Using globally declared tuple for Python multiprocessing











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I am having some trouble using a tuple globally with the multiprocessing class.



I have a code as produced below:



from multiprocessing import Pool

if __name__ == '__main__':
jj = ()
def f(x):
global jj
jj += (x*x,)

# Section A
#for ii in range(20):
# f(ii)
#print (jj)

# Section B
pool = Pool(processes=4)
pool.map(f, range(20))
pool.join()
print (jj)


If I run section only B, I get the tuple jj as an empty tuple. However, if I run only section A, I get a tuple of length 20.



Why is that so?










share|improve this question
























  • Please run either section A or section B at a time. Comment out the other section not in use. I use tuple because in my original code, I have to store a lot of variables and I read that the instantiation of tuples is much faster than a list. I am not calling these values anywhere in the code.
    – Shihab Khan
    Nov 22 at 8:59















up vote
0
down vote

favorite












I am having some trouble using a tuple globally with the multiprocessing class.



I have a code as produced below:



from multiprocessing import Pool

if __name__ == '__main__':
jj = ()
def f(x):
global jj
jj += (x*x,)

# Section A
#for ii in range(20):
# f(ii)
#print (jj)

# Section B
pool = Pool(processes=4)
pool.map(f, range(20))
pool.join()
print (jj)


If I run section only B, I get the tuple jj as an empty tuple. However, if I run only section A, I get a tuple of length 20.



Why is that so?










share|improve this question
























  • Please run either section A or section B at a time. Comment out the other section not in use. I use tuple because in my original code, I have to store a lot of variables and I read that the instantiation of tuples is much faster than a list. I am not calling these values anywhere in the code.
    – Shihab Khan
    Nov 22 at 8:59













up vote
0
down vote

favorite









up vote
0
down vote

favorite











I am having some trouble using a tuple globally with the multiprocessing class.



I have a code as produced below:



from multiprocessing import Pool

if __name__ == '__main__':
jj = ()
def f(x):
global jj
jj += (x*x,)

# Section A
#for ii in range(20):
# f(ii)
#print (jj)

# Section B
pool = Pool(processes=4)
pool.map(f, range(20))
pool.join()
print (jj)


If I run section only B, I get the tuple jj as an empty tuple. However, if I run only section A, I get a tuple of length 20.



Why is that so?










share|improve this question















I am having some trouble using a tuple globally with the multiprocessing class.



I have a code as produced below:



from multiprocessing import Pool

if __name__ == '__main__':
jj = ()
def f(x):
global jj
jj += (x*x,)

# Section A
#for ii in range(20):
# f(ii)
#print (jj)

# Section B
pool = Pool(processes=4)
pool.map(f, range(20))
pool.join()
print (jj)


If I run section only B, I get the tuple jj as an empty tuple. However, if I run only section A, I get a tuple of length 20.



Why is that so?







python python-3.x python-multiprocessing






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 22 at 9:00

























asked Nov 22 at 8:45









Shihab Khan

227




227












  • Please run either section A or section B at a time. Comment out the other section not in use. I use tuple because in my original code, I have to store a lot of variables and I read that the instantiation of tuples is much faster than a list. I am not calling these values anywhere in the code.
    – Shihab Khan
    Nov 22 at 8:59


















  • Please run either section A or section B at a time. Comment out the other section not in use. I use tuple because in my original code, I have to store a lot of variables and I read that the instantiation of tuples is much faster than a list. I am not calling these values anywhere in the code.
    – Shihab Khan
    Nov 22 at 8:59
















Please run either section A or section B at a time. Comment out the other section not in use. I use tuple because in my original code, I have to store a lot of variables and I read that the instantiation of tuples is much faster than a list. I am not calling these values anywhere in the code.
– Shihab Khan
Nov 22 at 8:59




Please run either section A or section B at a time. Comment out the other section not in use. I use tuple because in my original code, I have to store a lot of variables and I read that the instantiation of tuples is much faster than a list. I am not calling these values anywhere in the code.
– Shihab Khan
Nov 22 at 8:59












1 Answer
1






active

oldest

votes

















up vote
1
down vote



accepted










Ok, as Python multiprocessing global variable updates not returned to parent explains, global state is not shared among processes.



