator for checking that your json is valid or not.
– Piyush
Nov 22 at 5:54
1
1
Possible duplicate of How do I parse JSON in Android?
– Vladyslav Matviienko
Nov 22 at 6:16
Possible duplicate of How do I parse JSON in Android?
– Vladyslav Matviienko
Nov 22 at 6:16
add a comment |
3 Answers
3
active
oldest
votes
up vote
1
down vote
accepted
You can use this link to create POJO classes for your JSON in future. However your JSON is also not valid, it contains an extra , in your edit object.
"edit":{
"id":"156",
"user_id":"5466",<--This comma
}
add a comment |
up vote
1
down vote
your Json is incorrect. There is an extra "," inside edit object. Remove that and try accessing data of edit
Still if you are unable to access, I am attaching following POJO for you to use.
public class ExPojo
{
private String responseMessage;
private String result;
private Data data;
private Edit edit;
public String getResponseMessage ()
{
return responseMessage;
}
public void setResponseMessage (String responseMessage)
{
this.responseMessage = responseMessage;
}
public String getResult ()
{
return result;
}
public void setResult (String result)
{
this.result = result;
}
public Data getData ()
{
return data;
}
public void setData (Data data)
{
this.data = data;
}
public Edit getEdit ()
{
return edit;
}
public void setEdit (Edit edit)
{
this.edit = edit;
}
@Override
public String toString()
{
return "ClassPojo [responseMessage = "+responseMessage+", result = "+result+", data = "+data+", edit = "+edit+"]";
}
}
Hope this helps.
It is generally bad to do other people's work instead of them. It makes people even more lazy. Please don't.
– Vladyslav Matviienko
Nov 22 at 6:09
thanks for help +1. and I am getting price like 1.000000 and i want to display 1. how to do that
– Nilima
Nov 22 at 9:23
you can just cast that value to int like, (int) price
– Chandrani Chatterjee
Nov 22 at 12:08
add a comment |
up vote
-1
down vote
make pojo class like this way..
public class DataItem{
@SerializedName("dataid")
private String dataid;
@SerializedName("dataname")
private String dataname;
public void setDataid(String dataid){
this.dataid = dataid;
}
public String getDataid(){
return dataid;
}
public void setDataname(String dataname){
this.dataname = dataname;
}
public String getDataname(){
return dataname;
}
@Override
public String toString(){
return
"DataItem{" +
"dataid = '" + dataid + ''' +
",dataname = '" + dataname + ''' +
"}";
}
}
public class Edit{
@SerializedName("user_id")
private String userId;
@SerializedName("id")
private String id;
public void setUserId(String userId){
this.userId = userId;
}
public String getUserId(){
return userId;
}
public void setId(String id){
this.id = id;
}
public String getId(){
return id;
}
@Override
public String toString(){
return
"Edit{" +
"user_id = '" + userId + ''' +
",id = '" + id + ''' +
"}";
}
}
public class Response{
@SerializedName("result")
private String result;
@SerializedName("data")
private List<DataItem> data;
@SerializedName("edit")
private Edit edit;
@SerializedName("responseMessage")
private String responseMessage;
public void setResult(String result){
this.result = result;
}
public String getResult(){
return result;
}
public void setData(List<DataItem> data){
this.data = data;
}
public List<DataItem> getData(){
return data;
}
public void setEdit(Edit edit){
this.edit = edit;
}
public Edit getEdit(){
return edit;
}
public void setResponseMessage(String responseMessage){
this.responseMessage = responseMessage;
}
public String getResponseMessage(){
return responseMessage;
}
@Override
public String toString(){
return
"Response{" +
"result = '" + result + ''' +
",data = '" + data + ''' +
",edit = '" + edit + ''' +
",responseMessage = '" + responseMessage + ''' +
"}";
}
}
Generate pojo class used Robopojo plugin.
It is generally bad to do other people's work instead of them. It makes people even more lazy. Please don't.
– Vladyslav Matviienko
Nov 22 at 6:09
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53424414%2fi-am-not-able-to-access-data-as-per-pojo-class%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
1
down vote
accepted
You can use this link to create POJO classes for your JSON in future. However your JSON is also not valid, it contains an extra , in your edit object.
