Let $a in mathbb R$ where $y = e^x$ at $(a, e^a)$ and $(a+1, e^{a+1})$. Use a double integral to find the...











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Let $a in mathbb R$ where $y = e^x$ at $(a, e^a)$ and $(a+1, e^{a+1})$. Use a double integral to find the area enclosed



would the area be given by



$$int_{e^{a}}^{e^{a+1}} int_{a+1}^{a} e^{x}dxdy$$?










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    Let $a in mathbb R$ where $y = e^x$ at $(a, e^a)$ and $(a+1, e^{a+1})$. Use a double integral to find the area enclosed



    would the area be given by



    $$int_{e^{a}}^{e^{a+1}} int_{a+1}^{a} e^{x}dxdy$$?










    share|cite|improve this question
























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      Let $a in mathbb R$ where $y = e^x$ at $(a, e^a)$ and $(a+1, e^{a+1})$. Use a double integral to find the area enclosed



      would the area be given by



      $$int_{e^{a}}^{e^{a+1}} int_{a+1}^{a} e^{x}dxdy$$?










      share|cite|improve this question













      Let $a in mathbb R$ where $y = e^x$ at $(a, e^a)$ and $(a+1, e^{a+1})$. Use a double integral to find the area enclosed



      would the area be given by



      $$int_{e^{a}}^{e^{a+1}} int_{a+1}^{a} e^{x}dxdy$$?







      multivariable-calculus






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      asked Nov 29 at 4:34









      Tree Garen

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          The elemental area is $dx dy$. For every value of $x$, $y$ ranges from $0rightarrow e^x$. Finally, $x$ ranges from $arightarrow a+1$. The total area is $int_{a}^{a+1}int_{0}^{e^x} dy dx$.






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            The elemental area is $dx dy$. For every value of $x$, $y$ ranges from $0rightarrow e^x$. Finally, $x$ ranges from $arightarrow a+1$. The total area is $int_{a}^{a+1}int_{0}^{e^x} dy dx$.






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              The elemental area is $dx dy$. For every value of $x$, $y$ ranges from $0rightarrow e^x$. Finally, $x$ ranges from $arightarrow a+1$. The total area is $int_{a}^{a+1}int_{0}^{e^x} dy dx$.






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                up vote
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                The elemental area is $dx dy$. For every value of $x$, $y$ ranges from $0rightarrow e^x$. Finally, $x$ ranges from $arightarrow a+1$. The total area is $int_{a}^{a+1}int_{0}^{e^x} dy dx$.






                share|cite|improve this answer












                The elemental area is $dx dy$. For every value of $x$, $y$ ranges from $0rightarrow e^x$. Finally, $x$ ranges from $arightarrow a+1$. The total area is $int_{a}^{a+1}int_{0}^{e^x} dy dx$.







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                answered Nov 29 at 4:44









                Shubham Johri

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