Let $a in mathbb R$ where $y = e^x$ at $(a, e^a)$ and $(a+1, e^{a+1})$. Use a double integral to find the...
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Let $a in mathbb R$ where $y = e^x$ at $(a, e^a)$ and $(a+1, e^{a+1})$. Use a double integral to find the area enclosed
would the area be given by
$$int_{e^{a}}^{e^{a+1}} int_{a+1}^{a} e^{x}dxdy$$?
multivariable-calculus
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Let $a in mathbb R$ where $y = e^x$ at $(a, e^a)$ and $(a+1, e^{a+1})$. Use a double integral to find the area enclosed
would the area be given by
$$int_{e^{a}}^{e^{a+1}} int_{a+1}^{a} e^{x}dxdy$$?
multivariable-calculus
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up vote
0
down vote
favorite
up vote
0
down vote
favorite
Let $a in mathbb R$ where $y = e^x$ at $(a, e^a)$ and $(a+1, e^{a+1})$. Use a double integral to find the area enclosed
would the area be given by
$$int_{e^{a}}^{e^{a+1}} int_{a+1}^{a} e^{x}dxdy$$?
multivariable-calculus
Let $a in mathbb R$ where $y = e^x$ at $(a, e^a)$ and $(a+1, e^{a+1})$. Use a double integral to find the area enclosed
would the area be given by
$$int_{e^{a}}^{e^{a+1}} int_{a+1}^{a} e^{x}dxdy$$?
multivariable-calculus
multivariable-calculus
asked Nov 29 at 4:34
Tree Garen
36219
36219
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The elemental area is $dx dy$. For every value of $x$, $y$ ranges from $0rightarrow e^x$. Finally, $x$ ranges from $arightarrow a+1$. The total area is $int_{a}^{a+1}int_{0}^{e^x} dy dx$.
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1 Answer
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1 Answer
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up vote
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The elemental area is $dx dy$. For every value of $x$, $y$ ranges from $0rightarrow e^x$. Finally, $x$ ranges from $arightarrow a+1$. The total area is $int_{a}^{a+1}int_{0}^{e^x} dy dx$.
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The elemental area is $dx dy$. For every value of $x$, $y$ ranges from $0rightarrow e^x$. Finally, $x$ ranges from $arightarrow a+1$. The total area is $int_{a}^{a+1}int_{0}^{e^x} dy dx$.
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up vote
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The elemental area is $dx dy$. For every value of $x$, $y$ ranges from $0rightarrow e^x$. Finally, $x$ ranges from $arightarrow a+1$. The total area is $int_{a}^{a+1}int_{0}^{e^x} dy dx$.
The elemental area is $dx dy$. For every value of $x$, $y$ ranges from $0rightarrow e^x$. Finally, $x$ ranges from $arightarrow a+1$. The total area is $int_{a}^{a+1}int_{0}^{e^x} dy dx$.
answered Nov 29 at 4:44
Shubham Johri
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