"edit":{
"id":"156",
"user_id":"5466",<--This comma
}
add a comment |
up vote
1
down vote
accepted
You can use this link to create POJO classes for your JSON in future. However your JSON is also not valid, it contains an extra , in your edit object.
"edit":{
"id":"156",
"user_id":"5466",<--This comma
}
add a comment |
up vote
1
down vote
accepted
up vote
1
down vote
accepted
You can use this link to create POJO classes for your JSON in future. However your JSON is also not valid, it contains an extra , in your edit object.
"edit":{
"id":"156",
"user_id":"5466",<--This comma
}
You can use this link to create POJO classes for your JSON in future. However your JSON is also not valid, it contains an extra , in your edit object.
"edit":{
"id":"156",
"user_id":"5466",<--This comma
}
answered Nov 22 at 5:41
AwaisMajeed
657219
657219
add a comment |
add a comment |
up vote
1
down vote
your Json is incorrect. There is an extra "," inside edit object. Remove that and try accessing data of edit
Still if you are unable to access, I am attaching following POJO for you to use.
public class ExPojo
{
private String responseMessage;
private String result;
private Data data;
private Edit edit;
public String getResponseMessage ()
{
return responseMessage;
}
public void setResponseMessage (String responseMessage)
{
this.responseMessage = responseMessage;
}
public String getResult ()
{
return result;
}
public void setResult (String result)
{
this.result = result;
}
public Data getData ()
{
return data;
}
public void setData (Data data)
{
this.data = data;
}
public Edit getEdit ()
{
return edit;
}
public void setEdit (Edit edit)
{
this.edit = edit;
}
@Override
public String toString()
{
return "ClassPojo [responseMessage = "+responseMessage+", result = "+result+", data = "+data+", edit = "+edit+"]";
}
}
Hope this helps.
It is generally bad to do other people's work instead of them. It makes people even more lazy. Please don't.
– Vladyslav Matviienko
Nov 22 at 6:09
thanks for help +1. and I am getting price like 1.000000 and i want to display 1. how to do that
– Nilima
Nov 22 at 9:23
you can just cast that value to int like, (int) price
– Chandrani Chatterjee
Nov 22 at 12:08
add a comment |
up vote
1
down vote
your Json is incorrect. There is an extra "," inside edit object. Remove that and try accessing data of edit
Still if you are unable to access, I am attaching following POJO for you to use.
public class ExPojo
{
private String responseMessage;
private String result;
private Data data;
private Edit edit;
public String getResponseMessage ()
{
return responseMessage;
}
public void setResponseMessage (String responseMessage)
{
this.responseMessage = responseMessage;
}
public String getResult ()
{
return result;
}
public void setResult (String result)
{
this.result = result;
}
public Data getData ()
{
return data;
}
public void setData (Data data)
{
this.data = data;
}
public Edit getEdit ()
{
return edit;
}
public void setEdit (Edit edit)
{
this.edit = edit;
}
@Override
public String toString()
{
return "ClassPojo [responseMessage = "+responseMessage+", result = "+result+", data = "+data+", edit = "+edit+"]";
}
}
Hope this helps.
It is generally bad to do other people's work instead of them. It makes people even more lazy. Please don't.
– Vladyslav Matviienko
Nov 22 at 6:09
thanks for help +1. and I am getting price like 1.000000 and i want to display 1. how to do that
– Nilima
Nov 22 at 9:23
you can just cast that value to int like, (int) price
– Chandrani Chatterjee
Nov 22 at 12:08
add a comment |
up vote
1
down vote
up vote
1
down vote
your Json is incorrect. There is an extra "," inside edit object. Remove that and try accessing data of edit
Still if you are unable to access, I am attaching following POJO for you to use.