You can share state using, for example, multiprocessing.Queue.



from multiprocessing import Pool, Queue

if __name__ == "__main__":
jj = ()
q = Queue()

def f(x):
global jj
jj += (x * x,)

def f_multi(x):
q.put(x * x)

# Section A
for ii in range(20):
f(ii)
print(jj)

# Section B
pool = Pool(processes=4)
pool.map(f_multi, range(20))
pool.close()

stop = "STOP"
q.put(stop)
items =
for i in iter(q.get, stop):
items.append(i)

print(tuple(items))


Alternatively you can use print(tuple(sorted(items))) to get the values in the same order as Section A will produce. 4 processes are working on the task in Section B and hence the "unordered" result.






share|improve this answer























  • Thanks a lot. Actually @Dušan, the problem which I am facing is that I don't have a single variable I'd have to put in a Queue. I have a function that generates a lot of data. I'm trying to store that data from each iteration so that I can use them later on for validating/checking my results. Is there any efficient way to do that? It seems to be that I'll have to do this for each of the variables.
    – Shihab Khan
    Nov 22 at 9:34






  • 1




    You can put all variables you want to return from your function to a dict and then put that dict to the Queue, e.g. q.put({'data1': [1,2,3], 'data2': (0.5, 0.6)}).
    – Dušan Maďar
    Nov 22 at 9:43












  • This sounds like a good idea. If I can make the function return this dictionary then I don't even have to use a queue.
    – Shihab Khan
    Nov 22 at 9:53











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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes








up vote
1
down vote



accepted










Ok, as Python multiprocessing global variable updates not returned to parent explains, global state is not shared among processes.



You can share state using, for example, multiprocessing.Queue.



from multiprocessing import Pool, Queue

if __name__ == "__main__":
jj = ()
q = Queue()

def f(x):
global jj
jj += (x * x,)

def f_multi(x):
q.put(x * x)

# Section A
for ii in range(20):
f(ii)
print(jj)

# Section B
pool = Pool(processes=4)
pool.map(f_multi, range(20))
pool.close()

stop = "STOP"
q.put(stop)
items =
for i in iter(q.get, stop):
items.append(i)

print(tuple(items))


Alternatively you can use print(tuple(sorted(items))) to get the values in the same order as Section A will produce. 4 processes are working on the task in Section B and hence the "unordered" result.






share|improve this answer























  • Thanks a lot. Actually @Dušan, the problem which I am facing is that I don't have a single variable I'd have to put in a Queue. I have a function that generates a lot of data. I'm trying to store that data from each iteration so that I can use them later on for validating/checking my results. Is there any efficient way to do that? It seems to be that I'll have to do this for each of the variables.
    – Shihab Khan
    Nov 22 at 9:34






  • 1




    You can put all variables you want to return from your function to a dict and then put that dict to the Queue, e.g. q.put({'data1': [1,2,3], 'data2': (0.5, 0.6)}).
    – Dušan Maďar
    Nov 22 at 9:43












  • This sounds like a good idea. If I can make the function return this dictionary then I don't even have to use a queue.
    – Shihab Khan
    Nov 22 at 9:53















up vote
1
down vote



accepted










Ok, as Python multiprocessing global variable updates not returned to parent explains, global state is not shared among processes.



You can share state using, for example, multiprocessing.Queue.



from multiprocessing import Pool, Queue

if __name__ == "__main__":
jj = ()
q = Queue()

def f(x):
global jj
jj += (x * x,)

def f_multi(x):
q.put(x * x)

# Section A
for ii in range(20):
f(ii)
print(jj)

# Section B
pool = Pool(processes=4)
pool.map(f_multi, range(20))
pool.close()

stop = "STOP"
q.put(stop)
items =
for i in iter(q.get, stop):
items.append(i)

print(tuple(items))


Alternatively you can use print(tuple(sorted(items))) to get the values in the same order as Section A will produce. 4 processes are working on the task in Section B and hence the "unordered" result.






share|improve this answer























  • Thanks a lot. Actually @Dušan, the problem which I am facing is that I don't have a single variable I'd have to put in a Queue. I have a function that generates a lot of data. I'm trying to store that data from each iteration so that I can use them later on for validating/checking my results. Is there any efficient way to do that? It seems to be that I'll have to do this for each of the variables.
    – Shihab Khan
    Nov 22 at 9:34






  • 1




    You can put all variables you want to return from your function to a dict and then put that dict to the Queue, e.g. q.put({'data1': [1,2,3], 'data2': (0.5, 0.6)}).
    – Dušan Maďar
    Nov 22 at 9:43












  • This sounds like a good idea. If I can make the function return this dictionary then I don't even have to use a queue.
    – Shihab Khan
    Nov 22 at 9:53













up vote
1
down vote



accepted







up vote
1
down vote



accepted






Ok, as Python multiprocessing global variable updates not returned to parent explains, global state is not shared among processes.



