how to select current rows and some rows before it in pandas dataframe?











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I have the below dataframe with date as index and need to select current row and rows before it



df:



        val   val1
date
2018-01-12 20 30
2018-01-20 10 50
2018-01-27 30 40

for col in df.columns:
subset_data = <code to write to select df with current row and last 139 rowss>
add_n = seasonal_decompose(subset_data[col], model='additive')
...


what code should i write to pass subset_data as current row and last 139 rows.










share|improve this question






















  • What is your expected output?
    – Mayank Porwal
    Nov 22 at 8:42










  • hi Mayank, there is a lot of code written, but i just need the part where I can select the subset of data and this subset changes everytime with loop so more like rows between current row and 139 rows before it
    – user3222101
    Nov 22 at 8:47












  • Assuming your "current row" is given with the variable i, and df is the name of your dataframe, df.iloc[i-139:i,:] is the subset of the whole dataframe you're looking for. This assumes you've made sure that i is at least 139 so that no index out of range occurrs
    – Lukas Thaler
    Nov 22 at 9:28

















up vote
-1
down vote

favorite












I have the below dataframe with date as index and need to select current row and rows before it



df:



        val   val1
date
2018-01-12 20 30
2018-01-20 10 50
2018-01-27 30 40

for col in df.columns:
subset_data = <code to write to select df with current row and last 139 rowss>
add_n = seasonal_decompose(subset_data[col], model='additive')
...


what code should i write to pass subset_data as current row and last 139 rows.










share|improve this question






















  • What is your expected output?
    – Mayank Porwal
    Nov 22 at 8:42










  • hi Mayank, there is a lot of code written, but i just need the part where I can select the subset of data and this subset changes everytime with loop so more like rows between current row and 139 rows before it
    – user3222101
    Nov 22 at 8:47












  • Assuming your "current row" is given with the variable i, and df is the name of your dataframe, df.iloc[i-139:i,:] is the subset of the whole dataframe you're looking for. This assumes you've made sure that i is at least 139 so that no index out of range occurrs
    – Lukas Thaler
    Nov 22 at 9:28















up vote
-1
down vote

favorite









up vote
-1
down vote

favorite











I have the below dataframe with date as index and need to select current row and rows before it



df:



        val   val1
date
2018-01-12 20 30
2018-01-20 10 50
2018-01-27 30 40

for col in df.columns:
subset_data = <code to write to select df with current row and last 139 rowss>
add_n = seasonal_decompose(subset_data[col], model='additive')
...


what code should i write to pass subset_data as current row and last 139 rows.










share|improve this question













I have the below dataframe with date as index and need to select current row and rows before it



df:



        val   val1
date
2018-01-12 20 30
2018-01-20 10 50
2018-01-27 30 40

for col in df.columns:
subset_data = <code to write to select df with current row and last 139 rowss>
add_n = seasonal_decompose(subset_data[col], model='additive')
...


what code should i write to pass subset_data as current row and last 139 rows.







pandas dataframe






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share|improve this question











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asked Nov 22 at 8:35









user3222101

289110




289110












  • What is your expected output?
    – Mayank Porwal
    Nov 22 at 8:42










  • hi Mayank, there is a lot of code written, but i just need the part where I can select the subset of data and this subset changes everytime with loop so more like rows between current row and 139 rows before it
    – user3222101
    Nov 22 at 8:47












  • Assuming your "current row" is given with the variable i, and df is the name of your dataframe, df.iloc[i-139:i,:] is the subset of the whole dataframe you're looking for. This assumes you've made sure that i is at least 139 so that no index out of range occurrs
    – Lukas Thaler
    Nov 22 at 9:28




















  • What is your expected output?
    – Mayank Porwal
    Nov 22 at 8:42










  • hi Mayank, there is a lot of code written, but i just need the part where I can select the subset of data and this subset changes everytime with loop so more like rows between current row and 139 rows before it
    – user3222101
    Nov 22 at 8:47












  • Assuming your "current row" is given with the variable i, and df is the name of your dataframe, df.iloc[i-139:i,:] is the subset of the whole dataframe you're looking for. This assumes you've made sure that i is at least 139 so that no index out of range occurrs
    – Lukas Thaler
    Nov 22 at 9:28


















What is your expected output?
– Mayank Porwal
Nov 22 at 8:42




What is your expected output?
– Mayank Porwal
Nov 22 at 8:42












hi Mayank, there is a lot of code written, but i just need the part where I can select the subset of data and this subset changes everytime with loop so more like rows between current row and 139 rows before it
– user3222101
Nov 22 at 8:47






hi Mayank, there is a lot of code written, but i just need the part where I can select the subset of data and this subset changes everytime with loop so more like rows between current row and 139 rows before it
– user3222101
Nov 22 at 8:47














Assuming your "current row" is given with the variable i, and df is the name of your dataframe, df.iloc[i-139:i,:] is the subset of the whole dataframe you're looking for. This assumes you've made sure that i is at least 139 so that no index out of range occurrs
– Lukas Thaler
Nov 22 at 9:28






Assuming your "current row" is given with the variable i, and df is the name of your dataframe, df.iloc[i-139:i,:] is the subset of the whole dataframe you're looking for. This assumes you've made sure that i is at least 139 so that no index out of range occurrs
– Lukas Thaler
Nov 22 at 9:28



















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