Htykuut

I have a dataframe and I try to get string, where on of column contain some string
Df looks like

member_id,event_path,event_time,event_duration

30595,"2016-03-30 12:27:33",yandex.ru/,1

30595,"2016-03-30 12:31:42",yandex.ru/,0

30595,"2016-03-30 12:31:43",yandex.ru/search/?lr=10738&msid=22901.25826.1459330364.89548&text=%D1%84%D0%B8%D0%BB%D1%8C%D0%BC%D1%8B+%D0%BE%D0%BD%D0%BB%D0%B0%D0%B9%D0%BD&suggest_reqid=168542624144922467267026838391360&csg=3381%2C3938%2C2%2C3%2C1%2C0%2C0,0

30595,"2016-03-30 12:31:44",yandex.ru/search/?lr=10738&msid=22901.25826.1459330364.89548&text=%D1%84%D0%B8%D0%BB%D1%8C%D0%BC%D1%8B+%D0%BE%D0%BD%D0%BB%D0%B0%D0%B9%D0%BD&suggest_reqid=168542624144922467267026838391360&csg=3381%2C3938%2C2%2C3%2C1%2C0%2C0,0

30595,"2016-03-30 12:31:45",yandex.ru/search/?lr=10738&msid=22901.25826.1459330364.89548&text=%D1%84%D0%B8%D0%BB%D1%8C%D0%BC%D1%8B+%D0%BE%D0%BD%D0%BB%D0%B0%D0%B9%D0%BD&suggest_reqid=168542624144922467267026838391360&csg=3381%2C3938%2C2%2C3%2C1%2C0%2C0,0

30595,"2016-03-30 12:31:46",yandex.ru/search/?lr=10738&msid=22901.25826.1459330364.89548&text=%D1%84%D0%B8%D0%BB%D1%8C%D0%BC%D1%8B+%D0%BE%D0%BD%D0%BB%D0%B0%D0%B9%D0%BD&suggest_reqid=168542624144922467267026838391360&csg=3381%2C3938%2C2%2C3%2C1%2C0%2C0,0

30595,"2016-03-30 12:31:49",kinogo.co/,1

30595,"2016-03-30 12:32:11",kinogo.co/melodramy/,0

And another df with urls

url

003.ru/[a-zA-Z0-9-_%$#?.:+=|()]+/mobilnyj_telefon_bq_phoenix

003.ru/[a-zA-Z0-9-_%$#?.:+=|()]+/mobilnyj_telefon_fly_

003.ru/sonyxperia

003.ru/[a-zA-Z0-9-_%$#?.:+=|()]+/mobilnye_telefony_smartfony

003.ru/[a-zA-Z0-9-_%$#?.:+=|()]+/mobilnye_telefony_smartfony/brands5D5Bbr_23

1click.ru/sonyxperia

1click.ru/[a-zA-Z0-9-_%$#?.:+=|()]+/chasy-motorola

I use

urls = pd.read_csv('relevant_url1.csv', error_bad_lines=False)

substr = urls.url.values.tolist()

data = pd.read_csv('data_nts2.csv', error_bad_lines=False, chunksize=50000)

result = pd.DataFrame()

for i, df in enumerate(data):

    res = df[df['event_time'].str.contains('|'.join(substr), regex=True)]

but it return me

UserWarning: This pattern has match groups. To actually get the groups, use str.extract.

How can I fix that?

At least one of the regex patterns in urls must use a capturing group.
str.contains only returns True or False for each row in df['event_time'] --
it does not make use of the capturing group. Thus, the UserWarning is alerting you
that the regex uses a capturing group but the match is not used.

If you wish to remove the UserWarning you could find and remove the capturing group from the regex pattern(s). They are not shown in the regex patterns you posted, but they must be there in your actual file. Look for parentheses outside of the character classes.

Alternatively, you could suppress this particular UserWarning by putting

import warnings

warnings.filterwarnings("ignore", 'This pattern has match groups')

before the call to str.contains.

Here is a simple example which demonstrates the problem (and solution):

# import warnings

# warnings.filterwarnings("ignore", 'This pattern has match groups') # uncomment to suppress the UserWarning



import pandas as pd



df = pd.DataFrame({ 'event_time': ['gouda', 'stilton', 'gruyere']})



urls = pd.DataFrame({'url': ['g(.*)']})   # With a capturing group, there is a UserWarning

# urls = pd.DataFrame({'url': ['g.*']})   # Without a capturing group, there is no UserWarning. Uncommenting this line avoids the UserWarning.



substr = urls.url.values.tolist()

df[df['event_time'].str.contains('|'.join(substr), regex=True)]

prints

  script.py:10: UserWarning: This pattern has match groups. To actually get the groups, use str.extract.

  df[df['event_time'].str.contains('|'.join(substr), regex=True)]

Removing the capturing group from the regex pattern:

urls = pd.DataFrame({'url': ['g.*']})   

avoids the UserWarning.

Since regex=True is provided, sublist gets treated as a regex, which in your case contains capturing groups (strings enclosed with parentheses).

You get the warning because if you want to capture something then there is no use of str.contains (which returns boolean depending upon whether the provided pattern is contained within the string or not)

Obviously, you can suppress the warnings but it's better to fix
them.

Either escape the parenthesis blocks or use str.extract if you really want to capture something.