How to compute a multivariable integral [on hold]












-1














How to compute the integral $int_{mathbb{R}^3} exp(-sqrt{1+|p|^2}) dp$, where $p in mathbb{R}^3$?










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put on hold as off-topic by Jyrki Lahtonen, Brahadeesh, Saad, Tianlalu, José Carlos Santos 2 days ago


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Jyrki Lahtonen, Brahadeesh, Saad, Tianlalu, José Carlos Santos

If this question can be reworded to fit the rules in the help center, please edit the question.









  • 2




    Is it a line integral? Can you provide more information. In general the function exp(f(p)) has no anti derivative if f(p) is not linear.
    – Ameryr
    Nov 30 at 16:42










  • And exp(f(p)) has an anti derivative if also f(p) = ln(g(p)) for some g(p).
    – Ameryr
    Nov 30 at 16:49










  • Did you try substitution with spherical coordinates? Show some work! Also, what exactly are you looking for? Do you need or expect an algebraic solution or would a numerical method be enough?
    – Mefitico
    Nov 30 at 16:50










  • this is a triple generalized integral
    – Bloodpolyhydron
    Dec 1 at 5:21










  • so I think it can not use spherical coordinate to substitude
    – Bloodpolyhydron
    Dec 1 at 5:23
















-1














How to compute the integral $int_{mathbb{R}^3} exp(-sqrt{1+|p|^2}) dp$, where $p in mathbb{R}^3$?










share|cite|improve this question















put on hold as off-topic by Jyrki Lahtonen, Brahadeesh, Saad, Tianlalu, José Carlos Santos 2 days ago


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Jyrki Lahtonen, Brahadeesh, Saad, Tianlalu, José Carlos Santos

If this question can be reworded to fit the rules in the help center, please edit the question.









  • 2




    Is it a line integral? Can you provide more information. In general the function exp(f(p)) has no anti derivative if f(p) is not linear.
    – Ameryr
    Nov 30 at 16:42










  • And exp(f(p)) has an anti derivative if also f(p) = ln(g(p)) for some g(p).
    – Ameryr
    Nov 30 at 16:49










  • Did you try substitution with spherical coordinates? Show some work! Also, what exactly are you looking for? Do you need or expect an algebraic solution or would a numerical method be enough?
    – Mefitico
    Nov 30 at 16:50










  • this is a triple generalized integral
    – Bloodpolyhydron
    Dec 1 at 5:21










  • so I think it can not use spherical coordinate to substitude
    – Bloodpolyhydron
    Dec 1 at 5:23














-1












-1








-1







How to compute the integral $int_{mathbb{R}^3} exp(-sqrt{1+|p|^2}) dp$, where $p in mathbb{R}^3$?










share|cite|improve this question















How to compute the integral $int_{mathbb{R}^3} exp(-sqrt{1+|p|^2}) dp$, where $p in mathbb{R}^3$?







multivariable-calculus






share|cite|improve this question















share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited 2 days ago









Robert Z

93.1k1060131




93.1k1060131










asked Nov 30 at 16:37









Bloodpolyhydron

71




71




put on hold as off-topic by Jyrki Lahtonen, Brahadeesh, Saad, Tianlalu, José Carlos Santos 2 days ago


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Jyrki Lahtonen, Brahadeesh, Saad, Tianlalu, José Carlos Santos

If this question can be reworded to fit the rules in the help center, please edit the question.




put on hold as off-topic by Jyrki Lahtonen, Brahadeesh, Saad, Tianlalu, José Carlos Santos 2 days ago


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Jyrki Lahtonen, Brahadeesh, Saad, Tianlalu, José Carlos Santos

If this question can be reworded to fit the rules in the help center, please edit the question.








  • 2




    Is it a line integral? Can you provide more information. In general the function exp(f(p)) has no anti derivative if f(p) is not linear.
    – Ameryr
    Nov 30 at 16:42










  • And exp(f(p)) has an anti derivative if also f(p) = ln(g(p)) for some g(p).
    – Ameryr
    Nov 30 at 16:49










  • Did you try substitution with spherical coordinates? Show some work! Also, what exactly are you looking for? Do you need or expect an algebraic solution or would a numerical method be enough?
    – Mefitico
    Nov 30 at 16:50










  • this is a triple generalized integral
    – Bloodpolyhydron
    Dec 1 at 5:21










  • so I think it can not use spherical coordinate to substitude
    – Bloodpolyhydron
    Dec 1 at 5:23














  • 2




    Is it a line integral? Can you provide more information. In general the function exp(f(p)) has no anti derivative if f(p) is not linear.
    – Ameryr
    Nov 30 at 16:42










  • And exp(f(p)) has an anti derivative if also f(p) = ln(g(p)) for some g(p).
    – Ameryr
    Nov 30 at 16:49










  • Did you try substitution with spherical coordinates? Show some work! Also, what exactly are you looking for? Do you need or expect an algebraic solution or would a numerical method be enough?
    – Mefitico
    Nov 30 at 16:50










  • this is a triple generalized integral
    – Bloodpolyhydron
    Dec 1 at 5:21










  • so I think it can not use spherical coordinate to substitude
    – Bloodpolyhydron
    Dec 1 at 5:23








2




2




Is it a line integral? Can you provide more information. In general the function exp(f(p)) has no anti derivative if f(p) is not linear.
– Ameryr
Nov 30 at 16:42




Is it a line integral? Can you provide more information. In general the function exp(f(p)) has no anti derivative if f(p) is not linear.
– Ameryr
Nov 30 at 16:42












And exp(f(p)) has an anti derivative if also f(p) = ln(g(p)) for some g(p).
– Ameryr
Nov 30 at 16:49




And exp(f(p)) has an anti derivative if also f(p) = ln(g(p)) for some g(p).
– Ameryr
Nov 30 at 16:49












Did you try substitution with spherical coordinates? Show some work! Also, what exactly are you looking for? Do you need or expect an algebraic solution or would a numerical method be enough?
– Mefitico
Nov 30 at 16:50




Did you try substitution with spherical coordinates? Show some work! Also, what exactly are you looking for? Do you need or expect an algebraic solution or would a numerical method be enough?
– Mefitico
Nov 30 at 16:50












this is a triple generalized integral
– Bloodpolyhydron
Dec 1 at 5:21




this is a triple generalized integral
– Bloodpolyhydron
Dec 1 at 5:21












so I think it can not use spherical coordinate to substitude
– Bloodpolyhydron
Dec 1 at 5:23




so I think it can not use spherical coordinate to substitude
– Bloodpolyhydron
Dec 1 at 5:23















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