public class ExPojo
{
private String responseMessage;
private String result;
private Data data;
private Edit edit;
public String getResponseMessage ()
{
return responseMessage;
}
public void setResponseMessage (String responseMessage)
{
this.responseMessage = responseMessage;
}
public String getResult ()
{
return result;
}
public void setResult (String result)
{
this.result = result;
}
public Data getData ()
{
return data;
}
public void setData (Data data)
{
this.data = data;
}
public Edit getEdit ()
{
return edit;
}
public void setEdit (Edit edit)
{
this.edit = edit;
}
@Override
public String toString()
{
return "ClassPojo [responseMessage = "+responseMessage+", result = "+result+", data = "+data+", edit = "+edit+"]";
}
}
Hope this helps.
your Json is incorrect. There is an extra "," inside edit object. Remove that and try accessing data of edit
Still if you are unable to access, I am attaching following POJO for you to use.
public class ExPojo
{
private String responseMessage;
private String result;
private Data data;
private Edit edit;
public String getResponseMessage ()
{
return responseMessage;
}
public void setResponseMessage (String responseMessage)
{
this.responseMessage = responseMessage;
}
public String getResult ()
{
return result;
}
public void setResult (String result)
{
this.result = result;
}
public Data getData ()
{
return data;
}
public void setData (Data data)
{
this.data = data;
}
public Edit getEdit ()
{
return edit;
}
public void setEdit (Edit edit)
{
this.edit = edit;
}
@Override
public String toString()
{
return "ClassPojo [responseMessage = "+responseMessage+", result = "+result+", data = "+data+", edit = "+edit+"]";
}
}
Hope this helps.
answered Nov 22 at 5:37
Chandrani Chatterjee
309215
309215
It is generally bad to do other people's work instead of them. It makes people even more lazy. Please don't.
– Vladyslav Matviienko
Nov 22 at 6:09
thanks for help +1. and I am getting price like 1.000000 and i want to display 1. how to do that
– Nilima
Nov 22 at 9:23
you can just cast that value to int like, (int) price
– Chandrani Chatterjee
Nov 22 at 12:08
add a comment |
It is generally bad to do other people's work instead of them. It makes people even more lazy. Please don't.
– Vladyslav Matviienko
Nov 22 at 6:09
thanks for help +1. and I am getting price like 1.000000 and i want to display 1. how to do that
– Nilima
Nov 22 at 9:23
you can just cast that value to int like, (int) price
– Chandrani Chatterjee
Nov 22 at 12:08
It is generally bad to do other people's work instead of them. It makes people even more lazy. Please don't.
– Vladyslav Matviienko
Nov 22 at 6:09
It is generally bad to do other people's work instead of them. It makes people even more lazy. Please don't.
– Vladyslav Matviienko
Nov 22 at 6:09
thanks for help +1. and I am getting price like 1.000000 and i want to display 1. how to do that
– Nilima
Nov 22 at 9:23
thanks for help +1. and I am getting price like 1.000000 and i want to display 1. how to do that
– Nilima
Nov 22 at 9:23
you can just cast that value to int like, (int) price
– Chandrani Chatterjee
Nov 22 at 12:08
you can just cast that value to int like, (int) price
– Chandrani Chatterjee
Nov 22 at 12:08
add a comment |
up vote
-1
down vote
make pojo class like this way..
public class DataItem{
@SerializedName("dataid")
private String dataid;
@SerializedName("dataname")
private String dataname;
public void setDataid(String dataid){
this.dataid = dataid;
}
public String getDataid(){
return dataid;
}
public void setDataname(String dataname){
this.dataname = dataname;
}
public String getDataname(){
return dataname;
}
@Override
public String toString(){
return
"DataItem{" +
"dataid = '" + dataid + ''' +
",dataname = '" + dataname + ''' +
"}";
}
}
public class Edit{
@SerializedName("user_id")
private String userId;
@SerializedName("id")
private String id;
public void setUserId(String userId){
this.userId = userId;
}
public String getUserId(){
return userId;
}
public void setId(String id){
this.id = id;
}
public String getId(){
return id;
}
@Override
public String toString(){
return
"Edit{" +
"user_id = '" + userId + ''' +
",id = '" + id + ''' +
"}";
}
}
public class Response{
@SerializedName("result")
private String result;
@SerializedName("data")
private List<DataItem> data;
@SerializedName("edit")
private Edit edit;
@SerializedName("responseMessage")
private String responseMessage;
public void setResult(String result){
this.result = result;
}
public String getResult(){
return result;
}
public void setData(List<DataItem> data){
this.data = data;
}
public List<DataItem> getData(){
return data;
}
public void setEdit(Edit edit){
this.edit = edit;
}
public Edit getEdit(){
return edit;
}
public void setResponseMessage(String responseMessage){
this.responseMessage = responseMessage;
}
public String getResponseMessage(){
return responseMessage;
}
@Override
public String toString(){
return
"Response{" +
"result = '" + result + ''' +
",data = '" + data + ''' +
",edit = '" + edit + ''' +
",responseMessage = '" + responseMessage + ''' +
"}";
}
}
Generate pojo class used Robopojo plugin.