You can share state using, for example, multiprocessing.Queue.



from multiprocessing import Pool, Queue

if __name__ == "__main__":
jj = ()
q = Queue()

def f(x):
global jj
jj += (x * x,)

def f_multi(x):
q.put(x * x)

# Section A
for ii in range(20):
f(ii)
print(jj)

# Section B
pool = Pool(processes=4)
pool.map(f_multi, range(20))
pool.close()

stop = "STOP"
q.put(stop)
items =
for i in iter(q.get, stop):
items.append(i)

print(tuple(items))


Alternatively you can use print(tuple(sorted(items))) to get the values in the same order as Section A will produce. 4 processes are working on the task in Section B and hence the "unordered" result.






share|improve this answer














Ok, as Python multiprocessing global variable updates not returned to parent explains, global state is not shared among processes.



You can share state using, for example, multiprocessing.Queue.



from multiprocessing import Pool, Queue

if __name__ == "__main__":
jj = ()
q = Queue()

def f(x):
global jj
jj += (x * x,)

def f_multi(x):
q.put(x * x)

# Section A
for ii in range(20):
f(ii)
print(jj)

# Section B
pool = Pool(processes=4)
pool.map(f_multi, range(20))
pool.close()

stop = "STOP"
q.put(stop)
items =
for i in iter(q.get, stop):
items.append(i)

print(tuple(items))


Alternatively you can use print(tuple(sorted(items))) to get the values in the same order as Section A will produce. 4 processes are working on the task in Section B and hence the "unordered" result.







share|improve this answer














share|improve this answer



share|improve this answer








edited Nov 22 at 9:32

























answered Nov 22 at 9:26









Dušan Maďar

4,30741935




4,30741935












  • Thanks a lot. Actually @Dušan, the problem which I am facing is that I don't have a single variable I'd have to put in a Queue. I have a function that generates a lot of data. I'm trying to store that data from each iteration so that I can use them later on for validating/checking my results. Is there any efficient way to do that? It seems to be that I'll have to do this for each of the variables.
    – Shihab Khan
    Nov 22 at 9:34






  • 1




    You can put all variables you want to return from your function to a dict and then put that dict to the Queue, e.g. q.put({'data1': [1,2,3], 'data2': (0.5, 0.6)}).
    – Dušan Maďar
    Nov 22 at 9:43












  • This sounds like a good idea. If I can make the function return this dictionary then I don't even have to use a queue.
    – Shihab Khan
    Nov 22 at 9:53


















  • Thanks a lot. Actually @Dušan, the problem which I am facing is that I don't have a single variable I'd have to put in a Queue. I have a function that generates a lot of data. I'm trying to store that data from each iteration so that I can use them later on for validating/checking my results. Is there any efficient way to do that? It seems to be that I'll have to do this for each of the variables.
    – Shihab Khan
    Nov 22 at 9:34






  • 1




    You can put all variables you want to return from your function to a dict and then put that dict to the Queue, e.g. q.put({'data1': [1,2,3], 'data2': (0.5, 0.6)}).
    – Dušan Maďar
    Nov 22 at 9:43












  • This sounds like a good idea. If I can make the function return this dictionary then I don't even have to use a queue.
    – Shihab Khan
    Nov 22 at 9:53
















Thanks a lot. Actually @Dušan, the problem which I am facing is that I don't have a single variable I'd have to put in a Queue. I have a function that generates a lot of data. I'm trying to store that data from each iteration so that I can use them later on for validating/checking my results. Is there any efficient way to do that? It seems to be that I'll have to do this for each of the variables.
– Shihab Khan
Nov 22 at 9:34




Thanks a lot. Actually @Dušan, the problem which I am facing is that I don't have a single variable I'd have to put in a Queue. I have a function that generates a lot of data. I'm trying to store that data from each iteration so that I can use them later on for validating/checking my results. Is there any efficient way to do that? It seems to be that I'll have to do this for each of the variables.
– Shihab Khan
Nov 22 at 9:34




1




1




You can put all variables you want to return from your function to a dict and then put that dict to the Queue, e.g. q.put({'data1': [1,2,3], 'data2': (0.5, 0.6)}).
– Dušan Maďar
Nov 22 at 9:43






You can put all variables you want to return from your function to a dict and then put that dict to the Queue, e.g. q.put({'data1': [1,2,3], 'data2': (0.5, 0.6)}).
– Dušan Maďar
Nov 22 at 9:43














This sounds like a good idea. If I can make the function return this dictionary then I don't even have to use a queue.
– Shihab Khan
Nov 22 at 9:53




This sounds like a good idea. If I can make the function return this dictionary then I don't even have to use a queue.
– Shihab Khan
Nov 22 at 9:53


















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