It is generally bad to do other people's work instead of them. It makes people even more lazy. Please don't.
– Vladyslav Matviienko
Nov 22 at 6:09
add a comment |
up vote
-1
down vote
make pojo class like this way..
public class DataItem{
@SerializedName("dataid")
private String dataid;
@SerializedName("dataname")
private String dataname;
public void setDataid(String dataid){
this.dataid = dataid;
}
public String getDataid(){
return dataid;
}
public void setDataname(String dataname){
this.dataname = dataname;
}
public String getDataname(){
return dataname;
}
@Override
public String toString(){
return
"DataItem{" +
"dataid = '" + dataid + ''' +
",dataname = '" + dataname + ''' +
"}";
}
}
public class Edit{
@SerializedName("user_id")
private String userId;
@SerializedName("id")
private String id;
public void setUserId(String userId){
this.userId = userId;
}
public String getUserId(){
return userId;
}
public void setId(String id){
this.id = id;
}
public String getId(){
return id;
}
@Override
public String toString(){
return
"Edit{" +
"user_id = '" + userId + ''' +
",id = '" + id + ''' +
"}";
}
}
public class Response{
@SerializedName("result")
private String result;
@SerializedName("data")
private List<DataItem> data;
@SerializedName("edit")
private Edit edit;
@SerializedName("responseMessage")
private String responseMessage;
public void setResult(String result){
this.result = result;
}
public String getResult(){
return result;
}
public void setData(List<DataItem> data){
this.data = data;
}
public List<DataItem> getData(){
return data;
}
public void setEdit(Edit edit){
this.edit = edit;
}
public Edit getEdit(){
return edit;
}
public void setResponseMessage(String responseMessage){
this.responseMessage = responseMessage;
}
public String getResponseMessage(){
return responseMessage;
}
@Override
public String toString(){
return
"Response{" +
"result = '" + result + ''' +
",data = '" + data + ''' +
",edit = '" + edit + ''' +
",responseMessage = '" + responseMessage + ''' +
"}";
}
}
Generate pojo class used Robopojo plugin.
It is generally bad to do other people's work instead of them. It makes people even more lazy. Please don't.
– Vladyslav Matviienko
Nov 22 at 6:09
add a comment |
up vote
-1
down vote
up vote
-1
down vote
make pojo class like this way..
public class DataItem{
@SerializedName("dataid")
private String dataid;
@SerializedName("dataname")
private String dataname;
public void setDataid(String dataid){
this.dataid = dataid;
}
public String getDataid(){
return dataid;
}
public void setDataname(String dataname){
this.dataname = dataname;
}
public String getDataname(){
return dataname;
}
@Override
public String toString(){
return
"DataItem{" +
"dataid = '" + dataid + ''' +
",dataname = '" + dataname + ''' +
"}";
}
}
public class Edit{
@SerializedName("user_id")
private String userId;
@SerializedName("id")
private String id;
public void setUserId(String userId){
this.userId = userId;
}
public String getUserId(){
return userId;
}
public void setId(String id){
this.id = id;
}
public String getId(){
return id;
}
@Override
public String toString(){
return
"Edit{" +
"user_id = '" + userId + ''' +
",id = '" + id + ''' +
"}";
}
}
public class Response{
@SerializedName("result")
private String result;
@SerializedName("data")
private List<DataItem> data;
@SerializedName("edit")
private Edit edit;
@SerializedName("responseMessage")
private String responseMessage;
public void setResult(String result){
this.result = result;
}
public String getResult(){
return result;
}
public void setData(List<DataItem> data){
this.data = data;
}
public List<DataItem> getData(){
return data;
}
public void setEdit(Edit edit){
this.edit = edit;
}
public Edit getEdit(){
return edit;
}
public void setResponseMessage(String responseMessage){
this.responseMessage = responseMessage;
}
public String getResponseMessage(){
return responseMessage;
}
@Override
public String toString(){
return
"Response{" +
"result = '" + result + ''' +
",data = '" + data + ''' +
",edit = '" + edit + ''' +
",responseMessage = '" + responseMessage + ''' +
"}";
}
}
Generate pojo class used Robopojo plugin.
make pojo class like this way..
public class DataItem{
@SerializedName("dataid")
private String dataid;
@SerializedName("dataname")
private String dataname;
public void setDataid(String dataid){
this.dataid = dataid;
}
public String getDataid(){
return dataid;
}
public void setDataname(String dataname){
this.dataname = dataname;
}
public String getDataname(){
return dataname;
}
@Override
public String toString(){
return
"DataItem{" +
"dataid = '" + dataid + ''' +
",dataname = '" + dataname + ''' +
"}";
}
}
public class Edit{
@SerializedName("user_id")
private String userId;
@SerializedName("id")
private String id;
public void setUserId(String userId){
this.userId = userId;
}
public String getUserId(){
return userId;
}
public void setId(String id){
this.id = id;
}
public String getId(){
return id;
}
@Override
public String toString(){
return
"Edit{" +
"user_id = '" + userId + ''' +
",id = '" + id + ''' +
"}";
}
}
public class Response{
@SerializedName("result")
private String result;
@SerializedName("data")
private List<DataItem> data;
@SerializedName("edit")
private Edit edit;
@SerializedName("responseMessage")
private String responseMessage;
public void setResult(String result){
this.result = result;
}
public String getResult(){
return result;
}
public void setData(List<DataItem> data){
this.data = data;
}
public List<DataItem> getData(){
return data;
}
public void setEdit(Edit edit){
this.edit = edit;
}
public Edit getEdit(){
return edit;
}
public void setResponseMessage(String responseMessage){
this.responseMessage = responseMessage;
}
public String getResponseMessage(){
return responseMessage;
}
@Override
public String toString(){
return
"Response{" +
"result = '" + result + ''' +
",data = '" + data + ''' +
",edit = '" + edit + ''' +
",responseMessage = '" + responseMessage + ''' +
"}";
}
}
Generate pojo class used Robopojo plugin.
answered Nov 22 at 5:37
Android Team
7,45811033
7,45811033
It is generally bad to do other people's work instead of them. It makes people even more lazy. Please don't.
– Vladyslav Matviienko
Nov 22 at 6:09
add a comment |
It is generally bad to do other people's work instead of them. It makes people even more lazy. Please don't.
– Vladyslav Matviienko
Nov 22 at 6:09
It is generally bad to do other people's work instead of them. It makes people even more lazy. Please don't.
– Vladyslav Matviienko
Nov 22 at 6:09
It is generally bad to do other people's work instead of them. It makes people even more lazy. Please don't.
– Vladyslav Matviienko
Nov 22 at 6:09
add a comment |
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Some of your past answers have not been well-received, and you're in danger of being blocked from answering.
Please pay close attention to the following guidance:
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53424414%2fi-am-not-able-to-access-data-as-per-pojo-class%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
1
Please post the code you have so far so we can best help you.
– Sub 6 Resources
Nov 22 at 5:33
2
if you are having trouble creating pojo class by your own use this website jsonschema2pojo
– Kevin Kurien
Nov 22 at 5:34
@Sub6Resources just help me with pojo class, i have created one but can you tell how to access data of edit json object.
– Nilima
Nov 22 at 5:35
Always use JsonValidator for checking that your json is valid or not.
– Piyush
Nov 22 at 5:54
1
Possible duplicate of How do I parse JSON in Android?
– Vladyslav Matviienko
Nov 22 at 6:16